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From equations (3-4) to (3-6) obtain equations (3.8). It is easiest to start by eliminating 蠁 between equations (3-4) and (3-5) using cos2蠁+蝉颈苍2蠁 = 1 The electron speed u may then be eliminated between the remaining equations.

Short Answer

Expert verified

Using the given equations, the following can be obtained is '-=hmec1-cos.

Step by step solution

01

Given data

h=h'cos+umeucos..(1)0=h'sin-umeusin..(2)hc-mec2=hc'+umec2..(3)

02

Concept  used

Einstein's mass-energy equivalence relation can be expressed as,

E = mc2

03

Use the equations and solve

Rearranging the above equations (1 and 2) will give:

umeucos=h-h'cosumeusin=h'sin

Squaring both will give:

umeu2cos2=h-h'cos2umeu2sin2=h'sin2

Adding both equations will lead to:

umeu2=h2-2h2'cos+h'2鈥..(4)

The Square of equation 3 will give

umeu2=h2+h2-2h2'+2mech-h'+me2c2鈥..(5)

04

Subtract equation 5 from equation 4

Simplify further,

me2u2c2-u2c2=-2h2'1-cos+2mech'-h+mec22h2'1-cos=2mech'-hh'1-cos=mec1'-1-'=hmec1-cos

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