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Consider a particle bound in a simple harmonic oscillator potential. Initially \((t<0)\), it is in the ground state. At \(t=0\) a perturbation of the form $$ H^{\prime}(x, t)=A x^{2} e^{-t / \tau} $$ is switched on. Using time-dependent perturbation theory, calculate the probability that, after a sufficiently long time \((t \gg \tau)\), the system will have made a transition to a given excited state. Consider all final states.

Short Answer

Expert verified
The probability of transition to each state is \( P_n = |c_n(\infty)|^2 \), calculated for all \( n \).

Step by step solution

01

Define Perturbation Theory Framework

The starting point is the time-dependent perturbation theory, which analyzes how a small time-dependent change in a system's Hamiltonian affects the system's quantum states. In this case, we define the nominal Hamiltonian of the harmonic oscillator as \( H_0 = \frac{p^2}{2m} + \frac{1}{2} m \omega^2 x^2 \) and the time-dependent perturbation introduced is \( H'(x,t)=A x^{2} e^{-t / \tau} \).
02

Use Transition Amplitude Formula

For a system initially in the ground state \(|0\rangle\), the probability amplitude for a transition to an excited state \(|n\rangle\) is given by first-order time-dependent perturbation theory as \( c_n(t) = -\frac{i}{\hbar} \int_0^t \langle n | H'(t') | 0 \rangle e^{i \omega_{n0} t'} dt' \). Here, \( \omega_{n0} = \frac{E_n - E_0}{\hbar} \).
03

Calculate Matrix Elements

The matrix element \( \langle n | H'(t') | 0 \rangle = A e^{-t'/\tau} \langle n | x^2 | 0 \rangle \) needs to be calculated. For a simple harmonic oscillator, this becomes \( \langle n | x^2 | 0 \rangle = \frac{\hbar}{2m\omega} (\sqrt{n(n-1)}\delta_{n,n-2} + \sqrt{(n+1)(n+2)}\delta_{n,n+2} + (2n+1)\delta_{n,n}) \).
04

Evaluate the Integral

The integral for \( c_n(t) \) becomes \( c_n(t) = -\frac{iA}{\hbar} \langle n | x^2 | 0 \rangle \int_0^t e^{(i \omega_{n0} - 1/\tau) t'} dt' \). This evaluates to \( c_n(t) = -\frac{iA}{\hbar} \langle n | x^2 | 0 \rangle \cdot \frac{1 - e^{(i \omega_{n0} - 1/\tau) t}}{i \omega_{n0} - 1/\tau} \).
05

Consider the Limit \( t \gg \tau \)

As \( t \rightarrow \infty \), the exponential term \( e^{(i \omega_{n0} - 1/\tau) t} \) vanishes. The transition amplitude simplifies to \( c_n(\infty) = -\frac{iA}{\hbar} \langle n | x^2 | 0 \rangle \cdot \frac{1}{i \omega_{n0} - 1/\tau} \).
06

Find the Transition Probability

The probability of transition to state \( |n\rangle \) is \( P_n = |c_n(\infty)|^2 = \left( \frac{A |\langle n | x^2 | 0 \rangle|}{\hbar (\omega_{n0}^2 + 1/\tau^2)^{1/2}} \right)^2 \). Sum over all \( n \) to find the total transition probability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum State Transitions
Quantum state transitions describe the process by which a quantum system changes from one energy state to another. This is a crucial topic in quantum mechanics, particularly in understanding phenomena at the atomic and molecular levels. When a system is subjected to a time-dependent perturbation, it can transition between different quantum states. In our exercise, the system initially starts in the ground state and can transition to excited states over time due to the perturbing potential applied.In time-dependent perturbation theory, the probability of a transition between the initial and final states is computed using the probability amplitude. The amplitude for the transition from the initial ground state \(|0\rangle\) to an excited state \(|n\rangle\) is expressed as:\[ c_n(t) = -\frac{i}{\hbar} \int_0^t \langle n | H'(t') | 0 \rangle e^{i \omega_{n0} t'} dt'\]where \(\omega_{n0}\) is the angular frequency difference between the initial and final states. The calculation allows us to determine the likelihood of each possible transition.Some important points to consider:
  • State transitions require energy differences usually provided by the perturbation.
  • The probability amplitude is crucial for predicting transition outcomes over time.
  • The mathematics captures how these transitions are less likely if the system's conditions deviate significantly from the resonant frequency.
Harmonic Oscillator Potential
A harmonic oscillator potential is a fundamental concept in physics, modeling systems with a restoring force proportional to displacement. In quantum mechanics, this potential is key to understanding particles in a quadratic potential field, like electrons in atoms or lattice vibrations in solids. Mathematically, it is given by,\[ H_0 = \frac{p^2}{2m} + \frac{1}{2} m \omega^2 x^2\]where \(p\) is momentum, \(m\) is mass, \(\omega\) is angular frequency, and \(x\) is position. This is known as the simple harmonic oscillator potential.Looking at our exercise, the oscillator starts in its ground state in this potential. Our perturbation component, \( H' = A x^{2} e^{-t/\tau}\), modifies this potential slightly over time, influencing the behavior of the quantum states.Key aspects about harmonic oscillators:
  • Serve as an essential approximation for many quantum systems, even beyond simple applications.
  • The energy levels are quantized, meaning states are discrete rather than continuous.
  • Because of its symmetry, calculations tend to be simpler compared to more complicated potentials.
Matrix Element Calculation
Matrix element calculations play a central role in quantum mechanics, often dictating the probability of transitions between quantum states under perturbations. The specific matrix elements of interest in our scenario are expressed as \( \langle n | x^2 | 0 \rangle \), which need to be determined for transition probability calculations.In this exercise, calculating this element involves evaluating the effect of the perturbation \( x^2 \) within the eigenstates of the harmonic oscillator. For a simple harmonic oscillator, the matrix element is:\[\langle n | x^2 | 0 \rangle = \frac{\hbar}{2m\omega} (\sqrt{n(n-1)}\delta_{n,n-2} + \sqrt{(n+1)(n+2)}\delta_{n,n+2} + (2n+1)\delta_{n,n})\]These calculations are integral in determining how different terms \(\delta_{n,m}\) select specific transitions, reflecting the rules by which state transitions are allowed or forbidden.Points to remember:
  • Matrix elements indicate the effect of perturbation on the system.
  • They are often symmetrically structured due to the properties of the harmonic oscillator.
  • Understanding values for specific \(n\) is critical for accurate predictions of quantum system behavior.

