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Suppose that the linear density of the A string on a violin is \(7.8 \times 10^{-4} \mathrm{kg} / \mathrm{m} .\) A wave on the string has a frequency of \(440 \mathrm{Hz}\) and a wavelength of \(65 \mathrm{cm} .\) What is the tension in the string?

Short Answer

Expert verified
The tension in the string is 63.8 N.

Step by step solution

01

Convert Units

The wavelength is given in centimeters. First, convert this to meters by dividing by 100. So, the wavelength \( \lambda = 65 \text{ cm} = 0.65 \text{ m} \).
02

Use the Wave Speed Formula

The wave speed \( v \) on a string is related to frequency \( f \) and wavelength \( \lambda \) by the formula \( v = f \lambda \). Substitute \( f = 440 \text{ Hz} \) and \( \lambda = 0.65 \text{ m} \): \[ v = 440 \times 0.65 = 286 \text{ m/s}. \]
03

Write Down the Formula for Tension in the String

The tension \( T \) in the string can be found using the formula \( v = \sqrt{\frac{T}{\mu}} \), where \( \mu \) is the linear density of the string.
04

Rearrange for Tension

Rearrange the tension formula to solve for \( T \): \( v^2 = \frac{T}{\mu} \) becomes \( T = \mu v^2 \).
05

Substitute Known Values

Substitute the linear density \( \mu = 7.8 \times 10^{-4} \text{ kg/m} \) and wave speed \( v = 286 \text{ m/s} \) into the equation for tension: \[ T = 7.8 \times 10^{-4} \times (286)^2. \]
06

Perform the Calculation

Calculate the tension: \[ T = 7.8 \times 10^{-4} \times 81796 = 63.8 \text{ N}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Density
In physics, linear density is a property of materials that describes their mass per unit length. It tells us how much mass occupies a certain length of the material. For example, if you have a string, the linear density will tell you how heavy a one-meter section of that string is.

Mathematically, linear density is represented by the symbol \( \mu \) (mu) and is defined as follows:
  • \( \mu = \frac{m}{L} \)
where \( m \) is the mass of the string and \( L \) is its length. Linear density is measured in kilograms per meter (kg/m).

Understanding linear density is crucial when determining the wave characteristics on a string, like speed and tension. For example, the linear density of an A string on a violin helps in calculating the tension required to produce a sound at a specific frequency.
Frequency
Frequency is a fundamental concept when it comes to understanding waves. It describes how often the wave oscillates or vibrates per second. Frequency is measured in Hertz (Hz), which equates to one oscillation per second.

In the context of a violin string, the frequency determines the pitch of the note. For example, the A string on a violin typically vibrates at a frequency of 440 Hz, which corresponds to the standard pitch of the musical note A above middle C.
  • High frequency = high pitch sound
  • Low frequency = low pitch sound
The frequency of a wave on a string is directly related to its speed and wavelength. This relationship is an integral part of calculating other properties such as tension in the string, using the formula:\[ v = f \lambda \] where \( v \) is wave speed, \( f \) is frequency, and \( \lambda \) is wavelength.
Wavelength
Wavelength is the distance between two successive crests or troughs of a wave. It's essentially the "length" of one complete wave cycle. The wavelength is typically measured in meters (m).

In our exercise, the wavelength of the wave on the violin A string is given as 65 cm. Since we usually conduct these calculations in meters, it's important to convert this measurement into meters, which becomes 0.65 m. This conversion is necessary for accurately applying the wave speed formula in physics.

Together with frequency, wavelength determines the wave's speed. The fundamental relationship is expressed as:\[ v = f \lambda \] where \( v \) is the wave speed, \( f \) is the frequency, and \( \lambda \) is the wavelength. This concept is key to solving problems involving wave speed and tension in strings.
Tension in String
Tension in a string is an important factor that influences how waves propagate along it. Tension refers to the force exerted along the string, pulling it taut. When we talk about strings on musical instruments like violins, tension affects the pitch of the sound produced.

There is a direct relationship between the wave speed \( v \), linear density \( \mu \), and tension \( T \) in the string, given by the formula:
  • \[ v = \sqrt{\frac{T}{\mu}} \]
This equation can be rearranged to solve for tension:
  • \[ T = \mu v^2 \]
In our context, using the linear density of \( 7.8 \times 10^{-4} \) kg/m and the wave speed of 286 m/s, substituting these values into the equation gives us the tension in the violin string as approximately 63.8 N (Newtons). Understanding tension is crucial for tuning instruments and analyzing waveforms.

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Most popular questions from this chapter

Hearing damage may occur when a person is exposed to a sound intensity level of \(90.0 \mathrm{dB}\) (relative to the threshold of hearing) for a period of 9.0 hours. One particular eardrum has an area of \(2.0 \times 10^{-4} \mathrm{m}^{2} .\) How much sound energy is incident on this eardrum during this time?

A speedboat, starting from rest, moves along a straight line away from a dock. The boat has a constant acceleration of \(+3.00 \mathrm{m} / \mathrm{s}^{2}\) (see the figure). Attached to the dock is a siren that is producing a \(755-\mathrm{Hz}\) tone. If the air temperature is \(20^{\circ} \mathrm{C},\) what is the frequency of the sound heard by a person on the boat when the boat's displacement from the dock is \(+45.0 \mathrm{m} ?\)

A typical adult ear has a surface area of \(2.1 \times 10^{-3} \mathrm{m}^{2}\). The sound intensity during a normal conversation is about \(3.2 \times 10^{-6} \mathrm{W} / \mathrm{m}^{2}\) at the listener's ear. Assume that the sound strikes the surface of the ear perpendicularly. How much power is intercepted by the ear?

The tension in a string is \(15 \mathrm{N}\), and its linear density is \(0.85 \mathrm{kg} / \mathrm{m}\). A wave on the string travels toward the \(-x\) direction; it has an amplitude of \(3.6 \mathrm{cm}\) and a frequency of \(12 \mathrm{Hz}\). What are the (a) speed and (b) wavelength of the wave? (c) Write down a mathematical expression (like Equation 16.3 or 16.4 ) for the wave, substituting numbers for the variables \(A, f,\) and \(\lambda\)

A monatomic ideal gas \((\gamma=1.67)\) is contained within a box whose volume is \(2.5 \mathrm{m}^{3} .\) The pressure of the gas is \(3.5 \times 10^{s} \mathrm{Pa}\). The total mass of the gas is \(2.3 \mathrm{kg}\). Find the speed of sound in the gas.

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