/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 At an instant when a soccer ball... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

At an instant when a soccer ball is in contact with the foot of a player kicking it, the horizontal or \(x\) component of the ball's acceleration is \(810 \mathrm{m} / \mathrm{s}^{2}\) and the vertical or \(y\) component of its acceleration is \(1100 \mathrm{m} / \mathrm{s}^{2} .\) The ball's mass is \(0.43 \mathrm{kg} .\) What is the magnitude of the net force acting on the soccer ball at this instant?

Short Answer

Expert verified
The net force is approximately 587 N.

Step by step solution

01

Identify Given Values

The problem provides the following values:- Horizontal component of acceleration \(a_x = 810 \, \text{m/s}^2\)- Vertical component of acceleration \(a_y = 1100 \, \text{m/s}^2\)- Mass of the ball \(m = 0.43 \, \text{kg}\).
02

Calculate the Net Acceleration

The net acceleration \(a_{net}\) can be obtained by using the Pythagorean theorem for the horizontal and vertical components:\[a_{net} = \sqrt{a_x^2 + a_y^2}\]Substitute the given values:\[a_{net} = \sqrt{810^2 + 1100^2} \, \text{m/s}^2\]\[a_{net} = \sqrt{656100 + 1210000} \, \text{m/s}^2\]\[a_{net} = \sqrt{1866100} \, \text{m/s}^2\]\[a_{net} \approx 1365 \text{ m/s}^2\]
03

Apply Newton's Second Law to Find Net Force

According to Newton's Second Law, the net force \(F_{net}\) is the product of mass \(m\) and net acceleration \(a_{net}\):\[F_{net} = m \cdot a_{net}\]Substitute the mass and the calculated net acceleration:\[F_{net} = 0.43 \, \text{kg} \times 1365 \, \text{m/s}^2\]\[F_{net} \approx 587 \text{ N}\]
04

Conclusion: State the Magnitude of the Net Force

Thus, the magnitude of the net force acting on the soccer ball is approximately \(587\) Newtons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental principle in physics. It describes how the motion of an object is affected by forces. Here is the simplest form of this law:
- When a net force acts on an object, it produces an acceleration that is inversely proportional to the object's mass.In mathematical terms, the law is stated as:\[ F = m \cdot a \]where:- \( F \) is the net force acting on an object.- \( m \) is the mass of the object.- \( a \) is the acceleration of the object.This law is important because it links the force applied to an object and the resulting acceleration. This relationship can be used to calculate the net force, provided we know the mass and acceleration. For example, if we know how fast the soccer ball accelerates and its mass, we can find the force exerted by the player's foot.
Net Acceleration
Net acceleration refers to the total acceleration of an object when multiple forces are acting upon it. In the case of a soccer ball, both horizontal and vertical accelerations are present. To find the net acceleration, it is necessary to consider both these components:
- Horizontal acceleration: \( a_x = 810 \, \text{m/s}^2 \)- Vertical acceleration: \( a_y = 1100 \, \text{m/s}^2 \)The net acceleration \( a_{net} \) can be thought of as a combination of these components. In physics, net acceleration combines using vector principles, helping us see the overall effect of forces acting in different directions on the soccer ball's motion.
Vector Components
Vector components are useful in breaking down a vector into perpendicular directions. Whenever a force is applied, it can often be split into different directions that simplify understanding and calculations.
For example, the acceleration of the soccer ball has two components:- Horizontal component along the \( x \)-axis \( (a_x) \)- Vertical component along the \( y \)-axis \( (a_y) \)By understanding acceleration in terms of these components, calculations become easier. We can separately evaluate how the force affects motion in each direction and then combine the results to get a complete picture of the object's motion. This decomposition is crucial when addressing forces and motion in a two-dimensional plane.
Pythagorean Theorem
The Pythagorean Theorem is a mathematical principle used to determine the relationship between the lengths of the sides of a right triangle. In vector analysis, this theorem helps us calculate the magnitude of a vector resultant from its orthogonal components.
For net acceleration, we used the following formula derived from the Pythagorean Theorem:\[ a_{net} = \sqrt{a_x^2 + a_y^2} \]The equation calculates the net acceleration as analogous to calculating the hypotenuse of a right triangle. Here:- \( a_x \) and \( a_y \) are the known vector components.- \( a_{net} \) is the vector sum, or the 'hypotenuse'.This theorem is vital because it allows us to compute the total effect of accelerations in different directions, giving a clear measure of the net acceleration felt by the soccer ball.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The three objects in the drawing are connected by strings that pass over massless and friction-free pulleys. The objects move, and the coefficient of kinetic friction between the middle object and the surface of the table is \(0.100 .\) (a) What is the acceleration of the three objects? (b) Find the tension in each of the two strings.

A space probe has two engines. Each generates the same amount of force when fired, and the directions of these forces can be independently adjusted. When the engines are fired simultaneously and each applies its force in the same direction, the probe, starting from rest, takes \(28 \mathrm{s}\) to travel a certain distance. How long does it take to travel the same distance, again starting from rest, if the engines are fired simultaneously and the forces that they apply to the probe are perpendicular?

A Mercedes-Benz \(300 \mathrm{SL}\) ( \(m=1700 \mathrm{kg}\) ) is parked on a road that rises \(15^{\circ}\) above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?

The speed of a bobsled is increasing because it has an acceleration of \(2.4 \mathrm{m} / \mathrm{s}^{2} .\) At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total \(450 \mathrm{N}\). The combined mass of the bobsled and its riders is \(270 \mathrm{kg}\). (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

Refer to Multiple-Concept Example 10 for help in solving problems like this one. An ice skater is gliding horizontally across the ice with an initial velocity of \(+6.3 \mathrm{m} / \mathrm{s}\). The coefficient of kinetic friction between the ice and the skate blades is \(0.081,\) and air resistance is negligible. How much time elapses before her velocity is reduced to \(+2.8 \mathrm{m} / \mathrm{s} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.