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The three objects in the drawing are connected by strings that pass over massless and friction-free pulleys. The objects move, and the coefficient of kinetic friction between the middle object and the surface of the table is \(0.100 .\) (a) What is the acceleration of the three objects? (b) Find the tension in each of the two strings.

Short Answer

Expert verified
The acceleration is \( a = \frac{(m_1 - m_3 - \mu_k m_2) g}{m_1 + m_2 + m_3} \). Tensions are \( T_1 = m_1 g - m_1 a \) and \( T_2 = m_3 g + m_3 a \).

Step by step solution

01

Define the System

Let's assign masses to each object. Assume the mass of the first object is \( m_1 \), the middle object \( m_2 \), and the third object \( m_3 \). Also, let the tension in the string connected to \( m_1 \) be \( T_1 \) and the tension in the string connected to \( m_3 \) be \( T_2 \). We know the coefficient of kinetic friction between \( m_2 \) and the table is \( \mu_k = 0.100 \). Our goal is to find the acceleration \( a \) of the system and the tensions \( T_1 \) and \( T_2 \) in the strings.
02

Write the Equation for each Mass

1. For \( m_1 \), the forces acting are gravity and tension. Thus, \( m_1 g - T_1 = m_1 a \). 2. For \( m_2 \), the forces in the horizontal direction are tension minus friction from the table surface. So, \( T_1 - T_2 - f_k = m_2 a \), where \( f_k = \mu_k m_2 g \).3. For \( m_3 \), the forces are tension and gravity. Hence, \( T_2 - m_3 g = m_3 a \).
03

Solve for Acceleration

Add the equations from Step 2 to eliminate \( T_1 \) and \( T_2 \). This gives:\[ m_1 g - m_3 g - \mu_k m_2 g = (m_1 + m_2 + m_3) a \]Simplify to solve for \( a \):\[ a = \frac{(m_1 - m_3 - \mu_k m_2) g}{m_1 + m_2 + m_3} \]
04

Solve for Tension T1

Substitute \( a \) from Step 3 into the equation for \( m_1 \):\[ T_1 = m_1 g - m_1 a \]
05

Solve for Tension T2

Substitute \( a \) from Step 3 into the equation for \( m_3 \):\[ T_2 = m_3 g + m_3 a \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
When objects slide against each other, kinetic friction is the force that opposes the sliding motion. It's a crucial concept in physics because it affects how easily things move. In this exercise, the middle object on the table experiences kinetic friction.
Kinetic friction depends on two main factors:
  • The nature of the surfaces in contact, represented by the coefficient of kinetic friction \( \mu_k \).
  • The normal force, which is usually the object's weight if it's lying flat on a surface.
So, for an object with mass \( m_2 \) on a flat table, the force of kinetic friction \( f_k \) can be calculated using:\[ f_k = \mu_k \cdot m_2 \cdot g \]where \( g \) is the acceleration due to gravity. Here, \( \mu_k \) is given as 0.100, which tells us that the table surface does provide some resistance to the object's sliding.
Understanding kinetic friction and calculating it correctly are key steps in determining how this friction affects the motion and acceleration of connected objects.
Tension
Tension refers to the pulling force transmitted through a string, cable, or similar object when forces act from opposite ends. When analyzing systems with ropes or strings, like those in this physics problem, tension becomes an essential variable to consider.
In our exercise, two tensions, \( T_1 \) and \( T_2 \), occur in the strings connecting the masses:
  • \( T_1 \) is the tension between the pulley and the mass \( m_1 \).
  • \( T_2 \) is the tension between the pulley and the mass \( m_3 \).
For each mass, the tension is part of the net force equation. For example, the mass \( m_1 \) experiences a downward gravitational force and an upward tension force, expressed as \( m_1 g - T_1 = m_1 a \).
By analyzing these forces, you can solve for tensions \( T_1 \) and \( T_2 \), which are necessary to understand how the forces balance within the system, eventually helping us find the system's acceleration.
Acceleration
Acceleration is the rate at which an object changes its velocity. In this problem, all three connected masses accelerate together due to the forces acting on them. Calculating this shared acceleration is crucial to understand the motion dynamics of the system.
Using Newton’s Second Law, which tells us that the net force is equal to mass times acceleration \( F = ma \), we can determine the system's overall acceleration. By summing up the forces on each object, as shown in the step-by-step solution, the equation becomes:\[ m_1 g - m_3 g - \mu_k m_2 g = (m_1 + m_2 + m_3) a \]When we solve for \( a \), we find:\[ a = \frac{(m_1 - m_3 - \mu_k m_2) g}{m_1 + m_2 + m_3} \]This formula shows how the gravitational forces on \( m_1 \) and \( m_3 \), combined with the frictional resistance against \( m_2 \), influence the acceleration of the system.
Understanding acceleration in connected systems like this one helps us predict motion and solve real-world physics problems more effectively.

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