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Obtain equation (9- 15) from (9-14). Make use or the following sums, correct when |x|<1 :

∑n=0∞xn=11-x∑n=0∞nxn=x(1-x)2

Short Answer

Expert verified

Equation E¯=∑n=0∞nhӬ0e-mӬ0kBT∑n=0∞emhӬ0kBT simplifies to equation E¯=hӬ0ehӬ0kBT-1

Step by step solution

01

Average Energy. 

Let us consider the expression for the average energy:

E¯=∑n=0∞nhӬ0e-nhӬ0kBT∑n=0∞e-nhӬ0kBT

Performing some minor modifications, we have:

E¯=hӬ0∑n=0∞ne-nhӬ0kBT∑n=0∞e-nhӬ0kBT

E¯=∑n=0∞nhӬ0e-nhӬ0kBT∑n=0∞e-nhӬ0kBT

02

Properties

Making use of the propertyx=e-hÓ¬0kBT.

∑n=0∞xn=11-x⇒∑n=0∞[e-hӬ0kBT]n=11-e-hӬ0kBT

And,

∑n=0∞nxn=x(1-x)2⇒∑n=0∞n[e-hӬ0kBT]n=e-hӬ0kBT(1-e-hӬ0kBT)2

03

Final Average Energy.

E¯=hӬ0e-hӬ0kBT(1-e-hӬ0kBT)2 11-e-hӬ0kBT=hӬ0e-hӬ0kBT1-e-hӬ0kBT=hӬ0(ehӬ0kBT)(1-e-hӬ0kBT)=hӬ0ehӬ0kBT-(ehӬ0kBT)(e-hӬ0kBT)=hӬ0ehӬ0kBT-1

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