/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 A major-league pitcher can throw... [FREE SOLUTION] | 91Ó°ÊÓ

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A major-league pitcher can throw a baseball in excess of \(41.0 \mathrm{m} / \mathrm{s}\). If a ball is thrown horizontally at this speed, how much will it drop by the time it reaches a catcher who is \(17.0 \mathrm{m}\) away from the point of release?

Short Answer

Expert verified
The ball will drop approximately 0.843 meters.

Step by step solution

01

Understand the Problem

You need to calculate how much the ball will drop due to gravity when thrown horizontally at a speed of \(41.0 \, \mathrm{m/s}\) over a horizontal distance of \(17.0 \, \mathrm{m}\).
02

Calculate the Time of Flight

Since the ball is thrown horizontally, use the horizontal speed and distance to find the time it takes for the ball to reach the catcher. Use the formula for time: \( t = \frac{d}{v} \). Here, \( d = 17.0 \, \mathrm{m} \) and \( v = 41.0 \, \mathrm{m/s} \). Thus, \( t = \frac{17.0}{41.0} \approx 0.4146 \, \mathrm{s} \).
03

Calculate the Vertical Drop

Use the formula for the vertical displacement due to gravity: \( h = \frac{1}{2}gt^2 \), where \( g \) is the acceleration due to gravity (approximately \(9.81 \, \mathrm{m/s^2}\)) and \( t \) is the time of flight calculated in Step 2. So, \( h = \frac{1}{2} \times 9.81 \times (0.4146)^2 \approx 0.843 \, \mathrm{m} \).
04

Conclusion

The ball will drop approximately \(0.843 \, \mathrm{m}\) by the time it reaches the catcher.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravity
Gravity is the force that pulls objects toward the earth's surface. It is responsible for the vertical motion of objects when they are in the air. When a baseball is thrown horizontally by a pitcher, gravity starts acting on it immediately. Regardless of the horizontal velocity, the ball experiences an acceleration downward due to gravity, which is a constant at approximately 9.81 m/s².

Understanding the role of gravity is essential in projectile motion problems because it determines how much an object will fall or drop over time. In our example, the effect of gravity is what causes the baseball, thrown horizontally, to drop by approximately 0.843 meters by the time it reaches the catcher.

Key points to remember about gravity in these scenarios include:
  • Gravity acts downwards consistently.
  • It is constant at 9.81 m/s² near the surface of the Earth.
  • Gravity affects only vertical motion, not horizontal.
Horizontal Velocity
Horizontal velocity refers to the speed at which an object moves along the horizontal plane. In projectile motion, horizontal velocity remains constant if air resistance is negligible. This is because there are typically no horizontal forces acting on the object once it’s been projected.

In the baseball example, the pitcher throws the ball with a horizontal velocity of 41.0 m/s. This high speed ensures the ball travels quickly across the horizontal distance of 17 meters to the catcher. Since there is no horizontal acceleration (assuming no air resistance), the horizontal velocity remains stable throughout the ball’s flight.

To determine the time of flight for the baseball, we use:
  • The formula: \[ t = \frac{d}{v} \]
  • The horizontal distance \(d = 17.0 \text{ meters} \)
  • The horizontal velocity \(v = 41.0 \text{ m/s} \)
This calculation becomes:\[ t = \frac{17.0}{41.0} \approx 0.4146 \text{ seconds} \]This time figure is crucial for emphasizing how horizontal velocity directly influences the dynamics of projectile motion.
Vertical Displacement
Vertical displacement in projectile motion refers to how far the object has moved vertically from its original position, under the effect of gravity. In our scenario, while the baseball is traveling horizontally, it is simultaneously dropping downwards due to gravity.

The calculation for vertical displacement is based on the time of flight and the acceleration due to gravity. The formula used for calculating the vertical drop is:\[ h = \frac{1}{2}gt^2 \]where:
  • \( g = 9.81 \text{ m/s}^2 \) (gravity)
  • \( t = 0.4146 \text{ seconds} \) (from the horizontal motion calculation)
Substituting these values, we find the vertical displacement:\[ h = \frac{1}{2} \times 9.81 \times (0.4146)^2 \approx 0.843 \text{ meters} \]
This calculation shows that despite being thrown horizontally, the ball shifts vertically by about 0.843 meters by the time it reaches the catcher, showcasing how vertical displacement occurs in all projectile motion due to gravity.

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Most popular questions from this chapter

Relative to the ground, a car has a velocity of \(16.0 \mathrm{m} / \mathrm{s}\), directed due north. Relative to this car, a truck has a velocity of \(24.0 \mathrm{m} / \mathrm{s}\), directed \(52.0^{\circ}\) north of east. What is the magnitude of the truck's velocity relative to the ground?

A spider crawling across a table leaps onto a magazine blocking its path. The initial velocity of the spider is \(0.870 \mathrm{m} / \mathrm{s}\) at an angle of \(35.0^{\circ}\) above the table, and it lands on the magazine 0.0770 s after leaving the table. Ignore air resistance. How thick is the magazine? Express your answer in millimeters.

A Coast Guard ship is traveling at a constant velocity of \(4.20 \mathrm{m} / \mathrm{s}\), due east, relative to the water. On his radar screen the navigator detects an object that is moving at a constant velocity. The object is located at a distance of \(2310 \mathrm{m}\) with respect to the ship, in a direction \(32.0^{\circ}\) south of east. Six minutes later, he notes that the object's position relative to the ship has changed to \(1120 \mathrm{m}, 57.0^{\circ}\) south of west. What are the magnitude and direction of the velocity of the object relative to the water? Express the direction as an angle with respect to due west.

A ferryboat is traveling in a direction \(38.0^{\circ}\) north of east with a speed of \(5.50 \mathrm{m} / \mathrm{s}\) relative to the water. A passenger is walking with a velocity of \(2.50 \mathrm{m} / \mathrm{s}\) due east relative to the boat. What is the velocity (magnitude and direction) of the passenger with respect to the water? Determine the directional angle relative to due east.

A quarterback claims that he can throw the football a horizontal distance of \(183 \mathrm{m}(200 \mathrm{yd}) .\) Furthermore, he claims that he can do this by launching the ball at the relatively low angle of \(30.0^{\circ}\) above the horizontal. To evaluate this claim, determine the speed with which this quarterback must throw the ball. Assume that the ball is launched and caught at the same vertical level and that air resistance can be ignored. For comparison, a baseball pitcher who can accurately throw a fastball at \(45 \mathrm{m} / \mathrm{s}(100 \mathrm{mph})\) would be considered exceptional.

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