91影视

The proposed reaction is ${螖}^{+}鈫�{危}^{+}+{蟺}^0+纬$

A Feynman diagram is drawn to express the particle interaction in nature.

Conservation of charge is shown below:

$$\begin{gathered} {螖}^{+}鈫�{危}^{+}+{蟺}^0+纬 \\ (+e)鈫�(+e)+\left(0\right)+\left(0\right) \\ (+e)鈫�(+e) \end{gathered}$$

Thus, the charge before the decay and after the decay is equal.

Therefore, the charge is conserved.

Conservation of baryons number is given below:

$$\begin{gathered} {螖}^{+}鈫�{危}^{+}+{蟺}^0+纬 \\ (+1)鈫�(+1)+\left(0\right)+\left(0\right) \\ (+1)鈫�(+1) \end{gathered}$$

Thus, the baryons number before the decay is equal to the baryons number after the decay.

Therefore, the baryons' number is conserved.

Conservation of energy:

$$\begin{gathered} {螖}^{+}鈫�{危}^{+}+{蟺}^0+纬 \\ (1232{\text{MeV/c}}^2)鈫�(1232{\text{MeV/c}}^2)+(135{\text{MeV/c}}^2) \\ 1232{\text{MeV/c}}^2鈫�1367{\text{MeV/c}}^2 \end{gathered}$$

The energy $1232\text{MeV}$ before the decay is less than the energy $1367\text{MeV}$ that alters the decay.

Thus, energy conservation is violated.From the above results, we conclude that the decay reaction is not possible.

The proposed decay is not possible.