/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 An automatic dryer spins wet clo... [FREE SOLUTION] | 91Ó°ÊÓ

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An automatic dryer spins wet clothes at an angular speed of \(5.2 \mathrm{rad} / \mathrm{s} .\) Starting from rest, the dryer reaches its operating speed with an average angular acceleration of \(4.0 \mathrm{rad} / \mathrm{s}^{2} .\) How long does it take the dryer to come up to speed?

Short Answer

Expert verified
The dryer takes 1.3 seconds to reach its operating speed.

Step by step solution

01

Identify the known values

We are given the following values: initial angular speed \( \omega_0 = 0 \, \mathrm{rad/s} \) (since it starts from rest), final angular speed \( \omega = 5.2 \, \mathrm{rad/s} \), and average angular acceleration \( \alpha = 4.0 \, \mathrm{rad/s^2} \). We need to find the time \( t \) it takes to reach the operating speed.
02

Use the angular kinematics equation

We use the kinematics equation for angular motion: \( \omega = \omega_0 + \alpha t \). In this equation, \( \omega \) is the final angular speed, \( \omega_0 \) is the initial angular speed, \( \alpha \) is the angular acceleration, and \( t \) is the time elapsed.
03

Substitute the known values into the equation

Substitute \( \omega = 5.2 \), \( \omega_0 = 0 \), and \( \alpha = 4.0 \) into the equation: \[ 5.2 = 0 + 4.0t \]
04

Solve for time \( t \)

We need to isolate \( t \) by dividing both sides of the equation by \( 4.0 \): \[ t = \frac{5.2}{4.0} = 1.3 \]
05

Conclusion

The time it takes for the dryer to come up to its operating speed is \( 1.3 \) seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Angular Speed
Angular speed, often symbolized by \( \omega \), is a measure of how quickly an object rotates around a fixed point or axis. It tells us how many radians (a unit for measuring angles) an object sweeps through per second. Let's break it down in simpler terms:
  • Imagine the Earth spinning around its axis. The speed at which it completes one rotation is akin to the angular speed.
  • If you think of a clock's second hand, its angular speed would tell you how fast it moves through the numbers on the clock face.
In the context of our exercise, the automatic dryer reaches an angular speed of \(5.2\, \mathrm{rad/s}\). This means that every second, the drum of the dryer spins such that it covers \(5.2\) radians. This unit conveys how fast the dryer is spinning once it's fully operational. Understanding angular speed is crucial for predicting and analyzing rotational motion across different applications.
When engaging with problems involving angular speed, it's essential to differentiate it from linear speed. Linear speed refers to how fast an object moves along a straight line, while angular speed concerns rotational movements.
Grasping Angular Acceleration
Angular acceleration, denoted by \( \alpha \), measures how quickly an object's angular speed changes over time. It's the rotational equivalent of linear acceleration, which you might be more familiar with. Here's a simpler look:
  • Angular acceleration tells us how fast an object "speeds up" or "slows down" in its rotational motion.
  • Imagine a potter's wheel gradually speeding up from a stop until it reaches its full spinning speed. The rate of this increase in spinning speed is the angular acceleration.
In our dryer example, the angular acceleration is given as \(4.0\, \mathrm{rad/s^2}\). This means that for every second the dryer accelerates, its angular speed increases by \(4.0\, \mathrm{rad/s}\). So, over time, the dryer speeds up until it reaches its operating speed. Understanding angular acceleration helps us determine how quickly rotational devices reach their desired speed. This concept also assists in designing mechanisms that need controlled rotational movement.
Kinematics Equation in Angular Motion
The kinematics equation for angular motion is a powerful tool that relates various aspects of rotational movement. The equation used in the exercise is \( \omega = \omega_0 + \alpha t \). Let's break it down to see what it means:
  • \( \omega \) is the final angular speed, which is how fast the object is spinning after accelerating.
  • \( \omega_0 \) is the initial angular speed. It's the speed at which the object starts, and in our exercise, the dryer starts from rest, so \( \omega_0 = 0\).
  • \( \alpha \) represents the angular acceleration, the rate at which the angular speed increases over time.
  • \( t \) is the time it takes for the object to adjust to its new angular speed.
Inserting these known values into our equation helps us calculate the time needed for a dryer to come up to full speed. This equation is fundamental in problems involving rotational motion, as it offers a straightforward way to find an unknown when you have other rotational quantities. It's a cornerstone of understanding motion that involves spinning or circular paths, widely applicable in mechanics and engineering fields.

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Most popular questions from this chapter

The angular speed of the rotor in a centrifuge increases from 420 to \(1420 \mathrm{rad} / \mathrm{s}\) in a time of \(5.00 \mathrm{s}\). (a) Obtain the angle through which the rotor turns. (b) What is the magnitude of the angular acceleration?

An automobile tire has a radius of 0.330 m, and its center moves forward with a linear speed of \(v=15.0 \mathrm{m} / \mathrm{s} .\) (a) Determine the angular speed of the wheel. (b) Relative to the axle, what is the tangential speed of a point located \(0.175 \mathrm{m}\) from the axle?

The sun appears to move across the sky, because the earth spins on its axis. To a person standing on the earth, the sun subtends an angle of \(\theta_{\operatorname{sun}}=\) \(9.28 \times 10^{-3}\) rad (see conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?

A rectangular plate is rotating with a constant angular speed about an axis that passes perpendicularly through one corner, as the drawing shows. The centripetal acceleration measured at corner \(A\) is \(n\) times as great as that measured at corner \(B\). What is the ratio \(L_{1} / L_{2}\) of the lengths of the sides of the rectangle when \(n=2.00 ?\)

A ball of radius 0.200 m rolls with a constant linear speed of \(3.60 \mathrm{m} / \mathrm{s}\) along a horizontal table. The ball rolls off the edge and falls a vertical distance of \(2.10 \mathrm{m}\) before hitting the floor. What is the angular displacement of the ball while the ball is in the air?

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