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Consider a composite system made up of two spin \(\frac{1}{2}\) objects. For \(t<0\), the Hamiltonian does not depend on spin and can be taken to be zero by suitably adjusting the energy scale. For \(t>0\), the Hamiltonian is given by $$ H=\left(\frac{4 \Delta}{\hbar^{2}}\right) \mathbf{S}_{1} \cdot \mathbf{S}_{2} $$ Suppose the system is in \(|+-\rangle\) for \(t \leq 0\). Find, as a function of time, the probability for being found in each of the following states \(|++\rangle,|+-\rangle,|-+\rangle\), and \(|--\rangle\). a. By solving the problem exactly. b. By solving the problem assuming the validity of first-order time-dependent perturbation theory with \(H\) as a perturbation switched on at \(t=0\). Under what condition does (b) give the correct results?

Short Answer

Expert verified
Probabilities: - \\( |+-\rangle: \cos^2(\frac{2\Delta t}{\hbar})\\), - \\( |-+\rangle: \sin^2(\frac{2\Delta t}{\hbar})\\), - \\( |++\rangle, |--\rangle: 0\\). Perturbation is valid when \\( \Delta t / \hbar << 1\\).

Step by step solution

01

Understanding the Initial State

Initially, the system is in the state \(|+ -\rangle\). For \(t \leq 0\), the Hamiltonian is zero, meaning the system does not evolve in time. The basis states are \(|+ +\rangle, |+ -\rangle, |- +\rangle, |--\rangle\).
02

Writing the Hamiltonian for t > 0

For \(t > 0\), the Hamiltonian is given by \(H=\left(\frac{4 \Delta}{\hbar^{2}}\right) \mathbf{S}_{1} \cdot \mathbf{S}_{2}\). The dot product can be expressed using the identity \(\mathbf{S}_{1} \cdot \mathbf{S}_{2} = \frac{1}{2}(S^2 - S_1^2 - S_2^2)\). For two spin-\(\frac{1}{2}\) particles: \((S^2) |s, m\rangle = s(s+1)\hbar^2 |s, m\rangle\), where \(s\) is the total spin quantum number.
03

Calculate Using the Total Spin Eigenstates

The possible total spin quantum numbers are \(s=1\) and \(s=0\). Change the basis to total spin states: triplet \(\{ |1,1\rangle=|++\rangle, |1,0\rangle=\frac{1}{\sqrt{2}}(|+-\rangle + |-+\rangle), |1,-1\rangle=|--\rangle \}\) and singlet \(\{ |0,0\rangle=\frac{1}{\sqrt{2}}(|+-\rangle - |-+\rangle) \}\).
04

Solving for Time Evolution

- At \(t=0\), \(|+-\rangle = \frac{1}{\sqrt{2}}(|1,0\rangle + |0,0\rangle)\).- Total spin basis: \(H|1, m\rangle = \tfrac{\Delta}{\hbar^2}|1, m\rangle\) and \(H|0,0\rangle = -\tfrac{3 \Delta}{\hbar^2}|0,0\rangle\).- The states evolve as: \[ |1, m\rangle(t) = e^{-i(\frac{\Delta t}{\hbar})}|1, m\rangle \] \[ |0,0\rangle(t) = e^{i(\frac{3 \Delta t}{\hbar})}|0,0\rangle \]
05

Return to Original Basis

Combine the time-evolved states: \[ |+-\rangle(t) = \frac{e^{-i(\frac{\Delta t}{\hbar})}}{\sqrt{2}}|1,0\rangle + \frac{e^{i(\frac{3 \Delta t}{\hbar})}}{\sqrt{2}}|0,0\rangle \]Convert back: \[ |+-\rangle(t) = \frac{1}{2}(e^{-i(\frac{\Delta t}{\hbar})} + e^{i(\frac{3 \Delta t}{\hbar})})|+-\rangle + \frac{1}{2}(e^{-i(\frac{\Delta t}{\hbar})} - e^{i(\frac{3 \Delta t}{\hbar})})|-+\rangle \]
06

Calculate the Probabilities

- The probability for \( |+-\rangle \) is \( P_{|+-\rangle}(t) = |\frac{1}{2}(e^{-i(\frac{\Delta t}{\hbar})} + e^{i(\frac{3 \Delta t}{\hbar})})|^2 = \cos^2(\frac{2\Delta t}{\hbar})\).- The probability for \( |-+\rangle \) is \( P_{|-+\rangle}(t) = |\frac{1}{2}(e^{-i(\frac{\Delta t}{\hbar})} - e^{i(\frac{3 \Delta t}{\hbar})})|^2 = \sin^2(\frac{2\Delta t}{\hbar})\).- The probability for \( |++\rangle \) and \( |--\rangle \) is \( P_{|++\rangle}(t) = P_{|--\rangle}(t) = 0\).
07

Use Time-Dependent Perturbation Theory

For time-dependent perturbation theory, assume \(H(t)=\theta(t)\hat{V}\) is a perturbation. The first-order probability amplitude is \( c_{f}^{(1)}(t) = -\frac{i}{\hbar}\int_{0}^{t}\langle f | \hat{V} | i \rangle e^{i\omega_{fi}t'} dt'\), mainly non-zero for first-order transitions. This simplifies to valid results when \( \Delta t / \hbar << 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spin-1/2 Systems
In quantum mechanics, a **spin-1/2 system** is one of the simplest types of quantum systems, which often involves particles like electrons. Spin, a fundamental property of particles, can be visualized as a type of intrinsic angular momentum. For spin-1/2 particles, this angular momentum can exist in one of two possible states: **up** \((|+\rangle)\) or **down** \((|-\rangle)\). This binary nature is akin to a classical bit and forms the foundation of quantum computing as a **qubit**.
  • These particles obey the Pauli exclusion principle, restricting them to unique quantum states in a system.
  • The mathematics of spin involves Pauli matrices, which describe rotations and other transformations.
  • In a composite system of two spin-1/2 particles, like in the exercise, the combined system has four possible states: \(|++\rangle, |+-\rangle, |-+\rangle,\) and \(|--\rangle\).

