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The average intensity of light emerging from a polarizing sheet is \(0.764 \mathrm{W} / \mathrm{m}^{2},\) and the average intensity of the horizontally polarized light incident on the sheet is \(0.883 \mathrm{W} / \mathrm{m}^{2}\). Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Short Answer

Expert verified
The transmission axis makes an angle of about 21.6 degrees with the horizontal.

Step by step solution

01

Understand the Problem

We are given two intensities. The first one, 0.764 W/m², is the average intensity of light after passing through a polarizer. The second one, 0.883 W/m², is the average intensity of the horizontally polarized light incident on the sheet. We need to find the angle of the transmission axis of the polarizer with the horizontal.
02

Recall Malus's Law Formula

Malus's Law provides a formula to calculate the intensity of light passing through a polarizer. The formula is: \[ I = I_0 \cos^2(\theta) \]where \( I \) is the intensity after the polarizer (0.764 W/m²), \( I_0 \) is the initial intensity of the incident light (0.883 W/m²), and \( \theta \) is the angle between the light's initial polarization direction and the polarizer's axis.
03

Solve for Cosine Squared

We will now solve Malus's Law for \( \cos^2(\theta) \):\[ \cos^2(\theta) = \frac{I}{I_0} = \frac{0.764}{0.883} \]
04

Compute Cosine Squared Value

Calculate \( \cos^2(\theta) \):\[ \cos^2(\theta) = \frac{0.764}{0.883} \approx 0.865 \ \cos(\theta) \approx \sqrt{0.865} \approx 0.930 \]
05

Determine the Angle \(\theta\)

Now we calculate \(\theta\) using the inverse cosine function:\[ \theta = \cos^{-1}(0.930) \] Calculate \(\theta\) to find the angle in degrees.
06

Calculate Angle

The angle \(\theta\) can be computed using a scientific calculator:\[ \theta \approx \cos^{-1}(0.930) \approx 21.6^\circ \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Malus's Law
Malus's Law is a principle used to predict how the intensity of light changes as it passes through a polarizing filter. This law states that the intensity of light after passing through a polarizer can be calculated using the formula:
  • \[ I = I_0 \cos^2(\theta) \]
Here, \( I \) is the intensity of the light after it emerges from the polarizer, \( I_0 \) is the intensity of the incident light, and \( \theta \) is the angle between the polarizer's transmission axis and the initial polarization direction of the light.
This formula shows that light intensity decreases as the angle \( \theta \) moves away from 0 degrees. When the angle is 90 degrees, theoretically, no light can pass through the polarizer, leading to an intensity of zero.
Malus's Law is particularly useful in various applications, such as in sunglasses, cameras, and other optical devices, where controlling the glare or brightness of light is necessary.
Intensity of Light
The intensity of light is a measure of the amount of energy that light waves carry over a specific area. It is represented in units such as watts per square meter (W/m²). When dealing with the polarization of light, intensity is an crucial factor in determining how much light passes through a particular medium or surface.
In polarizing situations like the one in the exercise, the initial intensity \( I_0 \) indicates how much light initially strikes the polarizing filter. After passing through the filter, the intensity is reduced, and this is represented by \( I \).
Understanding intensity is essential for predicting and analyzing the behavior of light in various settings, especially in designing systems that rely on precise light levels, such as photography and astronomy.
Angle of Transmission Axis
The angle of the transmission axis in a polarizing filter is critical for determining which portion of the incident light is allowed to pass through. This angle, denoted as \( \theta \), is the angle between the transmission axis of the polarizer and the light's original polarization direction.
  • When \( \theta \) is 0 degrees, maximum light passes through because the alignment between the light and the polarizer is perfect.
  • When \( \theta \) is 90 degrees, the polarizer blocks all light because the alignment is perpendicular.
In practice, the precise control of this angle allows for the modulation of light intensity, which can have significant implications in fields such as optical engineering and photography. By applying Malus's Law and experimentation, one can measure this angle accurately, helping in the design of systems that require specific light properties.

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Most popular questions from this chapter

Suppose that a police car is moving to the right at \(27 \mathrm{m} / \mathrm{s},\) while a speeder is coming up from behind at a speed of \(39 \mathrm{m} / \mathrm{s}\), both speeds being with respect to the ground. Assume that the electromagnetic wave emitted by the police car's radar gun has a frequency of \(8.0 \times 10^{9} \mathrm{Hz}\). Find the difference between the frequency of the wave that returns to the police car after reflecting from the speeder's car and the original frequency emitted by the police car.

On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about \(1.0 \times 10^{3} \mathrm{W} / \mathrm{m}^{2} .\) What is the electromagnetic energy contained in \(5.5 \mathrm{m}^{3}\) of space just above the earth's surface?

Light that is polarized along the vertical direction is incident on a sheet of polarizing material. Only \(94 \%\) of the intensity of the light passes through the sheet and strikes a second sheet of polarizing material. No light passes through the second sheet. What angle does the transmission axis of the second sheet make with the vertical?

A politician holds a press conference that is televised live. The sound picked up by the microphone of a TV news network is broadcast via electromagnetic waves and heard by a television viewer. This vicwer is seated \(2.3 \mathrm{m}\) from his television set. A reporter at the press conference is located \(4.1 \mathrm{m}\) from the politician, and the sound of the words travels directly from the celebrity's mouth, through the air, and into the reporter's ears. The reporter hears the words exactly at the same instant that the television viewer hears them. Using a value of \(343 \mathrm{m} / \mathrm{s}\) for the speed of sound, determine the maximum distance between the television set and the politician. Ignore the small distance between the politician and the microphone. In addition, assume that the only delay between what the microphone picks up and the sound being emitted by the television set is that due to the travel time of the electromagnetic waves used by the network.

The magnitude of the electric field of an electromagnetic wave increases from 315 to \(945 \mathrm{N} / \mathrm{C}\). (a) Determine the wave intensities for the two values of the electric field. (b) What is the magnitude of the magnetic field associated with each electric field? (c) Determine the wave intensity for each value of the magnetic field.

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