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Chapter 11: Q65E (page 520)

(a) To release 100 MW of power, approximately how many uranium fissions must occur every second?

(b) How many kilograms of U-235 would have to fission in 1 year?

Short Answer

Expert verified

(a)NY=9.859脳1025decays/year

(b)M=38.5kg

Step by step solution

01

Given data

Given that the power released by the fission reaction is :

P=100MW=100脳106W

Then energy is:

Q=200MeV=200脳1.6脳10-13J=320脳10-13J

02

Find the Number of uranium-235 fissions that will occur

(a)

The Number of fission required for the release of 100 MW of energy is:

N=PQ=108W320脳10-13J=3.12脳1018decays/second

Let's calculate the Number of fission that would happen in a year,

Ny=N脳3.16脳107=9.859脳1025decays/year

Therefore, the Number of fission will be NY= 9.859脳1025decays/year.

03

Finding the Mass of uranium-235.

Mass of uranium-235 that would be decayed to release the power of 100 MeV for a year is:

M=NY脳mUr235=9.89脳1025脳235u脳1.66脳10-27kg/u=38.5kg

Thus, the Mass of the uranium is38.5kg .

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