/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 A piece of copper wire is formed... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A piece of copper wire is formed into a single circular loop of radius \(12 \mathrm{cm} .\) A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to \(0.60 \mathrm{T}\) in a time of \(0.45 \mathrm{s}\). The wire has a resistance per unit length of \(3.3 \times 10^{-2} \Omega / \mathrm{m} .\) What is the average electrical energy dissipated in the resistance of the wire?

Short Answer

Expert verified
The average electrical energy dissipated is approximately 0.066 Joules.

Step by step solution

01

Calculate the Loop's Circumference

First, find the circumference of the circular loop using the formula for the circumference of a circle, which is \( C = 2\pi r \). The radius \( r \) is given as \( 12\text{ cm} = 0.12\text{ m} \). So, \( C = 2\pi \times 0.12 \approx 0.755 \text{ m} \).
02

Determine the Total Resistance of the Wire

The resistance per unit length is given as \( 3.3 \times 10^{-2} \Omega/m \). The total resistance \( R \) of the wire is the resistance per unit length times the circumference: \( R = 3.3 \times 10^{-2} \times 0.755 \approx 0.0249 \Omega \).
03

Calculate the Change in Magnetic Flux

The magnetic flux \( \Phi \) through the loop is given by \( \Phi = B \cdot A \), where \( B \) is the magnetic field, and \( A = \pi r^2 \) is the area of the loop. The change in flux \( \Delta \Phi \) due to the change in magnetic field from 0 to 0.60 T is \( \Delta \Phi = (0.60 \text{ T}) \cdot \pi \cdot (0.12)^2 \). So, \( \Delta \Phi \approx 0.0271 \text{ Wb} \).
04

Calculate the Induced EMF

According to Faraday's Law, the average EMF induced in the loop is given by \( \text{EMF} = -\frac{\Delta \Phi}{\Delta t} \), where \( \Delta t = 0.45\text{ s} \). Thus, \( \text{EMF} = -\frac{0.0271}{0.45} \approx -0.0602 \text{ V} \).
05

Determine the Induced Current

Using Ohm's Law, the current \( I \) flowing through the loop is given by \( I = \frac{\text{EMF}}{R} \). Substituting the calculated values, \( I = \frac{0.0602}{0.0249} \approx 2.419 \text{ A} \).
06

Calculate the Electrical Energy Dissipated

The average power dissipated in the resistance is \( P = I^2 R \), and the energy dissipated over time \( \Delta t \) is \( E = P \cdot \Delta t \). Calculate \( E = (2.419)^2 \times 0.0249 \times 0.45 \approx 0.066 \text{ J} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law is a fundamental principle that describes how voltage is generated in a circuit by a changing magnetic field. This principle is key to understanding the phenomenon of electromagnetic induction. - **What Happens?** - When a magnetic field changes with time, it induces an electromotive force (EMF) in a loop of conductor. - This change can be in the field's magnitude, direction, or in the area of the loop intersecting the field.- **The Formula** - Mathematically, Faraday's Law states that the EMF induced is equal to the negative rate of change of magnetic flux through the loop: \[ \text{EMF} = -\frac{\Delta \Phi}{\Delta t} \] - Here, \(\Delta \Phi\) represents the change in magnetic flux and \(\Delta t\) the time over which it changes.- **Direction of Induced EMF** - The negative sign in the formula indicates Lenz's Law. This tells us that the direction of the induced current is such that it opposes the change in magnetic flux. - This is a nature's mechanism to conserve energy and is a crucial aspect of electromagnetic induction.
Magnetic Flux
Magnetic flux is a measure of the quantity of magnetism, taking into account the strength and the extent of a magnetic field. It’s a crucial concept for understanding how magnetic fields interact with electrical circuits.- **Basic Concept** - Magnetic flux (\( \Phi \)) through a surface is calculated as the product of the magnetic field (\( B \)) and the area (\( A \)) perpendicular to the field: \[ \Phi = B \cdot A \] - It is measured in webers (Wb).- **How It Changes** - Any change in the field strength, the orientation of the area with respect to the magnetic field, or the size of the area, results in a change of magnetic flux. - This change is what drives electromagnetic induction as it affects the induced EMF according to Faraday's Law.- **Importance of Area** - In the exercise, the area is a circle, determined by the loop’s radius \( r \), given by the formula \( A = \pi r^2 \). - Any change in the magnetic flux through this area contributes to the generation of voltage as per Faraday's Law.
Ohm's Law
Ohm's Law is a fundamental principle used to understand how current flows in a circuit in response to voltage. This concept is essential for solving the type of problem found in the exercise.- **Formula Basics** - The law states that the current (\( I \)) through a conductor between two points is directly proportional to the voltage (\( V \)) across the two points and inversely proportional to the resistance (\( R \)): \[ I = \frac{V}{R} \] - In the exercise, the voltage corresponds to the induced EMF.- **In Application** - Once the EMF is known from the change in magnetic flux, you can calculate the current using Ohm's Law. - This relationship helps find out how much current flows through the loop, which further aids in calculating the power dissipated in the circuit.- **Resistance Role** - The resistance of the wire is crucial since it determines how much of the induced EMF gets converted into useful current. - This resistance is affected by the wire’s material, length, and area.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is \(45.0 \Omega .\) The area of each turn is \(4.70 \times 10^{-4} \mathrm{m}^{2} .\) This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be \(8.87 \times 10^{-3} \mathrm{C} .\) Find the magnitude of the magnetic field.

The drawing shows a straight wire carrying a current \(I\). Above the wire is a rectangular loop that contains a resistor \(R\). If the current \(I\) is decreasing in time, what is the direction of the induced current through the resistor \(R-\) left-to-right or right-to-left?

Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surface is tilted at an angle of \(12^{\circ}\) from the horizontal, and a net magnetic flux of \(8.4 \times 10^{-3} \mathrm{Wb}\) passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. (b) Find the smallest possible value for the area of the second surface.

Two \(0.68-\mathrm{m}\) -long conducting rods are rotating at the same speed in opposite directions, and both are perpendicular to a 4.7-T magnetic field. As the drawing shows, the ends of these rods come to within \(1.0 \mathrm{mm}\) of each other as they rotate. Moreover, the fixed ends about which the rods are rotating are connected by a wire, so these ends are at the same electric potential. If a potential difference of \(4.5 \times 10^{3} \mathrm{V}\) is required to cause a 1.0 -mm spark in air, what is the angular speed (in \(\mathrm{rad} / \mathrm{s}\) ) of the rods when a spark jumps across the gap?

A rectangular loop of wire with sides 0.20 and \(0.35 \mathrm{m}\) lies in a plane perpendicular to a constant magnetic field (see part \(a\) of the drawing). The magnetic field has a magnitude of \(0.65 \mathrm{T}\) and is directed parallel to the normal of the loop's surface. In a time of 0.18 s, one-half of the loop is then folded back onto the other half, as indicated in part \(b\) of the drawing. Determine the magnitude of the average emf induced in the loop.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.