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Light that is polarized along the vertical direction is incident on a sheet of polarizing material. Only \(94 \%\) of the intensity of the light passes through the sheet and strikes a second sheet of polarizing material. No light passes through the second sheet. What angle does the transmission axis of the second sheet make with the vertical?

Short Answer

Expert verified
The transmission axis makes approximately \( 90^\circ \) with the vertical.

Step by step solution

01

Understand Polarization

Light that is polarized vertically has its electric field oscillations in the vertical plane. When it encounters a polarizing material, only the component of the light that is aligned with the transmission axis of the material is allowed to pass through. The intensity of transmitted light after passing through a polarizer is given by Malus's Law, which states that \( I = I_0 \cos^2(\theta) \), where \( I_0 \) is the initial intensity, \( I \) is the transmitted intensity, and \( \theta \) is the angle between the light's initial polarization direction and the transmission axis of the polarizer.
02

Apply Intensity Through First Polarizer

The problem states that 94% of the intensity passes through the first polarizer. According to Malus's Law: \( I = 0.94 I_0 = I_0 \cos^2(\theta_1) \), where \( \theta_1 \) is the angle made with the vertical axis for the first polarizer. Solving gives \( \cos(\theta_1) \approx \sqrt{0.94} \). Since there is some transmission, \( \theta_1 \) is not 90 or 0 degrees.
03

Analyze Second Polarizer Effect

No light passes through the second polarizer. According to Malus's Law, \( I = I' \cos^2(\theta_2) \) must be zero, where \( \theta_2 \) is the angle between the light that exits the first polarizer and the transmission axis of the second polarizer. For the intensity to be zero, \( \cos(\theta_2) = 0 \), meaning \( \theta_2 = 90^\circ \).
04

Determine the Transmission Axis of Second Polarizer

Since the light passing the first polarizer is not entirely vertical anymore, it is aligned according to the first polarizer's transmission axis. For no light to pass through the second polarizer, its transmission axis must be perpendicular to the light from the first polarizer. Thus, the transmission axis of the second polarizer must be \( 90^\circ \) to the direction of light from the first polarizer, but since no light passes vertically, the angle with the vertical is effectively \( 90^\circ + \theta_1 \), where \( \theta_1 \) is found based on \( \cos(\theta_1) \approx \sqrt{0.94} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus's Law
Malus's Law is key for understanding the behavior of polarized light as it passes through a polarizing filter. This law describes how the intensity of light is affected by the angle between its polarization direction and the transmission axis of the polarizer it encounters. According to Malus's Law, the transmitted light intensity, \( I \), can be calculated using the formula: \[ I = I_0 \cos^2(\theta) \] where \( I_0 \) is the initial light intensity, and \( \theta \) is the angle between the light's original polarization direction and the polarizer's transmission axis.

In simple terms, Malus's Law tells us that the closer the light's direction is to being aligned with the polarizer's transmission axis, the more light will pass through. The cosine squared term shows how the intensity diminishes as the angle increases. If the angle is 90 degrees, no light passes through as \( \cos^2(90^\circ) = 0 \).
Transmission Axis
The transmission axis of a polarizer is a critical factor in determining which light is allowed through it. It is the direction along which the polarizer allows the electric field component of light to pass. The transmission axis can be thought of as a gate that selectively permits light waves aligned with it.

When light, polarized in a certain direction, hits a polarizer, only the component of light that is parallel to the transmission axis is allowed through. For instance, if vertically polarized light meets a vertical transmission axis, it passes almost entirely. Conversely, if the transmission axis is perpendicular to the light's polarization, no light will get through.

Understanding the orientation of the transmission axis relative to incoming light is critical in applications like polarizing sunglasses and optical sensors.
Light Intensity
Light intensity refers to the amount of energy that a light wave carries per unit area and is perceived as brightness. When dealing with polarizers, recognizing how intensity changes with orientation and transmission axis is important.

As light interacts with a polarizer, its intensity is determined by the aforementioned Malus's Law. For example, if 94% of the initial light's intensity passes through a polarizing sheet, it indicates that the light's polarization direction is closely aligned with the sheet's transmission axis. Mathematically, this would mean solving \( 0.94 = \cos^2(\theta) \) to find the approximate angle \( \theta \).

To put it in perspective:
  • High alignment (small \( \theta \)) yields high intensity.
  • Low alignment (large \( \theta \), nearing 90 degrees) results in low intensity.
Understanding light intensity and its relationship with polarization is useful in optimizing various applications, such as improving the clarity of images viewed through screens and maximizing energy capture in photovoltaic cells.

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Most popular questions from this chapter

A laptop computer communicates with a router wirelessly, by means of radio signals. The router is connected by cable directly to the Internet. The laptop is \(8.1 \mathrm{m}\) from the router, and is downloading text and images from the Internet at an average rate of 260 Mbps, or 260 megabits per second. (A bit, or binary digit, is the smallest unit of digital information.) On average, how many bits are downloaded to the laptop in the time it takes the wireless signal to travel from the router to the laptop?

The drawing shows light incident on a polarizer whose transmission axis is parallel to the \(z\) axis. The polarizer is rotated clockwise through an angle \(\alpha .\) The average intensity of the incident light is \(7.0 \mathrm{W} / \mathrm{m}^{2}\). Determine the average intensity of the transmitted light for each of the six cases shown in the table.

A future space station in orbit about the earth is being powered by an electromagnetic beam from the earth. The beam has a cross-sectional area of \(135 \mathrm{m}^{2}\) and transmits an average power of \(1.20 \times 10^{4} \mathrm{W} .\) What are the rms values of the (a) electric and (b) magnetic fields?

A beam of polarized light with an average intensity of \(15 \mathrm{W} / \mathrm{m}^{2}\) is sent through a polarizer. The transmission axis makes an angle of \(25^{\circ}\) with respect to the direction of polarization. Determine the rms value of the electric field of the transmitted beam.

The average intensity of light emerging from a polarizing sheet is \(0.764 \mathrm{W} / \mathrm{m}^{2},\) and the average intensity of the horizontally polarized light incident on the sheet is \(0.883 \mathrm{W} / \mathrm{m}^{2}\). Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

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