/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 Indicate the direction of the el... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Indicate the direction of the electric field between the plates of the parallel plate capacitor shown in the drawing if the magnetic field is decreasing in time. Give your reasoning.

Short Answer

Expert verified
The electric field is directed from the top to the bottom plate due to the decreasing magnetic field.

Step by step solution

01

Understand the Exercise

The problem describes a parallel plate capacitor in which the magnetic field between the plates is decreasing with time. We need to find the direction of the electric field induced between these plates.
02

Recall Faraday's Law of Induction

Faraday's Law states that a changing magnetic field induces an electric field. Mathematically, this is represented as \( abla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t} \), where \( \mathbf{E} \) is the electric field and \( \mathbf{B} \) is the magnetic field.
03

Analyze the Given Scenario

Since the magnetic field is decreasing, \( \frac{\partial \mathbf{B}}{\partial t} < 0 \). According to Faraday's Law, this means that the induced electric field \( \mathbf{E} \) will be in a direction to oppose this change, creating a counterclockwise loop around the region where \( \mathbf{B} \) is decreasing.
04

Determine the Direction of Electric Field

For a parallel plate capacitor, if you view the plates from a side where the plates are horizontal, a clockwise induced electric field lines may be represented. The direction of the electric field between the plates will be from the positively charged plate to the negatively charged plate according to its natural orientation. Given the counteraction required due to the decreasing magnetic field, it should result in a clockwise electric field viewed from a side.
05

Conclusion

Thus, the electric field between the plates of the capacitor will be directed from the top plate to the bottom plate when viewed along the direction of \( \vec{B} \) going into the page.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law of Induction
Faraday's Law of Induction is a fundamental principle in electromagnetism. It explains how a changing magnetic field can induce an electric field. When the magnetic field varies over time, it creates an electric field in its surrounding space. This phenomenon is central to many technologies, such as electric generators and transformers.

The law is expressed mathematically as: \( abla \times \mathbf{E} = - \frac{\partial \mathbf{B}}{\partial t} \). Here, \( abla \times \mathbf{E} \) represents the curl or circulation of the electric field \( \mathbf{E} \), and \( \frac{\partial \mathbf{B}}{\partial t} \) indicates the rate of change of the magnetic field \( \mathbf{B} \) over time.

In simpler terms:
  • A decreasing magnetic field induces an electric field in a direction that attempts to oppose the reduction.
  • The induced field forms loops around the area where the magnetic field changes.
Faraday's Law shows that you don't need a physical conductor to have an electric field. It's the change in the magnetic field that is crucial, highlighting an intrinsic relationship in the fabric of electromagnetism.
Parallel Plate Capacitor
A parallel plate capacitor is a device that stores electric energy by maintaining an electric field between two conductive plates.

Let's break down its structure:
  • Two parallel conductive plates, typically metal.
  • An insulating material (dielectric) exists between the plates, preventing direct electrical contact.
The function of a parallel plate capacitor:
  • It accumulates electrical charge on each plate when connected to a voltage source.
  • Charge separation creates a uniform electric field between the plates.
The strength of the electric field \( E \) between the plates is given by \( E = \frac{V}{d} \), where \( V \) is the voltage applied across the plates and \( d \) is the distance between the plates.

In the context of a changing magnetic field, as described in the original exercise, Faraday's Law states that the change will induce an electric field that tries to resist that change. Therefore, understanding the role of electric and magnetic fields within a capacitor is crucial for leveraging their interactions in various applications.
Magnetic Field
A magnetic field is an invisible force field created by moving electric charges and magnetic materials. It is represented by the symbol \( \mathbf{B} \) and has both magnitude and direction. The simplest way to visualize a magnetic field is by using field lines that show the direction a north magnetic pole would move if placed within the field.

Key characteristics:
  • Magnetic fields exert forces on other magnets and currents within the field.
  • The field becomes stronger near the source of magnetism and weaker with distance.
In practical scenarios, changing magnetic fields play a vital role. According to Faraday's Law of Induction, a time-varying magnetic field can induce an electric field. This is especially important in the context of a parallel plate capacitor, where a decrease in the magnetic field can generate circular electric field lines that oppose the change.

The direction of this induced field can be deduced using the right-hand rule where the thumb direction indicates the conventional direction of the current (in this case, the direction of decreasing magnetic field), and curled fingers suggest the direction of induced loops of electric field. Understanding how magnetic fields interact with electric fields is foundational for electromagnetism and its applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A magnetic field is passing through a loop of wire whose area is \(0.018 \mathrm{m}^{2} .\) The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of \(0.20 \mathrm{T} / \mathrm{s}\) (a) Determine the magnitude of the emf induced in the loop. (b) Suppose that the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in \(\mathrm{m}^{2} / \mathrm{s}\) ) should the area be changed at the instant when \(B=1.8 \mathrm{T}\) if the induced emf is to be zero? Explain whether the area is to be enlarged or shrunk.

You need to design a \(60.0-\mathrm{Hz}\) ac generator that has a maximum emf of \(5500 \mathrm{V}\). The generator is to contain a 150 -turn coil that has an area per turn of \(0.85 \mathrm{m}^{2} .\) What should be the magnitude of the magnetic field in which the coil rotates?

In a television set the power needed to operate the picture tube comes from the secondary of a transformer. The primary of the transformer is connected to a \(120-\mathrm{V}\) receptacle on a wall. The picture tube of the television set uses \(91 \mathrm{W}\), and there is \(5.5 \mathrm{mA}\) of current in the secondary coil of the transformer to which the tube is connected. Find the turns ratio \(N_{\mathrm{s}} / N_{\mathrm{p}}\) of the transformer.

Two coils of wire are placed close together. Initially, a current of \(2.5 \mathrm{A}\) exists in one of the coils, but there is no current in the other. The current is then switched off in a time of \(3.7 \times 10^{-2} \mathrm{s}\). During this time, the average emf induced in the other coil is \(1.7 \mathrm{V}\). What is the mutual inductance of the two-coil system?

A standard door into a house rotates about a vertical axis through one side, as defined by the door's hinges. A uniform magnetic field is parallel to the ground and perpendicular to this axis. Through what angle must the door rotate so that the magnetic flux that passes through it decreases from its maximum value to one-third of its maximum value?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.