/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 A blood transfusion is being set... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A blood transfusion is being set up in an emergency room for an accident victim. Blood has a density of \(1060 \mathrm{kg} / \mathrm{m}^{3}\) and a viscosity of \(4.0 \times 10^{-3} \mathrm{Pa} \cdot \mathrm{s} .\) The needle being used has a length of \(3.0 \mathrm{cm}\) and an inner radius of \(0.25 \mathrm{mm} .\) The doctor wishes to use a volume flow rate through the needle of \(4.5 \times 10^{-8} \mathrm{m}^{3} / \mathrm{s} .\) What is the distance \(h\) above the victim's arm where the level of the blood in the transfusion bottle should be located? As an approximation, assume that the level of the blood in the transfusion bottle and the point where the needle enters the vein in the arm have the same pressure of one atmosphere. (In reality, the pressure in the vein is slightly above atmospheric pressure.)

Short Answer

Expert verified
The height needed is approximately 0.34 meters above the arm.

Step by step solution

01

Identify Required Formula

To determine the height, we use the Hagen-Poiseuille equation, which relates volume flow rate \( Q \), viscosity \( \eta \), radius \( r \), length \( L \), and pressure difference \( \Delta P \): \[ Q = \frac{{\pi r^4 \Delta P}}{{8 \eta L}} \] In this case, \( \Delta P = \rho gh \), where \( \rho \) is the density of blood and \( h \) is the height, as the pressure at both ends is equal to atmospheric pressure.
02

Rearrange for Height

Rearrange the formula to solve for height \( h \): \[ \Delta P = 8 \eta L \frac{Q}{\pi r^4} \] Substitute \( \Delta P = \rho gh \) to find: \[ h = \frac{8 \eta L Q}{\pi r^4 \rho g} \]
03

Substitute Known Values

Insert the given values into the equation:- viscosity \( \eta = 4.0 \times 10^{-3} \, \text{Pa} \cdot \text{s} \)- length \( L = 0.03 \, \text{m} \)- volume flow rate \( Q = 4.5 \times 10^{-8} \, \text{m}^3/\text{s} \)- radius \( r = 0.00025 \, \text{m} \) (converted to meters)- density \( \rho = 1060 \, \text{kg/m}^3 \)- gravitational acceleration \( g = 9.81 \, \text{m/s}^2 \)The formula becomes:\[ h = \frac{8 \times 4.0 \times 10^{-3} \times 0.03 \times 4.5 \times 10^{-8}}{\pi \times (0.00025)^4 \times 1060 \times 9.81} \]
04

Calculate the Result

Compute the above expression: First calculate \( r^4 \), then the entire denominator and numerator, and finally, the height \( h \):\[ r^4 = (0.00025)^4 = 3.90625 \times 10^{-14} \, \text{m}^4 \]Compute the numerator:\[ 8 \times 4.0 \times 10^{-3} \times 0.03 \times 4.5 \times 10^{-8} = 4.32 \times 10^{-11} \, \text{Pa} \cdot \text{m}^3 \]Compute the denominator:\[ \pi \times 3.90625 \times 10^{-14} \times 1060 \times 9.81 = 1.27827 \times 10^{-10} \]Finally, calculate \( h \):\[ h = \frac{4.32 \times 10^{-11}}{1.27827 \times 10^{-10}} = 0.3379 \, \text{m} \approx 0.34 \, \text{m} \]
05

