/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 In diving to a depth of \(750 \m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In diving to a depth of \(750 \mathrm{m},\) an elephant seal also moves \(460 \mathrm{m}\) due east of his starting point. What is the magnitude of the seal's displacement?

Short Answer

Expert verified
The displacement is approximately 879.75 m.

Step by step solution

01

Understand the Problem

The elephant seal moves both vertically (downwards) to a depth of 750 m and horizontally (eastward) by 460 m. We need to find the straight-line distance, or displacement, from the starting point to the final position.
02

Identify the Right Triangle

Consider the vertical movement of 750 m and the horizontal movement of 460 m as the legs of a right triangle. The displacement is the hypotenuse of this triangle.
03

Apply the Pythagorean Theorem

To find the hypotenuse (displacement), apply the Pythagorean theorem: \( c^2 = a^2 + b^2 \), where \(a = 750\, \text{m}\) and \(b = 460\, \text{m}\).
04

Calculate the Squares of Each Side

Calculate \(750^2 = 562,500\) and \(460^2 = 211,600\).
05

Add the Results

Add the squares of both sides: \(562,500 + 211,600 = 774,100\).
06

Take the Square Root

Find the square root of 774,100 to get the hypotenuse: \( c = \sqrt{774,100} \approx 879.75 \).
07

State the Displacement

The magnitude of the seal's displacement is approximately 879.75 meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Displacement
Displacement is a measure of how far an object has moved from its original position in a straight line. It's a vector quantity, meaning it has both magnitude and direction. In the context of the elephant seal, its overall displacement is the direct distance from where it started to where it ended, regardless of the path taken.

When determining displacement, the direction is essential, as it affects how we describe the end position relative to the start. In this exercise, the displacement is calculated by considering both the downward and eastward movements. These movements form the two legs of a right triangle, leading directly to the calculation of the hypotenuse as the total displacement.
Right Triangle
A right triangle is a type of triangle that has one angle measuring 90 degrees. It consists of two legs and a hypotenuse, which is the longest side opposite the right angle.

In this exercise, when the seal dives 750 meters down and then moves 460 meters east, these two movements form the legs of a right triangle. The displacement of the seal becomes the hypotenuse. This arrangement is essential for applying the Pythagorean Theorem, which we'll explore next.
Hypotenuse
The hypotenuse is the longest side of a right triangle, opposite the right angle. It's the straight-line distance connecting the two endpoints of the legs.

To find the hypotenuse in this situation, we apply the Pythagorean Theorem, which helps us calculate this distance when the lengths of the other two sides are known. By squaring each leg, adding these squares, and then taking the square root, we find the hypotenuse. This gives the seal’s total displacement as approximately 879.75 meters.
  • Formula: The theorem is expressed as \( c^2 = a^2 + b^2 \).
  • In the seal's case: \( a = 750 \text{ m} \), \( b = 460 \text{ m} \).
Vector Addition
Vector addition is the process of combining two or more vectors to determine a resultant vector. When dealing with vectors, such as displacement, both magnitude and direction matter.

In this exercise, the seal's downward and eastward movements are vectors. By arranging them at right angles, they provide a complete picture of the seal’s path. When these vectors are added, they give the hypotenuse of the triangle, providing the resultant vector which is the overall displacement.

  • Think of each movement (750 m down and 460 m east) as arrows pointing in different directions.
  • The resultant vector, or displacement, can be found using the geometric method applied here.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A puck is moving on an air hockey table. Relative to an \(x, y\) coordinate system at time \(t=0\) s, the \(x\) components of the puck's initial velocity and acceleration are \(v_{0 x}=+1.0 \mathrm{m} / \mathrm{s}\) and \(a_{x}=+2.0 \mathrm{m} / \mathrm{s}^{2} .\) The \(y\) components of the puck's initial velocity and acceleration are \(v_{0 y}=+2.0 \mathrm{m} / \mathrm{s}\) and \(a_{y}=-2.0 \mathrm{m} / \mathrm{s}^{2} .\) Find the magnitude and direction of the puck's velocity at a time of \(t=0.50\) s. Specify the direction relative to the \(+x\) axis.

A projectile is launched from ground level at an angle of \(12.0^{\circ}\) above the horizontal. It returns to ground level. To what value should the launch angle be adjusted, without changing the launch speed, so that the range doubles?

In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.050 s, during which time it experiences an acceleration of \(340 \mathrm{m} / \mathrm{s}^{2} .\) The ball is launched at an angle of \(51^{\circ}\) above the ground. Determine the horizontal and vertical components of the launch velocity.

In a marathon race Chad is out in front, running due north at a speed of \(4.00 \mathrm{m} / \mathrm{s} .\) John is \(95 \mathrm{m}\) behind him, running due north at a speed of \(4.50 \mathrm{m} / \mathrm{s} .\) How long does it take for John to pass Chad?

A jetliner can fly 6.00 hours on a full load of fuel. Without any wind it flies at a speed of \(2.40 \times 10^{2} \mathrm{m} / \mathrm{s} .\) The plane is to make a round-trip by heading due west for a certain distance, turning around, and then heading due east for the return trip. During the entire flight, however, the plane encounters a \(57.8-\mathrm{m} / \mathrm{s}\) wind from the jet stream, which blows from west to east. What is the maximum distance that the plane can travel due west and just be able to return home?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.