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A hydrometer is a device used to measure the density of a liquid. It is a cylindrical tube weighted at one end, so that it floats with the heavier end downward. The tube is contained inside a large "medicine dropper," into which the liquid is drawn using the squeeze bulb (see the drawing). For use with your car, marks are put on the tube so that the level at which it floats indicates whether the liquid is battery acid (more dense) or antifreeze (less dense). The hydrometer has a weight of \(W=5.88 \times 10^{-2} \mathrm{N}\) and a cross-sectional area of \(A=7.85 \times 10^{-5} \mathrm{m}^{2}\) How far from the bottom of the tube should the mark be put that denotes (a) battery acid \(\left(\rho=1280 \mathrm{kg} / \mathrm{m}^{3}\right)\) and (b) antifreeze \(\left(\rho=1073 \mathrm{kg} / \mathrm{m}^{3}\right) ?\)

Short Answer

Expert verified
Mark at 5.88 cm for battery acid and 7.02 cm for antifreeze.

Step by step solution

01

Understanding Archimedes' Principle

To solve this problem, we use Archimedes' principle which states that the buoyant force on the immersed part of the hydrometer is equal to the weight of the liquid displaced. This principle is given by \( F_b = \rho V g \), where \( \rho \) is the density of the liquid, \( V \) is the volume displaced, and \( g \) is the acceleration due to gravity.
02

Calculating Displaced Volume

Given that the hydrometer is in equilibrium, the buoyant force equals the weight of the hydrometer. Therefore, \( \rho V g = W \), where \( W = 5.88 \times 10^{-2} \mathrm{N} \). To find the volume \( V \), rearrange the equation to \( V = \frac{W}{\rho g} \).
03

Find the Submerged Length for Battery Acid

For battery acid with \( \rho = 1280 \mathrm{kg/m^3} \), substitute \( \rho \) into the volume equation: \( V = \frac{5.88 \times 10^{-2}}{1280 \times 9.81} \). Calculate this to find \( V \). Then use \( V = A h \) where \( h \) is the height, to find \( h = \frac{V}{A} \).
04

Find the Submerged Length for Antifreeze

For antifreeze with \( \rho = 1073 \mathrm{kg/m^3} \), use the same steps as with battery acid: \( V = \frac{5.88 \times 10^{-2}}{1073 \times 9.81} \). Compute \( V \) and then find \( h = \frac{V}{A} \) using the cross-sectional area \( A = 7.85 \times 10^{-5} \mathrm{m}^{2} \).
05

Calculate Final Values

Compute the exact values for \( h \) for both battery acid and antifreeze using the equations derived. This will give the distances from the bottom of the tube at which the marks should be placed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
When objects are submerged in a fluid, they experience a force known as the buoyant force. This force acts upwards, opposing the force of gravity, and is responsible for making objects float. According to Archimedes' Principle, the buoyant force on an object is equal to the weight of the fluid that the object displaces. This can be expressed with the formula:
  • \( F_b = \rho V g \)
Here, \( F_b \) is the buoyant force, \( \rho \) represents the density of the fluid, \( V \) is the volume of fluid displaced, and \( g \) is the acceleration due to gravity. This principle helps us understand why objects of different densities float or sink.
When the buoyant force equals the weight of the object, it floats. If it's less, the object sinks.
Density Measurement
Density measures how much mass is contained in a given volume. It is expressed as mass per unit volume (e.g., kg/m³). High-density liquids, like battery acid, have more mass packed in a given volume compared to low-density liquids, like antifreeze. Understanding density is key to many applications, such as determining whether a liquid will support a floating object or not.
In the context of a hydrometer, the tool measures the density of liquids to identify substances. By knowing the density, one can predict the liquid’s behavior and its potential uses. For instance, with a hydrometer, you could identify a denser liquid as battery acid by observing how much of the hydrometer sinks.
Hydrometer
A hydrometer is a simple yet effective tool used for measuring liquid density. Typically, it consists of a weighted tube that floats upright in a liquid. The level at which the hydrometer floats depends on the liquid's density. When placed in denser liquids, less of the hydrometer is submerged, as it doesn't need to displace much liquid to equal its weight.
To determine the density using a hydrometer:
  • Place it in the liquid.
  • Observe the depth to which it sinks.
For a vehicle, hydrometers can indicate the type of liquid, such as differentiating between battery acid and antifreeze, ensuring safe vehicle operation.
Volume Displacement
Volume displacement is a concept related to the amount of fluid that moves when an object is submerged. The displaced volume is directly proportional to how much of the object is underwater. In the formula \( V = A h \), \( V \) represents the displaced volume, \( A \) is the cross-sectional area, and \( h \) is the submerged height.
This concept is critical for calculating how deep a hydrometer will sink in a given liquid. By knowing the displaced volume, you can determine the point where the buoyant force balances the weight of the hydrometer. For instance, in denser liquids, a smaller volume is needed to match the hydrometer’s weight, resulting in a shallower subsurface depth.

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Most popular questions from this chapter

A water bed for sale has dimensions of \(1.83 \mathrm{m} \times 2.13 \mathrm{m} \times 0.229 \mathrm{m}\) The floor of the bedroom will tolerate an additional weight of no more than \(6660 \mathrm{N}\). Find the weight of the water in the bed and determine whether the bed should be purchased.

Multiple-Concept Example 8 presents an approach to problems of this kind. The hydraulic oil in a car lift has a density of \(8.30 \times 10^{2} \mathrm{kg} / \mathrm{m}^{3}\). The weight of the input piston is negligible. The radii of the input piston and output plunger are \(7.70 \times 10^{-3} \mathrm{m}\) and \(0.125 \mathrm{m},\) respectively. What input force \(F\) is needed to support the \(24500-\mathrm{N}\) combined weight of a car and the output plunger, when (a) the bottom surfaces of the piston and plunger are at the same level, and (b) the bottom surface of the output plunger is \(1.30 \mathrm{m}\) above that of the input piston?

A liquid is flowing through a horizontal pipe whose radius is \(0.0200 \mathrm{m}\). The pipe bends straight upward through a height of \(10.0 \mathrm{m}\) and joins another horizontal pipe whose radius is \(0.0400 \mathrm{m} .\) What volume flow rate will keep the pressures in the two horizontal pipes the same?

A blood transfusion is being set up in an emergency room for an accident victim. Blood has a density of \(1060 \mathrm{kg} / \mathrm{m}^{3}\) and a viscosity of \(4.0 \times 10^{-3} \mathrm{Pa} \cdot \mathrm{s} .\) The needle being used has a length of \(3.0 \mathrm{cm}\) and an inner radius of \(0.25 \mathrm{mm} .\) The doctor wishes to use a volume flow rate through the needle of \(4.5 \times 10^{-8} \mathrm{m}^{3} / \mathrm{s} .\) What is the distance \(h\) above the victim's arm where the level of the blood in the transfusion bottle should be located? As an approximation, assume that the level of the blood in the transfusion bottle and the point where the needle enters the vein in the arm have the same pressure of one atmosphere. (In reality, the pressure in the vein is slightly above atmospheric pressure.)

Water is circulating through a closed system of pipes in a two-floor apartment. On the first floor, the water has a gauge pressure of \(3.4 \times 10^{5} \mathrm{Pa}\) and a speed of \(2.1 \mathrm{m} / \mathrm{s}\). However, on the second floor, which is \(4.0 \mathrm{m}\) higher, the speed of the water is \(3.7 \mathrm{m} / \mathrm{s}\). The speeds are different because the pipe diameters are different. What is the gauge pressure of the water on the second floor?

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