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What wavelength of light is necessary to produce photoelectron of speed 2108mswith a magnesium target?

Short Answer

Expert verified

The wavelength of light necessary to produce photoelectron of speed 2108ms with a magnesium target is 82.5鈥塶尘.

Step by step solution

01

Converting into joules.

The energy of the photon is, E=hc . The Kinetic energy of the photon from the zinc plate is given by: KEmax=E- Here is the work function.

Now reforming the expression, we have,

=hc12尘位2+f

Because magnesium's work function potential is 3.7 eV, it must first be converted to Joules:

(3.7eV)1.61014鈥塉1鈥塩痴=5.921011J

02

Determine the value of wavelength.

Substituting the value to calculate the value of wavelength,

=(6.631014鈥塉蝉)3102ms12(9.11013鈥塳驳)2106ms2+5.921017鈥塉=8.25108鈥尘=82.5nm

Hence the value of wavelength is 82.5 nm.

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