/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 101 The sound intensity level at a r... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The sound intensity level at a rock concert is \(115 \mathrm{dB},\) while that at a jazz fest is 95 dB. Determine the ratio of the sound intensity at the rock concert to the sound intensity at the jazz fest.

Short Answer

Expert verified
The sound intensity at the rock concert is 100 times greater than at the jazz fest.

Step by step solution

01

Understanding Sound Intensity Level

The sound intensity level in decibels (dB) is given by the formula \( L = 10 \log_{10} \left( \frac{I}{I_0} \right) \), where \( I \) is the sound intensity and \( I_0 \) is the reference intensity, typically \( 10^{-12} \; \text{W/m}^2 \).
02

Setting Up the Equations for Both Sound Intensities

For the rock concert: \( L_1 = 115 \; \text{dB} = 10 \log_{10} \left( \frac{I_1}{I_0} \right) \). For the jazz fest: \( L_2 = 95 \; \text{dB} = 10 \log_{10} \left( \frac{I_2}{I_0} \right) \).
03

Solving for Intensities

Rearrange both equations: \( \frac{I_1}{I_0} = 10^{L_1/10} \) and \( \frac{I_2}{I_0} = 10^{L_2/10} \). Thus, \( I_1 = I_0 \times 10^{11.5} \) and \( I_2 = I_0 \times 10^{9.5} \).
04

Calculating the Intensity Ratio

The ratio \( \frac{I_1}{I_2} = \frac{I_0 \times 10^{11.5}}{I_0 \times 10^{9.5}} = \frac{10^{11.5}}{10^{9.5}} = 10^{11.5 - 9.5} = 10^2 \).
05

Concluding the Calculation

The sound intensity at the rock concert is \( 10^2 = 100 \) times greater than that at the jazz fest.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Decibels
Decibels (dB) are the units used to measure the intensity of sound. The scale is named after Alexander Graham Bell. Decibels provide a way to express sound intensity levels relative to a reference level, which is a very faint sound that humans can barely hear. This reference intensity is typically set at \(10^{-12} \, \text{W/m}^2\).

The decibel scale is logarithmic. This means it measures relative differences rather than absolute values. Such a scale allows us to capture the vast range of human hearing in more manageable numbers.

For instance, the intensity level of normal conversation might be around 60 dB, while that of a rock concert can be over 100 dB. This difference in decibels reflects a much larger difference in actual sound intensity, which helps illustrate why using a logarithmic scale is so useful in practice.
Sound Intensity
Sound intensity refers to the amount of energy that a sound wave carries per unit area. It is a measure of how much sound power passes through a certain area and is expressed in watts per square meter (\(\text{W/m}^2\)).

In everyday situations, we rarely think about sound in terms of intensity directly; instead, we perceive loudness as how we interpret that intensity. However, understanding sound intensity is crucial for quantifying and comparing different sound sources. This understanding allows us to assess, for example, how much more powerful a sound at a rock concert is compared to that at a quieter event, like a jazz performance.

In the example from the exercise, the intensity at a rock concert was shown to be 100 times greater than that at a jazz festival, demonstrating how significantly sound intensity can vary between different environments.
Logarithmic Scale
A logarithmic scale is a nonlinear scale used when there is a large range of quantities. Such scales are used in many scientific fields, including acoustics, because they make it easier to manage data with a vast range of values.

When it comes to sound, the logarithmic scale is used to convert the ratio of sound intensities to decibels. The formula \( L = 10 \log_{10} \left( \frac{I}{I_0} \right) \) uses logarithms to calculate the sound intensity level. This is beneficial because the human ear perceives sound intensity logarithmically, not linearly.

Therefore, a logarithmic scale aligns well with our experience of hearing, allowing us to express large differences in intensity as smaller, more comprehensible numbers (like using decibels) instead of cumbersome figures. This is why an increase of 10 dB in sound level represents a tenfold increase in sound intensity, while an increase from 95 dB to 115 dB corresponds to a hundredfold increase in actual intensity.
  • A key feature of logarithmic scales is their ability to simplify comparisons and calculations of multiplicative factors.
  • This scale is particularly useful in demonstrating changes in quantities that increase exponentially.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A bird is flying directly toward a stationary bird-watcher and emits a frequency of \(1250 \mathrm{Hz} .\) The bird-watcher, however, hears a frequency of \(1290 \mathrm{Hz} .\) What is the speed of the bird, expressed as a percentage of the speed of sound?

Light is an electromagnetic wave and travels at a speed of \(3.00 \times 10^{8} \mathrm{m} / \mathrm{s} .\) The human eye is most sensitive to yellow-green light, which has a wavelength of \(5.45 \times 10^{-7} \mathrm{m} .\) What is the frequency of this light?

Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticeable, but upon reaching shore, they can rise up to the astonishing height of a six-story building. One tsunami, generated off the Aleutian islands in Alaska, had a wavelength of \(750 \mathrm{km}\) and traveled a distance of \(3700 \mathrm{km}\) in 5.3 h. (a) What was the speed (in \(\mathrm{m} / \mathrm{s}\) ) of the wave? For reference, the speed of a 747 jetliner is about \(250 \mathrm{m} / \mathrm{s} .\) Find the wave's (b) frequency and (c) period.

A water-skier is moving at a speed of \(12.0 \mathrm{m} / \mathrm{s}\). When she skis in the same direction as a traveling wave, she springs upward every \(0.600 \mathrm{s}\) because of the wave crests. When she skis in the direction opposite to the direction in which the wave moves, she springs upward every 0.500 s in response to the crests. The speed of the skier is greater than the speed of the wave. Determine (a) the speed and (b) the wavelength of the wave.

A rocket, starting from rest, travels straight up with an acceleration of \(58.0 \mathrm{m} / \mathrm{s}^{2} .\) When the rocket is at a height of \(562 \mathrm{m},\) it produces sound that eventually reaches a ground-based monitoring station directly below. The sound is emitted uniformly in all directions. The monitoring station measures a sound intensity \(I\). Later, the station measures an intensity \(\frac{1}{3} I .\) There are no reflections. Assuming that the speed of sound is \(343 \mathrm{m} / \mathrm{s}\) find the time that has elapsed between the two measurements.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.