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Mars has a mass of \(6.46 \times 10^{23} \mathrm{kg}\) and a radius of \(3.39 \times 10^{6} \mathrm{m}\). (a) What is the acceleration due to gravity on Mars? (b) How much would a \(65-\mathrm{kg}\) person weigh on this planet?

Short Answer

Expert verified
(a) The acceleration due to gravity on Mars is approximately 3.71 m/s². (b) A 65 kg person weighs about 241.15 N on Mars.

Step by step solution

01

Understand the Formula for Gravitational Acceleration

The acceleration due to gravity on a planet can be calculated using \[ g = \frac{G \cdot M}{r^2} \]where \( G \) is the gravitational constant \( 6.674 \times 10^{-11} \mathrm{Nm}^2/\mathrm{kg}^2 \), \( M \) is the mass of the planet, and \( r \) is the radius of the planet.
02

Insert Mars' Mass and Radius into the Formula

Substitute Mars' mass \( M = 6.46 \times 10^{23} \text{ kg} \) and Mars' radius \( r = 3.39 \times 10^6 \text{ m} \) into the formula:\[ g = \frac{6.674 \times 10^{-11} \times 6.46 \times 10^{23}}{(3.39 \times 10^6)^2} \]
03

Calculate the Acceleration Due to Gravity on Mars

Calculate the acceleration:\[ g = \frac{6.674 \times 10^{-11} \times 6.46 \times 10^{23}}{1.1481 \times 10^{13}} \approx 3.71 \mathrm{m/s}^2 \]Thus, the acceleration due to gravity on Mars is approximately \( 3.71 \mathrm{m/s}^2 \).
04

Understand Weight Calculation on Mars

Weight can be determined using the equation \( F = m \cdot g \), where \( m \) is the mass of the object and \( g \) is the acceleration due to gravity on Mars.
05

Calculate the Weight of a 65 kg Person on Mars

Substituting the known values in the equation:\[ F = 65 \times 3.71 = 241.15 \text{ N} \]Therefore, a \(65\text{ kg}\) person would weigh approximately \(241.15 \text{ N}\) on Mars.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Acceleration
Gravitational acceleration refers to the rate at which an object speeds up as it falls under the influence of gravity. On Mars, this can be calculated using the formula:
  • \( g = \frac{G \cdot M}{r^2} \)
In this equation, \( g \) represents the gravitational acceleration on Mars, \( G \) stands for the gravitational constant, \( M \) is the mass of Mars, and \( r \) is the radius of Mars. By substituting the known values of Mars' mass and radius into the formula, we can determine that the gravitational acceleration on Mars is approximately \( 3.71 \text{ m/s}^2 \). This value indicates how much speed an object will gain each second when falling freely near Mars' surface.
Remember, this acceleration is due to the planet's mass and radius, hence why it's different from Earth's gravity.
Mass of Mars
The mass of Mars plays a crucial role in determining the strength of its gravitational field. Mars has a mass of \( 6.46 \times 10^{23} \text{ kg} \), which is a fundamental factor in the gravitational force exerted by the planet. This mass, combined with the gravitational constant, allows us to calculate things like gravitational acceleration and weight for objects on Mars.
In comparison to Earth, Mars is significantly lighter. This difference in mass is one of the reasons why the gravitational force on Mars is much weaker than on Earth. This is important to consider for various applications, such as space travel and the potential for human settlement on Mars, as the lower gravity affects everything from how we walk to how we build structures.
Weight on Mars
Weight on Mars is influenced by Mars' gravitational acceleration. An object's weight is the force it exerts due to gravity, and this can be calculated by multiplying the object’s mass by the gravitational acceleration on the surface. For instance, the weight \( F \) of a person weighing \( 65 \text{ kg} \) on Mars can be calculated as:
  • \( F = m \cdot g \)
Substituting the values, the calculation becomes:
  • \( F = 65 \times 3.71 = 241.15 \text{ N} \)
This shows that a person weighing \( 65 \text{ kg} \) on Earth would weigh only \( 241.15 \text{ N} \) on Mars. The reduced weight is directly a result of Mars' weaker gravitational pull when compared to Earth. Understanding weight on Mars helps us in planning activities and technologies for Mars exploration and possibly future habitation.
Gravitational Constant
The gravitational constant, denoted as \( G \), is crucial in calculations involving gravitational force. It has a constant value of \( 6.674 \times 10^{-11} \mathrm{Nm}^2/\mathrm{kg}^2 \) and is fundamental in the formula for gravitational acceleration:
  • \( g = \frac{G \cdot M}{r^2} \)
\( G \) is a universal constant, meaning it applies to all calculations worldwide and beyond. It represents the intensity of the gravitational force exerted by a cubic meter of mass at a unit distance. Having a precise value for \( G \) allows scientists to model the behavior of celestial bodies with great accuracy.
This constant helps us understand the relationship between mass, distance, and gravitational force across planets, including Mars, and plays an essential role in the fields of physics, astronomy, and engineering.

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Most popular questions from this chapter

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