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Most popular questions from this chapter

A diatomic molecule can be modeled as a rigid rotor with moment of inertia \(I\) and an electric dipole moment \(d\) along the axis of the rotor. The rotor is constrained to rotate in a plane, and a weak uniform electric field \(\mathscr{E}\) lies in the plane. Write the classical Hamiltonian for the rotor, and find the unperturbed energy levels by quantizing the angular- momentum operator. Then treat the electric field as a perturbation, and find the first nonvanishing corrections to the energy levels.

Consider a two-level system with \(E_{1}0\) by exactly solving the coupled differential equation $$ i \hbar \dot{c}_{k}=\sum_{n=1}^{2} V_{k n}(t) e^{i \omega_{k n} t} c_{n} \quad(k=1,2) $$ b. Do the same problem using time-dependent perturbation theory to lowest nonvanishing order. Compare the two approaches for small values of \(\gamma\). Treat the following two cases separately: (i) \(\omega\) very different from \(\omega_{21}\) and (ii) \(\omega\) close to \(\omega_{21}\). Answer for (a): (Rabi's formula) $$ \begin{aligned} &\left|c_{2}(t)\right|^{2}=\frac{\gamma^{2} / \hbar^{2}}{\gamma^{2} / \hbar^{2}+\left(\omega-\omega_{21}\right)^{2} / 4} \sin ^{2}\left\\{\left[\frac{\gamma^{2}}{\hbar^{2}}+\frac{\left(\omega-\omega_{21}\right)^{2}}{4}\right]^{1 / 2} t\right\\} \\ &\left|c_{1}(t)\right|^{2}=1-\left|c_{2}(t)\right|^{2} \end{aligned} $$

(Merzbacher (1970), p. 448 , Problem 11.) For the He wave function, use $$ \psi\left(\mathbf{x}_{1}, \mathbf{x}_{2}\right)=\left(Z_{\mathrm{eff}}^{3} / \pi a_{0}^{3}\right) \exp \left[\frac{-Z_{\mathrm{eff}}\left(r_{1}+r_{2}\right)}{a_{0}}\right] $$ with \(Z_{\text {eff }}=2-\frac{5}{16}\), as obtained by the variational method. The measured value of the diamagnetic susceptibility is \(1.88 \times 10^{-6} \mathrm{~cm}^{3} / \mathrm{mole}\). a. Using the Hamiltonian for an atomic electron in a magnetic field, determine, for a state of zero angular momentum, the energy change to order \(B^{2}\) if the system is in a uniform magnetic field represented by the vector potential \(\mathbf{A}=\frac{1}{2} \mathbf{B} \times \mathbf{x}\). b. Defining the atomic diamagnetic susceptibility \(\chi\) by \(E=-\frac{1}{2} \chi B^{2}\), calculate \(\chi\) for a helium atom in the ground state and compare the result with the measured value.

A one-dimensional simple harmonic oscillator of angular frequency \(\omega\) is acted upon by a spatially uniform but time-dependent force (not potential) $$ F(t)=\frac{\left(F_{0} \tau / \omega\right)}{\left(\tau^{2}+t^{2}\right)}, \quad-\infty

Consider a particle bound to a fixed center by a spherically symmetric potential \(V(r)\). a. Prove $$ |\psi(0)|^{2}=\left(\frac{m}{2 \pi \hbar^{2}}\right)\left\langle\frac{d V}{d r}\right\rangle $$ for all \(s\) states, ground and excited. b. Check this relation for the ground state of a three-dimensional isotropic oscillator, the hydrogen atom, and so on. (Note: This relation has actually been found to be useful in guessing the form of the potential between a quark and an antiquark. See Moxhay and Rosner, J. Math. Phys., 21 (1980) 1688.)

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