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Chapter 11: Q64E (page 520)

If all the nuclei in a pure sample of uranium-235 were to fission, yielding about 200 MeV each. What is the kinetic energy yield in joules per kilogram of fuel?

Short Answer

Expert verified

Kinetic energy isE=832脳1011J/kg

Step by step solution

01

Finding N is the number of uranium atoms.

We need to find the kinetic energy per kilogram of uranium-235 that is used as a fuel. It has about 200 MeV energy.

The total kinetic energy E in this fission process is calculated using the formula:

E=NQ

Here, Q is the energy released in the process, and N is the number of uranium atoms.

First, we will find N is the number of uranium atoms:

mM=N

Here, m is carbon mass, and M is molecule mass.

By substituting numerical values, we have:

N=mMN0=1kg3.9脳10-23kgN0=2.6脳1024

02

By converting 200 MeV into J.

200MeV=200脳1.6脳10-13J=320脳10-13J

Finally, we can calculate the kinetic energy as:

role="math" localid="1658420259863" E=320脳10-13J脳2.6脳1024E=832脳1011J/kg

Therefore, Kinetic energy isE=832脳1011J/kg

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Most popular questions from this chapter

Ten milligrams of pure polonium-210 is placed in 500 g of water.If no heat is allowed to escape to the surroundings, how much will the temperature rise in 1 hour?

Given initially 40mg of radium-226 (one of the decay products of uranium-238), determine,

(a) The amount that will be left after 500years.

(b) The number of 伪 particles the radium will have emitted during this time, and

(c) The amount of kinetic energy that will have been released.

(d) Find the decay rate of the radium at the end of the 500 year.

Oxygen-19 尾- decays. What is the daughter nucleus, and what may be said of the kinetic energy of the emitted尾- particle?

Using the semiempirical binding energy formula estimate the mass of a europium- 152 atom.

The first two terms in the semi empirical binding energy formula deal solely with the internucleon attraction.

(a) Calculate the ratio of the second term to first term forA=20 . What does it say about the surface nucleons?

(b) Repeat part (a), but forA=220 .
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