91影视

The given data can be listed below as,

The wavelength of X-rays is$位=0.057nm$.

The wavelength of scattered electrons is $位\text{'}=0.061nm.$.

The direction of the scattering of photons will be evaluated by using the concept of Compton鈥檚 scattering. The relation between the scattering angle and the wavelength change is a direct linear one.

The relation of Compton scattering is expressed as,

${位}^{\text{'}}-位=\frac{h}{m_{e}c}(1-\cos 胃)$

Here, $胃$is the direction of the scatter of photon, $m_e$ is the mass of an electron whose value is $9.1脳{10}^{-31}鈥�kg$,$h$is the Plank鈥檚 constant whose value is $6.63脳{10}^{-34}J鈰�s$and $c$ is the light speed in vacuum whose value i .

Substitute all the known values in the above equation.

$$\begin{gathered} (0.061\mathrm{nm}-0.057\mathrm{nm})脳\left(\frac{{10}^{-9}\mathrm{m}}{1\mathrm{nm}}\right)=\frac{\left(6.63脳{10}^{-34}\mathrm{J}路\mathrm{s}\right)}{\left(9.1脳{10}^{-31}\mathrm{kg}\right)\left(3脳{10}^8\mathrm{m}/\mathrm{s}\right)}(1-\cos 胃) \\ \left(4脳{10}^{-12}\mathrm{m}\right)=\left(2.43脳{10}^{-12}\mathrm{J}路{\mathrm{s}}^2/\mathrm{kg}路\mathrm{m}\right)\left(\frac{1\mathrm{m}}{1\mathrm{J}路{\mathrm{s}}^2/\mathrm{kg}路\mathrm{m}}\right)(1-\cos 胃) \\ (1-\cos 胃)=1.646 \\ 胃=134.{24}^{掳} \end{gathered}$$

Thus, the direction of scatter of photon is $134.{24}^{掳}$

The electron will move straight ahead after the collision, since it has acquired some of the forward linear momentum from the photon. The direction of the scattering of electrons would be along the horizontal direction.

Thus, the direction of the scattering of electrons would be along the horizontal direction.