/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A gymnast is performing a floor ... [FREE SOLUTION] | 91Ó°ÊÓ

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A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 5.00 rev/s while rotating through one-half of a revolution. How much time does this maneuver take?

Short Answer

Expert verified
The maneuver takes 0.125 seconds.

Step by step solution

01

Understand the Problem

The gymnast's initial angular velocity is 3.00 rev/s, final angular velocity is 5.00 rev/s, and she rotates through 0.5 revolution. We need to find the time taken for this maneuver.
02

Convert Angular Velocities to Radians per Second

Since one complete revolution equals \(2\pi\) radians, convert the angular velocities from revolutions per second to radians per second. The initial angular velocity \( \omega_i = 3.00 \times 2\pi = 6\pi \) rad/s, and the final angular velocity \( \omega_f = 5.00 \times 2\pi = 10\pi \) rad/s.
03

Calculate Angular Displacement in Radians

Convert the angular displacement from revolutions to radians: 0.5 revolutions equal \(0.5 \times 2\pi = \pi\) radians.
04

Use the Angular Motion Equation

Utilize the angular motion formula: \[ \theta = \frac{1}{2}(\omega_i + \omega_f)\cdot t \] where \(\theta\) is the angular displacement. Substitute \(\pi = \frac{1}{2}(6\pi + 10\pi)\cdot t\).
05

Solve for Time

Rearrange the equation for \( t \): \[ \pi = 8\pi \cdot t \]. Divide both sides by \(8\pi \), resulting in \( t = \frac{1}{8} \) seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is an essential concept in physics, especially when dealing with rotational motion. It describes how fast an object is rotating or spinning around a central point or axis. Angular velocity is typically measured in radians per second (rad/s), although it can be initially presented in revolutions per second (rev/s).
To convert angular velocity from revolutions per second to radians per second, remember that one complete revolution is equal to \(2\pi\) radians. Thus, if you have an angular velocity in revolutions per second, just multiply by \(2\pi\) to convert it to radians per second. For example, an angular velocity of 3 rev/s would be \(3 \times 2\pi = 6\pi \) rad/s. This conversion is crucial when solving problems involving angular motion, as it ensures that all units are consistent.
Radians
Radians are a unit of angular measure used in many areas of mathematics and physics. Unlike degrees, which are more commonly used in basic geometry, radians provide a more natural measure when working with angular motion and calculus.
In practical terms, one radian is the angle formed when the arc length is equal to the radius of the circle. A full circle equals \(2\pi\) radians, which corresponds to 360 degrees. Thus, to convert an angle from degrees to radians, you can use the conversion factor \( \pi/180\). If something rotates through a certain number of revolutions, you multiply by \(2\pi\) to convert this to radians. This conversion is especially important in physics exercises, where mathematical operations involving sine, cosine, or other trigonometric functions require the angle to be in radians.
Angular Displacement
Angular displacement is the angle through which an object moves on a circular path. It can be thought of as the rotational equivalent of linear displacement. Measured in radians, angular displacement indicates not only the angle covered but also the direction of rotation.
In our exercise example, the gymnast rotates through one-half of a revolution. We convert this into radians using the conversion: \(0.5 \times 2\pi = \pi\) radians. Angular displacement gives us information about the path the object covers, which is crucial for calculations involving angular motion equations. This value is often needed to find the time of a rotational movement, which we solve by knowing both the initial and final angular velocities.
Time Calculation
Calculating the time involved in an angular motion requires an understanding of the relationship between angular displacement, initial and final angular velocities, and time itself.
We use a fundamental equation for angular motion: \( \theta = \frac{1}{2}(\omega_i + \omega_f) \cdot t \), where \( \theta \) is the angular displacement, \( \omega_i \) is the initial angular velocity, and \( \omega_f \) is the final angular velocity. By substituting the known values into the equation, this allows us to solve for \( t \), the time the maneuver takes.
  • Substitute \(\theta = \pi\), \(\omega_i = 6\pi\), and \(\omega_f = 10\pi\).
  • Solve: \(\pi = \frac{1}{2}(6\pi + 10\pi)\cdot t\).
  • This simplifies to \(\pi = 8\pi \cdot t\).
By dividing both sides by \(8\pi\), we find that \( t = \frac{1}{8} \) seconds. This equation not only helps determine the time taken for a maneuver but also highlights the interconnectedness of angular velocity and displacement over time.

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Most popular questions from this chapter

Energy of a Bullet Dissipated by Plywood. As part of a criminal investigation, you need to determine how much of a bullet's energy is dissipated by a 0.500 -inch piece of plywood. You construct a device that consists of three disks that are separated by a distance \(d=0.950 \mathrm{m}\) and rotate on a common axis. The bullet is fired through the first disk (a few inches above its center), which is composed of a light plastic that has a negligible effect on the speed of the bullet. The bullet then passes through the second disk, which is composed of 0.500-inch plywood. Finally, the bullet strikes the third disk, where it becomes embedded. The disks rotate with an angular velocity of \(\omega=92.0 \mathrm{rad} / \mathrm{s} .\) The angular displacement between holes in the first and second disks is \(\Delta \theta_{12}=0.255\) rad, and the angular displacement between the holes in the second and third disks is \(\Delta \theta_{23}=0.273\) rad. If the mass of the bullet is \(15.0 \mathrm{g}\), find \((\mathrm{a})\) the initial speed of the bullet and \((\mathrm{b})\) the energy dissipated by the 0.50-inch plywood.

A wind turbine is initially spinning at a constant angular speed. As the wind's strength gradually increases, the turbine experiences a constant angular acceleration of \(0.140 \mathrm{rad} / \mathrm{s}^{2} .\) After making 2870 revolutions, its angular speed is \(137 \mathrm{rad} / \mathrm{s}\). (a) What is the initial angular velocity of the turbine? (b) How much time elapses while the turbine is speeding up?

A compact disc (CD) contains music on a spiral track. Music is put onto a CD with the assumption that, during playback, the music will be detected at a constant tangential speed at any point. since \(v_{\mathrm{T}}=r \omega, \mathrm{a} \mathrm{CD}\) rotates at a smaller angular speed for music near the outer edge and a larger angular speed for music near the inner part of the disc. For music at the outer edge \((r=0.0568 \mathrm{m}),\) the angular speed is 3.50 rev/s. Find \((\mathrm{a})\) the constant tangential speed at which music is detected and (b) the angular speed (in rev/s) for music at a distance of \(0.0249 \mathrm{m}\) from the center of a CD.

An automatic dryer spins wet clothes at an angular speed of \(5.2 \mathrm{rad} / \mathrm{s} .\) Starting from rest, the dryer reaches its operating speed with an average angular acceleration of \(4.0 \mathrm{rad} / \mathrm{s}^{2} .\) How long does it take the dryer to come up to speed?

The sun appears to move across the sky, because the earth spins on its axis. To a person standing on the earth, the sun subtends an angle of \(\theta_{\operatorname{sun}}=\) \(9.28 \times 10^{-3}\) rad (see conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?

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