Conclusion

The transfusion bottle should be placed approximately 0.34 meters above the victim's arm to achieve the desired flow rate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hagen-Poiseuille equation
Fluid dynamics in biological systems often involve the motion of liquids through narrow tubes or vessels. Here, the Hagen-Poiseuille equation is vital. This mathematical expression helps us describe how fluids flow through a pipe. The equation states that the volume flow rate (\(Q\)) through a cylindrical pipe is proportionally affected by the fourth power of the radius (\(r^4\)), the pressure difference across the pipe (\(\Delta P\)), and the pipe's length (\(L\)), and is inversely affected by the viscosity of the fluid (\(\eta\)). The formula is given by:\[Q = \frac{{\pi r^4 \Delta P}}{{8 \eta L}}.\]This equation is incredibly useful to analyze systems like blood flow in the circulatory system, where the vessels behave similarly to cylindrical pipes.
Viscosity
Viscosity is a physical property of fluids that describes their resistance to flow. People's everyday perception of viscosity can be related to how thick or sticky a fluid feels. For instance, honey has a much higher viscosity compared to water.
In biological contexts, such as blood flow, viscosity plays a critical role in determining how easily or how hard the blood moves through veins and arteries.
The higher the viscosity, the more resistance the fluid encounters, leading to slower movement. Blood viscosity is measurable and often presented in units known as Pascal-seconds (Pa·s). In the case of blood transfusions, understanding the viscosity is essential to ensure the fluid moves at a desired and regulated rate, ensuring patient safety and treatment efficacy.
Volume Flow Rate
The volume flow rate is a measurement of the amount of fluid passing through a specific section of pipe or vessel in a unit of time. It is usually denoted as \(Q\), with units of cubic meters per second (m³/s).
Volume flow rate plays a crucial role in medical applications, such as administering blood transfusions. Here, knowing the volume flow rate helps ensure that fluids are delivered to the patient at the correct speed, preventing complications.
In this exercise, with the given volume flow rate of \(4.5 \times 10^{-8} \, \text{m}^3/\text{s},\) medical professionals can adjust the height of the transfusion bottle to control this flow, employing the Hagen-Poiseuille equation as a guide.
Density of Fluids
Density is another essential property of fluids, indicating mass per unit volume, typically in kilograms per cubic meter (kg/m³). Understanding the density of a fluid is important as it affects how the fluid behaves under various forces, such as gravity.
In biological scenarios, blood has a particular density that affects how it circulates throughout the body. For example, knowing that the density of blood is \(1060 \, \text{kg/m}^3\) helps in calculations involving pressure differences, as used in the Heights-Poiseuille equation.
Accurate density values are important in calculating the necessary height for fluid delivery systems, like an IV drip, to ensure the fluid transfers at the correct pressure and speed to the patient.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Spring Gun. A hydraulic press is used to compress a spring that will then be used to project a \(25.0-\mathrm{kg}\) steel ball. The system is similar, but smaller in scale, to the car jack illustrated in Figure \(11.14 .\) In this case, the smaller cylinder has a diameter of \(d_{1}=0.75 \mathrm{cm}\) and has a manually operated plunger. The larger cylinder has a diameter of \(d_{2}=10.0 \mathrm{cm},\) and its piston compresses the spring. The idea is that the gun operator pulls a lever that pushes the plunger on the small cylinder, which transmits a pressure to the larger piston that, in turn, exerts a force on the spring and compresses it. Once the spring is compressed, the steel ball is loaded and the spring is released, ejecting the ball. (a) If a force of \(950 \mathrm{N}\) is exerted on the primary (smaller) piston to compress the spring \(1.25 \mathrm{m}\) from its equilibrium (uncompressed) position, what is the spring constant \(k\) of the spring? (b) What is the velocity of the steel ball just after it is ejected? (c) Neglecting air resistance, what is the maximum range of this "spring gun"?

A room has a volume of \(120 \mathrm{m}^{3} .\) An air-conditioning system is to replace the air in this room every twenty minutes, using ducts that have a square cross section. Assuming that air can be treated as an incompressible fluid, find the length of a side of the square if the air speed within the ducts is (a) \(3.0 \mathrm{m} / \mathrm{s}\) and (b) \(5.0 \mathrm{m} / \mathrm{s}\)

A full can of black cherry soda has a mass of \(0.416 \mathrm{kg}\). It contains \(3.54 \times 10^{-4} \mathrm{m}^{3}\) of liquid. Assuming that the soda has the same density as water, find the volume of aluminum used to make the can.

One of the concrete pillars that support a house is \(2.2 \mathrm{m}\) tall and has a radius of \(0.50 \mathrm{m}\). The density of concrete is about \(2.2 \times 10^{3} \mathrm{kg} / \mathrm{m}^{3} .\) Find the weight of this pillar in pounds \((1 \mathrm{N}=0.2248 \mathrm{lb})\)

A \(0.10-\mathrm{m} \times 0.20-\mathrm{m} \times 0.30-\mathrm{m}\) block is suspended from a wire and is completely under water. What buoyant force acts on the block?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.