/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Two wires are parallel, and one ... [FREE SOLUTION] | 91Ó°ÊÓ

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Two wires are parallel, and one is directly above the other. Each has a length of \(50.0 \mathrm{m}\) and a mass per unit length of \(0.020 \mathrm{kg} / \mathrm{m} .\) However, the tension in wire \(\mathrm{A}\) is \(6.00 \times 10^{2} \mathrm{N},\) and the tension in wire \(\mathrm{B}\) is \(3.00 \times 10^{2} \mathrm{N} .\) Transverse wave pulses are generated simultaneously, one at the left end of wire \(\mathrm{A}\) and one at the right end of wire \(\mathrm{B}\). The pulses travel toward each other. How much time does it take until the pulses pass each other?

Short Answer

Expert verified
The pulses pass each other in approximately 0.169 seconds.

Step by step solution

01

Determine Wave Velocity on Wire A

The velocity of a wave on a wire is determined by the formula \( v = \sqrt{\frac{T}{\mu}} \), where \( T \) is the tension and \( \mu \) is the mass per unit length. For wire A, \( \mu = 0.020 \mathrm{kg}/\mathrm{m} \) and \( T = 600 \mathrm{N} \). Therefore, the velocity \( v_A = \sqrt{\frac{600}{0.020}} = \sqrt{30000} \). Calculating gives \( v_A = 173.2 \, \mathrm{m/s} \).
02

Determine Wave Velocity on Wire B

Similarly, we calculate the wave velocity for wire B using \( v_B = \sqrt{\frac{T}{\mu}} \). Here, \( T = 300 \mathrm{N} \) and \( \mu = 0.020 \mathrm{kg}/\mathrm{m} \), so \( v_B = \sqrt{\frac{300}{0.020}} = \sqrt{15000} \). Calculating gives \( v_B = 122.5 \, \mathrm{m/s} \).
03

Calculate the Time for Pulses to Pass Each Other

The total distance between the starting points of the pulses is 50 meters, as each wire is 50 meters long and they are aligned end-to-end across two different wires. The pulses move towards each other, so we add their velocities to find the relative velocity, \( v_{relative} = v_A + v_B = 173.2 + 122.5 = 295.7 \mathrm{m/s} \). The time taken for them to meet is given by \( t = \frac{d}{v_{relative}} = \frac{50.0}{295.7} \approx 0.169 \mathrm{s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transverse Waves
Transverse waves are a type of wave where the motion of the medium's particles is perpendicular to the direction of wave travel. Imagine a wave moving along a wire; the particles of the wire move up and down as the wave travels horizontally along its length.
Transverse waves are important when studying waves on wires, as they are the type of waves typically generated in such scenarios. The characteristics of transverse waves include their wavelength, frequency, speed, and amplitude. These properties help describe how the wave looks and behaves as it travels through the medium.
In this particular exercise, transverse waves are generated on two wires, wire A and wire B. The waves travel in opposite directions on these parallel wires and eventually pass each other. Understanding the nature of transverse waves and how they move is essential when calculating their velocities, as their behavior is determined by factors like tension and mass per unit length of the wire.
Tension in Wires
The tension in a wire plays a crucial role in determining the velocity of waves traveling through it. Tension refers to the force exerted along the length of the wire and is measured in Newtons (N). A wire with higher tension will allow a wave to travel faster through it, due to the increased force that keeps the wire tight.
The formula for wave velocity in a wire is given by \[ v = \sqrt{\frac{T}{\mu}} \] where \( T \) is the tension of the wire, and \( \mu \) is the mass per unit length. This equation tells us that the wave speed increases as tension increases.
In the exercise, wire A has a tension of 600 N, while wire B has a tension of 300 N. As a result, the wave on wire A travels faster than the wave on wire B. Higher tension results in less sag or sway in the wire, providing less resistance to the wave and causing it to move more quickly.
Mass Per Unit Length
Mass per unit length, often denoted by \( \mu \), is another critical factor affecting the velocity of waves on a wire. It is measured in kilograms per meter (kg/m) and represents the mass of the wire distributed over its length.
This concept is central to understanding how waves behave on different wires. The formula for wave velocity, \( v = \sqrt{\frac{T}{\mu}} \), demonstrates that a decrease in mass per unit length \( \mu \) leads to an increase in wave velocity. Essentially, a lighter wire allows waves to travel faster since there is less mass to move.
In our problem, both wires A and B have the same mass per unit length of 0.020 kg/m. This constant factor allows us to compare the effect of different tensions on the velocity of waves in each wire. The uniformity in mass per unit length highlights the direct influence of tension differences on wave velocity.

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Most popular questions from this chapter

An amplified guitar has a sound intensity level that is \(14 \mathrm{dB}\) greater than the same unamplified sound. What is the ratio of the amplified intensity to the unamplified intensity?

A member of an aircraft maintenance crew wears protective earplugs that reduce the sound intensity by a factor of \(350 .\) When a jet aircraft is taking off, the sound intensity level experienced by the crew member is 88 dB. What sound intensity level would the crew member experience if he removed the protective earplugs?

The mass of a string is \(5.0 \times 10^{-3} \mathrm{kg},\) and it is stretched so that the tension in it is \(180 \mathrm{N}\). A transverse wave traveling on this string has a frequency of \(260 \mathrm{Hz}\) and a wavelength of \(0.60 \mathrm{m} .\) What is the length of the string?

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