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The average intensity of an electromagnetic wave is , where E0 is the amplitude of the electric field portion of the wave. Find a general expression for the photon flux in terms of E0 and wavelength .

Short Answer

Expert verified

The general expression for the photons flux in terms of and E0 will be given asj=0E022h

Step by step solution

01

Step-1: Calculation of average intensity of an electromagnetic wave.

To find an expression for the photon flux j (number of photons/s.m2), the average intensity of an electromagnetic wave will be required,

I=120cE02鈥︹赌︹赌︹赌︹赌..(1)

Here E0 electric field intensity, I is the intensity of light, c is the speed of light in the vacuum, and 0is the permittivity of free space

The intensity of light can be written as:

I=PA鈥︹赌︹赌........鈥︹赌..(2)

The general equation for power,

P=Et鈥︹赌︹赌︹赌︹赌︹赌︹赌︹赌(2)

Here, P is the power, E is the energy and t is the time.

Energy E of a photon of wavelength can be written as:-

E=hc

Here, h is the Plank鈥檚 constant, and c is the speed of light in the vacuum.

02

Step-2: Derivation of the final formula

Substitute value from equation (2) into equation (1), and we get,

PA=120CE02

Substitute value from equation (3) into the above expression and we get,

EtA=120CE02EAt=120CE02

Here, E is the energy of the photons.

03

Step-3: Final Formula

The total energy will be n times the energy of each photon, where n is the number of photons. So the expression for total energy En is given by:-

En=nhc=nhc

Expression for total energy:

EnAt=120CE02

Substituting En=nhcin the above expression and we get

1Atnhc=120cE02nhc=120cE02nhAt=120E02nAt=0E022h

Therefore, the expression for the photon flux j is given by j==0E022h.

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