/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 Two children \(A\) and \(B\) use... [FREE SOLUTION] | 91Ó°ÊÓ

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Two children \(A\) and \(B\) use bicycles, having wheels of ring type and disc type respectively. During a race, bicycles are given the same velocity from the bottom of the inclined bridge to ascend the bridge without pedalling, then (assuming pure rolling). (1) both bicycles with reach up to same height (2) bicycle of child \(A\) will reach a greater height (3) bicycle of child \(B\) will reach a greater height (4) depends on the masses of bicycles and the child

Short Answer

Expert verified
Bicycle of child B will reach a greater height due to its disc wheels.

Step by step solution

01

Understanding the Situation

When the bicycles start ascending the inclined bridge, they are given the same initial velocity. As they ascend, they will convert their kinetic energy into potential energy until they stop at the maximum height.
02

Identifying the Types of Bicycle Wheels

Child A's bicycle has wheels of ring type, and child B's bicycle has wheels of disc type. This means they have different moments of inertia, which affects their rotational energy.
03

Calculating the Initial Energies

For both bicycles, the initial energy is their total kinetic energy, given by:\[ K.E. = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 \]where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. Using the relation \(v = r\omega\), we have for a ring \(I = mr^2\) and for a disc \(I = \frac{1}{2}mr^2\).
04

Analyzing the Potential Energies at Maximum Height

At maximum height, the kinetic energy is converted into potential energy:\[ P.E. = mgh \]For both bicycles, the total mechanical energy is conserved. However, due to the difference in moments of inertia, their initial rotational kinetic energies will differ, affecting the height they reach.
05

Comparing the Heights Reached

Since the disc has a smaller moment of inertia compared to the ring, it retains more translational kinetic energy when rolling. Thus, it can convert more energy into height, allowing it to reach a greater height than the ring.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
When the two bicycles start their journey up the inclined bridge, they rely solely on kinetic energy for movement. