/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 Refer to Multiple-Concept Exampl... [FREE SOLUTION] | 91Ó°ÊÓ

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Refer to Multiple-Concept Example 10 for help in solving problems like this one. An ice skater is gliding horizontally across the ice with an initial velocity of \(+6.3 \mathrm{m} / \mathrm{s}\). The coefficient of kinetic friction between the ice and the skate blades is \(0.081,\) and air resistance is negligible. How much time elapses before her velocity is reduced to \(+2.8 \mathrm{m} / \mathrm{s} ?\)

Short Answer

Expert verified
The time elapsed is 4.39 seconds.

Step by step solution

01

Identify the Given Information

From the problem statement, we have:- Initial velocity, \( u = +6.3 \mathrm{\ m/s} \).- Final velocity, \( v = +2.8 \mathrm{\ m/s} \).- Coefficient of kinetic friction, \( \mu_k = 0.081 \).- Acceleration due to gravity, \( g = 9.8 \mathrm{\ m/s^2} \).
02

Calculate the Force of Friction

The force of friction \( F_f \) can be calculated using the formula:\[ F_f = \mu_k \cdot m \cdot g \]Where:- \( \mu_k = 0.081 \) is the coefficient of friction.- \( g = 9.8 \mathrm{\ m/s^2} \) is the gravitational acceleration.Since mass \( m \) cancels out when finding acceleration, we do not need its specific value here.
03

Determine the Acceleration Due to Friction

The friction force \( F_f \) causes a deceleration \( a \), which can be expressed as:\[ a = \mu_k \cdot g = 0.081 \times 9.8 \mathrm{\ m/s^2} \]Calculating gives:\[ a = 0.7938 \mathrm{\ m/s^2} \]Since it's a deceleration, it acts in the opposite direction to motion.
04

Use the Kinematic Equation to Find Time

Use the kinematic equation relating initial velocity, final velocity, acceleration, and time:\[ v = u + a \cdot t \]Substitute the known values:\[ +2.8 = +6.3 - 0.7938 \cdot t \]Solve for \( t \):\[ t = \frac{(6.3 - 2.8)}{0.7938} = 4.39 \mathrm{\ s} \]
05

Verify the Calculation

Reconfirm each calculation step, ensuring correct arithmetic operations to solidify that \( t = 4.39 \mathrm{\ s} \) is accurate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ice Skater
When you think of an ice skater gliding gracefully across the ice, it's easy to overlook the physics working behind the scenes. An ice skater relies on having a low coefficient of kinetic friction, which makes the skating experience smooth and efficient.
The momentum required for gliding comes from the initial push, giving the skater a measurable initial velocity. In this context, the skater begins with an initial velocity of 6.3 meters per second.
This speed determines how far and how fast the skater can travel before the forces of friction and air resistance eventually bring them to a stop or slow them down. The smooth surface of the ice, combined with the sharp blades of the skates, minimizes friction to enhance the skater's movement. However, as time passes, friction applies a force opposite to the direction of motion, slowing the skater down over time.
Kinematic Equations
Kinematic equations are mathematical formulas used to solve problems involving motion, such as the motion of an ice skater across a rink. These equations relate the following variables: initial velocity, final velocity, acceleration, time, and displacement.
In our exercise, we're especially interested in the equation: \[ v = u + a \cdot t \]
where
  • \(u\) is the initial velocity
  • \(v\) is the final velocity
  • \(a\) is the acceleration (or deceleration, if it's negative)
  • \(t\) is the time
This equation helps us determine how long it takes for the skater to slow down from an initial velocity of 6.3 m/s to a final velocity of 2.8 m/s. By rearranging and solving this equation, we can calculate the time elapsed, crucial for understanding how various forces interact.
Deceleration
Deceleration is the process of slowing down, and it occurs naturally in our ice skating example due to friction between the skate blades and the ice. It's essentially negative acceleration and acts opposite to the direction of motion.
The calculated deceleration due to friction is determined using the equation \[ a = \mu_k \cdot g \] where
  • \(\mu_k\) is the coefficient of kinetic friction (0.081 in this problem)
  • \(g\) is the acceleration due to gravity (9.8 m/s²)
When this deceleration is computed as 0.7938 m/s², it means that every second, the speed of the skater reduces by this amount. Understanding deceleration is crucial for predicting how soon an object in motion will come to a stop or reach a slower velocity when exposed to friction.
Coefficient of Kinetic Friction
The coefficient of kinetic friction, denoted as \( \mu_k \), quantifies the frictional resistance encountered during motion between two surfaces, in this scenario, between the ice and the skate blades. This constant is unique for every pair of materials and largely influences how easily one surface can move across another.
With a coefficient of 0.081 for the ice-skater interaction, it's quite a low value, reflecting the slippery nature of ice, which allows for smooth and extended gliding. Even so, this seemingly small number is significant.
It is used to calculate the frictional force that acts to slow down the skater: \[ F_f = \mu_k \cdot m \cdot g \] Though the mass \( m \) cancels out in this particular scenario when calculating deceleration, the coefficient still plays a pivotal role in determining the rate of deceleration, thereby impacting motion dynamics substantially.

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Most popular questions from this chapter

Mars has a mass of \(6.46 \times 10^{23} \mathrm{kg}\) and a radius of \(3.39 \times 10^{6} \mathrm{m}\). (a) What is the acceleration due to gravity on Mars? (b) How much would a \(65-\mathrm{kg}\) person weigh on this planet?

An electron is a subatomic particle \(\left(m=9.11 \times 10^{-31} \mathrm{kg}\right)\) that is subject to electric forces. An electron moving in the \(+x\) direction accelerates from an initial velocity of \(+5.40 \times 10^{5} \mathrm{m} / \mathrm{s}\) to a final velocity of \(+2.10 \times 10^{6} \mathrm{m} / \mathrm{s}\) while traveling a distance of \(0.038 \mathrm{m} .\) The electron's acceleration is due to two electric forces parallel to the \(x\) axis: \(\overrightarrow{\mathbf{F}}_{1}=+7.50 \times 10^{-17} \mathrm{N},\) and \(\overrightarrow{\mathbf{F}}_{2},\) which points in the \(-x\) direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force \(\overrightarrow{\mathbf{F}}_{2}\).

The speed of a bobsled is increasing because it has an acceleration of \(2.4 \mathrm{m} / \mathrm{s}^{2} .\) At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total \(450 \mathrm{N}\). The combined mass of the bobsled and its riders is \(270 \mathrm{kg}\). (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

Three forces act on a moving object. One force has a magnitude of \(80.0 \mathrm{N}\) and is directed due north. Another has a magnitude of \(60.0 \mathrm{N}\) and is directed due west. What must be the magnitude and direction of the third force, such that the object continues to move with a constant velocity?

A rocket blasts off from rest and attains a speed of \(45 \mathrm{m} / \mathrm{s}\) in \(15 \mathrm{s}\). An astronaut has a mass of 57 kg. What is the astronaut's apparent weight during takeoff?

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