This simplicity makes spin-1/2 systems an essential model for learning about more complex quantum systems. Notably, its discrete state space allows clear demonstrations of quantum entanglement and superposition, which are key phenomena in quantum mechanics.
Hamiltonian Dynamics
The **Hamiltonian** is a critical concept in both classical and quantum mechanics, essentially acting as the generator of time evolution in a system. In our context, the Hamiltonian determines how the quantum state of the system evolves over time. For a system of spin-1/2 particles, the Hamiltonian may involve interactions terms in the form of spin operators, which capture the coupling between different particles.
In the original exercise:
  • The Hamiltonian for \(t > 0\) is given by \(H=\left(\frac{4 \Delta}{\hbar^{2}}\right) \mathbf{S}_{1} \cdot \mathbf{S}_{2}\).
  • This indicates a coupling between the spins of the two particles, where \(\mathbf{S}_{1}\) and \(\mathbf{S}_{2}\) are spin operators for particles 1 and 2, respectively.
  • Using the identity \(\mathbf{S}_{1} \cdot \mathbf{S}_{2} = \frac{1}{2}(S^2 - S_1^2 - S_2^2)\), it's clear that the system's energy depends on the total configuration of spins.

The eigenvalues of the Hamiltonian correspond to possible energy levels of the system. Understanding these dynamics allows physicists to predict the behavior of quantum systems under various forces, interactions, and transformations.
Quantum State Evolution
**Quantum state evolution** concerns how quantum states change over time, driven by the system's Hamiltonian. Initially, for \(t \leq 0\), there is no evolution because the Hamiltonian is zero. However, when \(t > 0\), the system described evolves under this Hamiltonian influence.
Key aspects in quantum state evolution:
  • The time-dependent Schrödinger equation governs the evolution of quantum states: \(i\hbar \frac{d}{dt} |\psi(t)\rangle = H|\psi(t)\rangle\).
  • For the given problem, the total spin states \(|1, m\rangle\) and the singlet state \(|0,0\rangle\) evolve as \(|1, m\rangle(t) = e^{-i(\frac{\Delta t}{\hbar})}|1, m\rangle\) and \(|0,0\rangle(t) = e^{i(\frac{3 \Delta t}{\hbar})}|0,0\rangle\).
  • These transformations show how initial quantum states change into superpositions of base states due to interactions defined in the Hamiltonian.

This time dependence is crucial for determining the probability of finding the system in any given state at a later time. These probabilities, calculated by taking the absolute square of the state's amplitude, help predict physical phenomena like saturation and oscillation effects in quantum systems.

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Most popular questions from this chapter

A one-electron atom whose ground state is nondegenerate is placed in a uniform electric field in the \(z\)-direction. Obtain an approximate expression for the induced electric dipole moment of the ground state by considering the expectation value of ez with respect to the perturbed state vector computed to first order. Show that the same expression can also be obtained from the energy shift \(\Delta=-\alpha|\mathbf{E}|^{2} / 2\) of the ground state computed to second order. (Note: \(\alpha\) stands for the polarizability.) Ignore spin.

Consider a particle bound in a simple harmonic oscillator potential. Initially \((t<0)\), it is in the ground state. At \(t=0\) a perturbation of the form $$ H^{\prime}(x, t)=A x^{2} e^{-t / \tau} $$ is switched on. Using time-dependent perturbation theory, calculate the probability that, after a sufficiently long time \((t \gg \tau)\), the system will have made a transition to a given excited state. Consider all final states.

A diatomic molecule can be modeled as a rigid rotor with moment of inertia \(I\) and an electric dipole moment \(d\) along the axis of the rotor. The rotor is constrained to rotate in a plane, and a weak uniform electric field \(\mathscr{E}\) lies in the plane. Write the classical Hamiltonian for the rotor, and find the unperturbed energy levels by quantizing the angular- momentum operator. Then treat the electric field as a perturbation, and find the first nonvanishing corrections to the energy levels.

Consider a one-dimensional simple harmonic oscillator whose classical angular frequency is \(\omega_{0}\). For \(t<0\) it is known to be in the ground state. For \(t>0\) there is also a time-dependent potential $$ V(t)=F_{0} x \cos \omega t $$ where \(F_{0}\) is constant in both space and time. Obtain an expression for the expectation value \(\langle x\rangle\) as a function of time using time- dependent perturbation theory to lowest nonvanishing order. Is this procedure valid for \(\omega \simeq \omega_{0} ?\)

Consider an isotropic harmonic oscillator in two dimensions. The Hamiltonian is $$ H_{0}=\frac{p_{x}^{2}}{2 m}+\frac{p_{y}^{2}}{2 m}+\frac{m \omega^{2}}{2}\left(x^{2}+y^{2}\right) $$ a. What are the energies of the three lowest-lying states? Is there any degeneracy? b. We now apply a perturbation $$ V=\delta m \omega^{2} x y $$ where \(\delta\) is a dimensionless real number much smaller than unity. Find the zerothorder energy eigenket and the corresponding energy to first order [that is, the unperturbed energy obtained in (a) plus the first-order energy shift] for each of the three lowest-lying states. c. Solve the \(H_{0}+V\) problem exactly. Compare with the perturbation results obtained in (b).

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