/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 A conducting coil of 1850 turns ... [FREE SOLUTION] | 91Ó°ÊÓ

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A conducting coil of 1850 turns is connected to a galvanometer, and the total resistance of the circuit is \(45.0 \Omega .\) The area of each turn is \(4.70 \times 10^{-4} \mathrm{m}^{2} .\) This coil is moved from a region where the magnetic field is zero into a region where it is nonzero, the normal to the coil being kept parallel to the magnetic field. The amount of charge that is induced to flow around the circuit is measured to be \(8.87 \times 10^{-3} \mathrm{C} .\) Find the magnitude of the magnetic field.

Short Answer

Expert verified
The magnitude of the magnetic field is approximately 0.448 T (Tesla).

Step by step solution

01

Understand the Problem

We need to find the magnitude of the magnetic field (\(B\)) based on the given conditions: The coil with 1850 turns and a given area per turn is moved into a uniform magnetic field, inducing a known charge with a total circuit resistance.
02

Use Faraday's Law of Induction

Faraday's Law states that the induced electromotive force (emf) in the coil is equal to the change in magnetic flux times the number of turns (\(N\)). The equation is \( \text{emf} = -N \frac{d\Phi}{dt} \), where \(\Phi\) is the magnetic flux. Since the coil moves entirely into the magnetic field, the total change in flux is \(N \times A \times B\).
03

Relate Charge to Induced EMF

The total charge (\(Q\)) induced in the circuit is related to the emf by Ohm's Law, \(Q = \frac{\text{emf}}{R}\), where \(R\) is the total resistance of the circuit. Rearranging this gives \( \text{emf} = Q \times R \). Substitute this into the equation from Faraday's Law.
04

Solve for Magnetic Field B

Substitute the expression for \(\text{emf}\) from Step 3 into the Faraday's Law expression: \( Q \times R = N \times A \times B \). Rearrange to solve for \(B\): \( B = \frac{Q \times R}{N \times A} \).
05

Insert Given Values and Calculate

Given values are \(Q = 8.87 \times 10^{-3} \mathrm{C}\), \(R = 45.0 \Omega\), \(N = 1850\), and \(A = 4.70 \times 10^{-4} \mathrm{m}^2\). Substitute these into the equation: \( B = \frac{8.87 \times 10^{-3} \mathrm{C} \times 45.0 \Omega}{1850 \times 4.70 \times 10^{-4} \mathrm{m}^2} \approx 0.448 \mathrm{T} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle of electromagnetism that explains how electric currents can be generated by changing magnetic fields. It essentially states that a change in magnetic flux through a loop induces an electromotive force (emf) in the wire. The law is captured by the equation: \[ \text{emf} = -N \frac{d\Phi}{dt} \] where \( N \) is the number of turns of the coil and \( \Phi \) is the magnetic flux. This principle is what allows for the generation of electricity in most electric generators. When a coil is exposed to a changing magnetic field, an emf is induced, causing a current to flow if there is a closed loop. Faraday's Law helps us calculate how strong this induced voltage is, based on how quickly the magnetic flux
  • changes over time,
  • the number of turns in the coil,
  • and the area through which the field lines pass.
In our exercise, the coil was moved into a region with a magnetic field, creating a change in magnetic flux that induced an emf. The emf then produced a current, which we used to determine the magnetic field's strength.
Magnetic Flux
Magnetic flux \( \Phi \) is a measure of the strength and the extent of a magnetic field passing through a surface. It's described mathematically as: \[ \Phi = B \cdot A \cdot \cos(\theta) \] where \( B \) represents the magnetic field strength, \( A \) is the area that the field lines penetrate, and \( \theta \) is the angle between the magnetic field lines and the perpendicular to the surface. Think of magnetic flux as the number of magnetic field lines passing through a certain area. More lines equal greater flux. The concept of magnetic flux helps us understand how effectively a magnetic field interacts with a given surface.
  • If \( \theta = 0 \), the field is perfectly aligned with the surface, maximizing the flux.
  • If \( \theta = 90^\circ \), the field is parallel to the surface, resulting in zero flux.
In our problem, the coil changed its position relative to a magnetic field and thus underwent a change in magnetic flux, which is exactly how Faraday’s Law predicts an induced current.
Ohm's Law
Ohm's Law is a simple yet essential principle in electrical circuits. It articulates the relationship between voltage, current, and resistance in most electrical circuits. The formula is expressed as: \[ V = I \cdot R \] where \( V \) is the voltage (emf in the context of our exercise), \( I \) is the current, and \( R \) is the resistance. This fundamental relation allows us to calculate one quantity if we know the other two. In our exercise, we used a derived form of Ohm's Law. Given the total charge \( Q \) induced in the circuit, we can use Ohm's Law to relate it to the induced emf via the circuit's resistance \( R \): \[ Q = \frac{V}{R} \] Solving for \( V \), we find that \( V = Q \times R \). This helped us bridge the gap between the induced emf (voltage) and the changing magnetic flux. By knowing the total resistance and the induced charge, we can find the magnetic field's strength using the relation established from Faraday’s Law and Ohm’s Law.

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Most popular questions from this chapter

A \(5.40 \times 10^{-5} \mathrm{H}\) solenoid is constructed by wrapping 65 turns of wire around a cylinder with a cross-sectional area of \(9.0 \times 10^{-4} \mathrm{m}^{2} .\) When the solenoid is shortened by squeezing the turns closer together, the inductance increases to \(8.60 \times 10^{-5}\) H. Determine the change in the length of the solenoid.

The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e.g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose that the speed of the blood is \(0.30 \mathrm{m} / \mathrm{s}\) and the diameter of the vessel is \(5.6 \mathrm{mm} .\) In a \(0.60-\mathrm{T}\) magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

A planar coil of wire has a single turn. The normal to this coil is parallel to a uniform and constant (in time) magnetic field of 1.7 'I. An emf that has a magnitude of \(2.6 \mathrm{V}\) is induced in this coil because the coil's area \(A\) is shrinking. What is the magnitude of \(\Delta A / \Delta t,\) which is the rate (in \(\mathrm{m}^{2} / \mathrm{s}\) ) at which the area changes?

A \(120.0-\mathrm{V}\) motor draws a current of \(7.00 \mathrm{A}\) when running at normal speed. The resistance of the armature wire is \(0.720 \Omega .\) (a) Determine the back emf generated by the motor. (b) What is the current at the instant when the motor is just turned on and has not begun to rotate? (c) What series resistance must be added to limit the starting current to \(15.0 \mathrm{A} ?\)

A standard door into a house rotates about a vertical axis through one side, as defined by the door's hinges. A uniform magnetic field is parallel to the ground and perpendicular to this axis. Through what angle must the door rotate so that the magnetic flux that passes through it decreases from its maximum value to one-third of its maximum value?

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