/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A steel cable has a cross-sectio... [FREE SOLUTION] | 91Ó°ÊÓ

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A steel cable has a cross-sectional area \(2.83 \times 10^{-3} \mathrm{m}^{2}\) and is kept under a tension of \(1.00 \times 10^{4} \mathrm{N}\). The density of steel is \(7860 \mathrm{kg} / \mathrm{m}^{3}\). Note that this value is not the linear density of the cable. At what speed does a transverse wave move along the cable?

Short Answer

Expert verified
The speed of the wave is 21.21 m/s.

Step by step solution

01

Identify the relevant formula

To find the speed of a transverse wave on a cable, we use the formula \(v = \sqrt{\frac{T}{\mu}}\), where \(v\) is the wave speed, \(T\) is the tension in the cable, and \(\mu\) is the linear mass density of the cable.
02

Calculate the linear mass density

The linear mass density \(\mu\) is given by \(\mu = \rho \cdot A\), where \(\rho\) is the density of the material and \(A\) is the cross-sectional area. Substitute the values: \(\mu = 7860 \ \mathrm{kg/m^3} \times 2.83 \times 10^{-3} \ \mathrm{m^2} = 22.2398 \ \mathrm{kg/m}\).
03

Calculate the wave speed

Using the formula from Step 1 and the calculated \(\mu\) from Step 2, plug in the values: \(v = \sqrt{\frac{1.00 \times 10^{4} \ \mathrm{N}}{22.2398 \ \mathrm{kg/m}}} = \sqrt{449.7} = 21.21 \ \mathrm{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tension in Cable
The tension in a cable is a critical factor in determining the speed of transverse waves traveling through it. Tension refers to the force exerted along the cable that stretches or pulls it tight. In the context of wave mechanics, tension is denoted by the symbol \( T \) and is usually measured in Newtons (N).
When a cable is under tension, it affects wave propagation by varying the speed at which waves travel through the medium. The higher the tension, the faster the wave moves. This is because increased tension leads to swifter restoration of particles to their equilibrium positions, allowing the wave energy to traverse the cable at more rapid rates.
Key points to understand about tension are:
  • Tension increases with greater force applied to the cable.
  • High tension leads to more significant wave speeds.
  • Calculating tension accurately is crucial for determining wave behavior in practical applications such as engineering or sound transmissions.
Linear Mass Density
Linear mass density, often symbolized as \( \mu \), represents the mass of a cable per unit length. It's a crucial parameter for calculating wave speed in a longitudinal medium. It measures how much mass is in a given length of cable and is expressed in kilograms per meter (kg/m).
To determine linear mass density, you need two factors: the material's density (\( \rho \), in kg/m³) and the cross-sectional area of the cable (\( A \), in m²). It is calculated using the formula \( \mu = \rho \cdot A \).
As seen in the example problem, the density of steel and the specific cross-sectional area provided the necessary values to calculate \( \mu \) as 22.2398 kg/m. This information, in turn, plays a crucial role in determining the wave speed.
Key insights include:
  • Higher linear density usually results in slower wave speeds, as denser materials require more energy to oscillate.
  • Understanding linear density is essential for fields like material science and structural engineering, where wave behavior impacts design and functionality.
Wave Mechanics
Wave mechanics involves the study of how waves propagate through different mediums. In this context, we focus on transverse waves, which are waves that travel perpendicular to the direction of particle displacement.
The speed of transverse waves in a cable can be calculated using the formula \( v = \sqrt{\frac{T}{\mu}} \), where \( v \) is wave speed, \( T \) is tension, and \( \mu \) is linear mass density. This reflects the relationship between the internal properties of the material (tension and mass density) and how energy is transferred as waves move through the material.
In transverse waves:
  • The movement of particles is perpendicular to the direction of energy transfer.
  • Waves carry energy without carrying matter with them.
  • Examples include vibrations in strings and seismic waves that shake the ground.
Understanding wave mechanics is essential in physics, as it applies to many areas, from musical instruments to earthquake analysis and beyond.

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Most popular questions from this chapter

Two sources of sound are located on the \(x\) axis, and each emits power uniformly in all directions. There are no reflections. One source is positioned at the origin and the other at \(x=+123 \mathrm{m}\). The source at the origin emits four times as much power as the other source. Where on the \(x\) axis are the two sounds equal in intensity? Note that there are two answers.

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