/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Baseball player A bunts the ball... [FREE SOLUTION] | 91Ó°ÊÓ

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Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of \(1.9 \mathrm{m} / \mathrm{s}\) parallel to the ground. Upon contact with the bat the ball is \(1.2 \mathrm{m}\) above the ground. Player \(\mathrm{B}\) wishes to duplicate this bunt, in so far as he also wants to give the ball a velocity parallel to the ground and have his ball travel the same horizontal distance as player A's ball does. However, player B hits the ball when it is \(1.5 \mathrm{m}\) above the ground. What is the magnitude of the initial velocity that player B's ball must be given?

Short Answer

Expert verified
Player B's ball must be given an initial velocity of approximately 1.70 m/s.

Step by step solution

01

Understand the Problem

We need to determine the initial velocity for player B's ball, given that it is hit from a height of 1.5 m, so that it travels the same horizontal distance as player A's ball, which was hit from a height of 1.2 m with an initial horizontal velocity of 1.9 m/s.
02

Calculate Time of Flight for Player A

Use the formula for the time of flight in free fall: \[ t_A = \sqrt{\frac{2h_A}{g}} \]where \( h_A = 1.2 \mathrm{m} \) is the initial height and \( g = 9.8 \mathrm{m/s}^2 \) is the acceleration due to gravity. Calculate: \[ t_A = \sqrt{\frac{2 \times 1.2}{9.8}} \approx 0.495 \text{ seconds} \]
03

Calculate Horizontal Distance for Player A

Using player A's initial velocity and the time of flight just computed, calculate the horizontal distance traveled:\[ d_A = v_A \times t_A \]where \( v_A = 1.9 \mathrm{m/s} \). Calculate:\[ d_A = 1.9 \times 0.495 \approx 0.9405 \text{ meters} \]
04

Calculate Time of Flight for Player B

Use the formula for the time of flight again, but this time with player B's initial height:\[ t_B = \sqrt{\frac{2h_B}{g}} \]where \( h_B = 1.5 \mathrm{m} \). Calculate:\[ t_B = \sqrt{\frac{2 \times 1.5}{9.8}} \approx 0.553 \text{ seconds} \]
05

Determine Initial Velocity for Player B

To find the required initial velocity for player B, use the horizontal distance calculated for player A. Since player B must also achieve this distance:\[ d_B = v_B \times t_B = d_A \]\[ v_B = \frac{d_A}{t_B} \]Substitute the known values:\[ v_B = \frac{0.9405}{0.553} \approx 1.70 \mathrm{m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinematics
Kinematics is a branch of physics that studies the motion of objects without considering the forces that cause this motion. In the context of projectile motion, it involves understanding how an object moves under the influence of gravity alone.
The basic kinematic equations describe the position, velocity, and acceleration of an object over time, allowing us to predict its future motion.
  • Velocity: Refers to the speed of an object in a specific direction.
  • Acceleration: In the case of projectiles, this is often due to gravity, acting downwards at approximately 9.8 m/s².
In practical cases like our baseball, you use kinematics to calculate how long it will stay in the air (the time of flight) and how far it will travel horizontally. It’s essential to separate the motion into vertical and horizontal components to simplify the analysis.
Vertical motion is influenced by gravity, which affects the time the ball is in the air. The horizontal motion is influenced by the initial velocity provided to the ball. Together, these help us use kinematics to solve problems like determining the initial velocity needed for different circumstances of a bunt, as explored in our example.
Initial Velocity Calculation
Calculating the initial velocity in projectile motion involves breaking down the problem into horizontal and vertical components. For a ball hit parallel to the ground, the situation is simplified because the initial vertical velocity is zero. This means that the only initial velocity to consider is the horizontal component.
Using our example, the time of flight is calculated using the formula for free fall: \[ t = \sqrt{\frac{2h}{g}} \] where \( h \) is the height from which the ball is hit and \( g \) is the acceleration due to gravity.
This time helps us relate the initial horizontal velocity to the horizontal distance traveled, using:\[ d = v \times t \]Here, the known horizontal distance can be used to calculate the unknown initial velocity for player B.
In summary, knowing the height and horizontal distance allows you to determine this initial velocity, as demonstrated by the example with player B needing to match player A's horizontal distance.
Horizontal Motion
Horizontal motion in projectile motion is typically not influenced by gravity, assuming no other forces like air resistance. This means that the horizontal velocity stays constant during the flight of the projectile.
To assess this motion, you track how far the object travels horizontally while it is in the air. This distance is simply the product of the constant horizontal velocity and the time of flight: \[ d = v \times t \]
  • Time of Flight: Dictated by vertical motion and free fall calculations.
  • Horizontal Distance: The product of horizontal velocity and time of flight.
In our scenario, this allowed us to conclude that player B can achieve the same horizontal distance as player A by adjusting his initial velocity. Since player B hits the ball from a higher position, despite having a different time of flight, calculating the right initial velocity ensures he mirrors player A's results.

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Most popular questions from this chapter

As a tennis ball is struck, it departs from the racket horizontally with a speed of \(28.0 \mathrm{m} / \mathrm{s}\). The ball hits the court at a horizontal distance of \(19.6 \mathrm{m}\) from the racket. How far above the court is the tennis ball when it leaves the racket?

A bird watcher meanders through the woods, walking \(0.50 \mathrm{km}\) due east, \(0.75 \mathrm{km}\) due south, and \(2.15 \mathrm{km}\) in a direction \(35.0^{\circ}\) north of west. The time required for this trip is 2.50 h. Determine the magnitude and direction (relative to due west) of the bird watcher's (a) displacement and (b) average velocity. Use kilometers and hours for distance and time, respectively.

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is \(670 \mathrm{m} / \mathrm{s}\). The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target \(0.025 \mathrm{m}\) below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

A rifle is used to shoot twice at a target, using identical cartridges. The first time, the rifle is aimed parallel to the ground and directly at the center of the bull's-eye. The bullet strikes the target at a distance of \(H_{A}\) below the center, however. The second time, the rifle is similarly aimed, but from twice the distance from the target. This time the bullet strikes the target at a distance of \(H_{B}\) below the center. Find the ratio \(H_{B} / H_{A}\)

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of \(5.3 \mathrm{m} / \mathrm{s}\), hoping to land on the roof of an adjacent building. Air resistance is negligible. The horizontal distance between the two buildings is \(D,\) and the roof of the adjacent building is \(2.0 \mathrm{m}\) below the jumping-off point. Find the maximum value for \(D\).

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