Chapter 24: Problem 53
A future space station in orbit about the earth is being powered by an electromagnetic beam from the earth. The beam has a cross-sectional area of \(135 \mathrm{m}^{2}\) and transmits an average power of \(1.20 \times 10^{4} \mathrm{W} .\) What are the rms values of the (a) electric and (b) magnetic fields?
Short Answer
Step by step solution
Understand the Given Data
Calculate the Intensity of the Beam
Relate Intensity to Electric Field
Solve for Electric Field
Relate Electric Field to Magnetic Field
Solve for Magnetic Field
Concluding Step: Review and Validate
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electric Field
In this exercise, we calculate the root mean square (rms) value of the electric field for an electromagnetic beam. The rms value is a kind of average that helps in understanding the effective strength of the oscillating field. It is derived from the intensity of the wave, using the formula:
\[E_{\text{rms}} = \sqrt{\frac{2I}{c \varepsilon_0}}\]
Here,
- \(I\) is the intensity of the wave, given as the power per unit area.
- \(c\) is the speed of light, approximately \(3 \times 10^8 \text{m/s}\).
- \(\varepsilon_0\) is the permittivity of free space, valued at \(8.85 \times 10^{-12} \text{C}^2/\text{N} \cdot \text{m}^2\).
Magnetic Field
In electromagnetic waves, the rms value of the magnetic field is directly related to the rms value of the electric field through the speed of light \(c\). This relationship is expressed by:
\[B_{\text{rms}} = \frac{E_{\text{rms}}}{c}\]
This formula shows us:
- How the magnetic field's magnitude is derived from the electric field.
- It is inverse-proportional to the speed of light, emphasizing the intertwined nature of light speed and electromagnetic interactions.
- Allows us to understand the balance and proportionality between the two fields.
Intensity of Electromagnetic Waves
In this exercise, the intensity \(I\) of our electromagnetic beam was calculated using:
\[I = \frac{P}{A}\]
Where:
- \(P\) is the power of the beam, representing the total energy delivered per second.
- \(A\) is the cross-sectional area of the beam, indicating how widely the energy is spread.