/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 On a spacecraft, two engines are... [FREE SOLUTION] | 91Ó°ÊÓ

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On a spacecraft, two engines are turned on for 684 s at a moment when the velocity of the craft has \(x\) and \(y\) components of \(v_{0 x}=4370 \mathrm{m} / \mathrm{s}\) and \(v_{0 y}=6280 \mathrm{m} / \mathrm{s} .\) While the engines are firing, the craft undergoes a displacement that has components of \(x=4.11 \times 10^{6} \mathrm{m}\) and \(y=6.07 \times\) \(10^{6} \mathrm{m} .\) Find the \(x\) and \(y\) components of the craft's acceleration.

Short Answer

Expert verified
The acceleration components are \(a_x \approx 4.78 \, \text{m/s}^2\) and \(a_y \approx 7.58 \, \text{m/s}^2\).

Step by step solution

01

Understand the Problem

You are given the initial velocity components of a spacecraft \(v_{0x} = 4370 \, \text{m/s}\) and \(v_{0y} = 6280 \, \text{m/s}\) and a time of 684 seconds during which the engines are affecting the spacecraft's motion. The displacement during this time, \(x = 4.11 \times 10^6 \, \text{m}\) and \(y = 6.07 \times 10^6 \, \text{m}\), are also given. You need to find the acceleration components \(a_x\) and \(a_y\).
02

Use Kinematic Equations

To find the acceleration, use the kinematic equation for displacement: \[ s = v_0 t + \frac{1}{2} a t^2 \]For the \(x\)-component, it becomes:\[ 4.11 \times 10^6 = 4370 \times 684 + \frac{1}{2} a_x \times 684^2 \]And for the \(y\)-component:\[ 6.07 \times 10^6 = 6280 \times 684 + \frac{1}{2} a_y \times 684^2 \]
03

Solve for \(a_x\)

Rearrange the \(x\)-component equation to solve for \(a_x\):\[ 4.11 \times 10^6 = 4370 \times 684 + \frac{1}{2} a_x \times 684^2 \]First calculate the term with initial velocity:\[ 4370 \times 684 = 2991480 \]Substitute back into the equation and solve for \(a_x\):\[ 4.11 \times 10^6 = 2991480 + \frac{1}{2} a_x \times 684^2 \]\[ 1.11852 \times 10^6 = \frac{1}{2} a_x \times 684^2 \]\[ a_x = \frac{2 \times 1.11852 \times 10^6}{684^2} \]\[ a_x \approx 4.78 \, \text{m/s}^2 \]
04

Solve for \(a_y\)

Rearrange the \(y\)-component equation to solve for \(a_y\):\[ 6.07 \times 10^6 = 6280 \times 684 + \frac{1}{2} a_y \times 684^2 \]First calculate the term with initial velocity:\[ 6280 \times 684 = 4296720 \]Substitute back into the equation and solve for \(a_y\):\[ 6.07 \times 10^6 = 4296720 + \frac{1}{2} a_y \times 684^2 \]\[ 1.77328 \times 10^6 = \frac{1}{2} a_y \times 684^2 \]\[ a_y = \frac{2 \times 1.77328 \times 10^6}{684^2} \]\[ a_y \approx 7.58 \, \text{m/s}^2 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement
Displacement in kinematics refers to the change in position of an object. It is a vector quantity, which means it has both magnitude and direction. In the context of the spacecraft problem, displacement components in both the x and y directions are given:
  • An x-component of \(4.11 \times 10^6 \, \text{m} \)
  • A y-component of \(6.07 \times 10^6 \, \text{m} \)
Displacement differs from distance, as displacement only considers the starting and ending positions, while distance would consider the total path traveled. For this problem, knowing displacement helps in calculating the acceleration of the spacecraft once the initial velocity and time are known.
Velocity Components
Velocity is also a vector quantity and can be broken down into components, typically in the x and y directions in two-dimensional motion. These components are essential as they allow for separate analysis of motion in each direction.
  • The initial x-component of velocity for the spacecraft is \(v_{0x} = 4370 \, \text{m/s} \).
  • The initial y-component of velocity is \(v_{0y} = 6280 \, \text{m/s} \).
By understanding velocity components, you can solve complex motion problems by analyzing each direction separately. These components help determine the effects of external forces, like the engines in this problem, on the spacecraft's motion over the given time period of 684 seconds.
Acceleration Components
Acceleration, like velocity and displacement, is a vector and can also be expressed in components. It describes the rate of change of velocity with time. In the given exercise, the task is to find the x and y components of acceleration.To find these:- Use the kinematic equations that relate displacement, initial velocity, and acceleration over time.- The computations, as seen in the solution, involve rearranging the displacement formula to solve for the respective acceleration components.Knowing the acceleration components (\(a_x \approx 4.78 \, \text{m/s}^2 \) and \(a_y \approx 7.58 \, \text{m/s}^2 \)), gives us insight into how the spacecraft's velocity changes over time due to its engines.
Kinematic Equations
Kinematic equations are essential mathematical tools used to describe the motion of objects. They relate the five key motion variables: displacement (s), initial velocity (\(v_0\)), final velocity (v), acceleration (a), and time (t).For scenarios like the spacecraft problem, the key kinematic equation used is:\[s = v_0 t + \frac{1}{2} a t^2\]This equation links initial velocity, acceleration, and displacement over a specific time, allowing us to solve for unknown variables when the other quantities are known.Apply these equations:- For the x-direction: \[4.11 \times 10^6 = 4370 \times 684 + \frac{1}{2} a_x \times 684^2\]- For the y-direction: \[6.07 \times 10^6 = 6280 \times 684 + \frac{1}{2} a_y \times 684^2\]These steps in the solution demonstrate how to isolate and solve for acceleration, illustrating the powerful application of kinematic equations in physics.

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