/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 A \(0.10-\mathrm{m} \times 0.20-... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(0.10-\mathrm{m} \times 0.20-\mathrm{m} \times 0.30-\mathrm{m}\) block is suspended from a wire and is completely under water. What buoyant force acts on the block?

Short Answer

Expert verified
The buoyant force acting on the block is 58.86 N.

Step by step solution

01

Determine the Volume of the Block

First, calculate the volume of the block. Use the formula for the volume of a rectangular prism:\[ V = ext{length} imes ext{width} imes ext{height} \]Substitute the given dimensions into the formula:\[ V = 0.10 \, \text{m} \times 0.20 \, \text{m} \times 0.30 \, \text{m} = 0.006 \, \text{m}^3 \]
02

Recall the Buoyant Force Formula

The buoyant force can be found using Archimedes' principle, which states:\[ F_b = \rho \times V \times g \]where:- \( F_b \) is the buoyant force,- \( \rho \) is the density of the fluid (water, in this case, with a typical density of \( 1000 \, \text{kg/m}^3 \)),- \( V \) is the volume of the displaced fluid (equal to the volume of the block when fully submerged),- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)).
03

Substitute and Calculate the Buoyant Force

Substitute the known values into the buoyant force formula:\[ F_b = 1000 \, \text{kg/m}^3 \times 0.006 \, \text{m}^3 \times 9.81 \, \text{m/s}^2 \]Calculate the result:\[ F_b = 58.86 \, \text{N} \]
04

Conclusion

The calculated buoyant force that acts on the block is approximately \( 58.86 \, \text{N} \). This is the upward force exerted by the fluid on the submerged block.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' principle
Archimedes' principle is a fundamental concept in physics that explains why objects float or sink in a fluid. According to this principle, any object immersed in a fluid experiences an upward force, known as the buoyant force. This force is equal to the weight of the fluid that the object displaces. In simpler terms, if you submerge an object in water, the water pushes back with a force equal to the water's weight displaced by the object. This provides a clear explanation of why huge ships float and why balloons rise in the air. When calculating the buoyant force, it's important to remember that it depends solely on the volume of the object submerged and the density of the fluid, but not on the weight of the object itself. This principle is universally applicable, which means it doesn’t matter if you're dealing with a small block or a massive ship; the principle remains the same.
Density of water
When discussing buoyant forces, the density of the fluid the object is submerged in plays a crucial role. The density of a substance is defined as its mass per unit volume. Water, in most common conditions, has a density of approximately \(1000 \, \text{kg/m}^3\). This property is important because the buoyant force is calculated using this density value. The density of water is a constant that greatly simplifies calculations related to buoyant forces in freshwater environments. It's important to note that the density can change with temperature and pressure, but in general homework problems like this, it is safe to use the typical value of \(1000 \, \text{kg/m}^3\). This density is a key factor in determining how much upward force a submerged object will experience.
Volume calculation
Calculating the volume of an object is a crucial step when applying Archimedes' principle. The volume of the object submerged in the fluid determines the amount of fluid displaced, which directly relates to the buoyant force applied. For simple shapes like a rectangular block, the volume can be easily found by multiplying its length, width, and height. For the given exercise, the block's dimensions are \(0.10\, \text{m}\), \(0.20\, \text{m}\), and \(0.30\, \text{m}\), which results in a volume of \(0.006\, \text{m}^3\). Always ensure you're using the correct units; volume should be calculated in cubic meters within the metric system. Understanding how to calculate the volume not only facilitates determining the buoyant force but also assists in various other physics and engineering calculations. Having a precise volume calculation is crucial to ensure accurate results in practice.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prairie dogs are burrowing rodents. They do not suffocate in their burrows, because the effect of air speed on pressure creates sufficient air circulation. The animals maintain a difference in the shapes of two entrances to the burrow, and because of this difference, the air \(\left(\rho=1.29 \mathrm{kg} / \mathrm{m}^{3}\right)\) blows past the openings at different speeds, as the drawing indicates. Assuming that the openings are at the same vertical level, find the difference in air pressure between the openings and indicate which way the air circulates.

(a) The mass and the radius of the sun are, respectively, \(1.99 \times\) \(10^{30} \mathrm{kg}\) and \(6.96 \times 10^{8} \mathrm{m} .\) What is its density? (b) If a solid object is made from a material that has the same density as the sun, would it sink or float in water? Why? (c) Would a solid object sink or float in water if it were made from a material whose density was the same as that of the planet Saturn (mass \(=5.7 \times 10^{26} \mathrm{kg},\) radius \(\left.=6.0 \times 10^{7} \mathrm{m}\right) ?\) Provide a reason for your answer.

In the human body, blood vessels can dilate, or increase their radii, in response to various stimuli, so that the volume flow rate of the blood increases. Assume that the pressure at either end of a blood vessel, the length of the vessel, and the viscosity of the blood remain the same, and determine the factor \(R_{\text {dilated }} / R_{\text {normal }}\) by which the radius of a vessel must change in order to double the volume flow rate of the blood through the vessel.

Two hoses are connected to the same outlet using a Y-connector, as the drawing shows. The hoses \(A\) and \(B\) have the same length, but hose \(B\) has the larger radius. Each is open to the atmosphere at the end where the water exits. Water flows through both hoses as a viscous fluid, and Poiseuille's \(\operatorname{law}\left[Q=\pi R^{4}\left(P_{2}-P_{1}\right) /(8 \eta L)\right]\) applies to each. In this law, \(P_{2}\) is the pressure upstream, \(P_{1}\) is the pressure downstream, and \(Q\) is the volume flow rate. The ratio of the radius of hose \(\mathrm{B}\) to the radius of hose \(\mathrm{A}\) is \(R_{\mathrm{B}} / R_{\mathrm{A}}=1.50 .\) Find the ratio of the speed of the water in hose \(B\) to the speed in hose \(A\).

A paperweight, when weighed in air, has a weight of \(W=6.9 \mathrm{N}\). When completely immersed in water, however, it has a weight of \(W_{\text {in water }}=\) \(4.3 \mathrm{N} .\) Find the volume of the paperweight.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.