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Chapter 12: Q42E (page 557)

Sketch the Feynman diagram if the proposed decay is possible.

蟺0鈫�渭-+v炉渭

Short Answer

Expert verified

The proposed decay is not possible.

Step by step solution

01

Given data

The proposed reaction is 蟺0鈫�渭-+v炉渭

02

Concept of Feynman diagram

A Feynman diagram is drawn to express the particle interaction in nature.

03

 Step 3:Find conservation of energy

The conservation of energy is shown below:

蟺0鈫�渭-+v炉渭135MeV鈫�106MeV

The energy 106MeV after the decay is less than the energy 135MeV before the decay.

04

 Step 4: Find conservation of lepton numbers

Conservation of Leptons is given below:

蟺0鈫�渭-+v炉渭(0)鈫�(+1)+(-1)

Thus, the leptons number before the decay is equal to the leptons number after the decay.

Therefore, the Leptons number is conserved.

05

Find conservation of charge

Conservation of charge is:

蟺0鈫�渭-+v炉渭(0)鈫�(-e)+(0)(0)鈫�(-e)

Thus, the charge before the decay and after the decay isnot equal, which implies that the charge is not conserved.

Therefore, this decay reaction is not possible.

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Most popular questions from this chapter

For which particles does table 12.2 showboth particles and anti-particles?Which particles are their own antiparticles?

In the following exercises, two protons are smashed together in an attempt to convert kinetic energy into mass and new particles. Indicate whether the proposed reaction is possible. If not, indicate which rules are violated. Consider only those for charge, angular momentum, and baryon number If the reaction is possible, calculate the minimum kinetic energy required of the colliding protons.

p+p鈫�n+n炉+p+p炉

In the following exercises, two protons are smashed together in an attempt to convert kinetic energy into mass and new particles. Indicate whether the proposed reaction is possible. If not, indicate which rules are violated. Consider only those for charge, angular momentum, and baryon number If the reaction is possible, calculate the minimum kinetic energy required of the colliding protons.

p+p鈫�p+K+

Sketch the Feynman diagram if the proposed decay is possible.

螖+鈫�危++蟺0+纬

To show,

(a) 唯1(x,t)=Aeikx鈭�i蝇tis the solution of both Klein-Gordon and the Schrodinger equations.

(b) 唯2(x,t)=Aeikxcos蝇tis the solution of both Klein-Gordon but not the Schrodinger equations.

(c) The唯2 is a combination of positive and negative energy solutions of the Klein-Gordon equation.

(d) To compare the time dependence of唯2 for 唯1and 唯2.
See all solutions

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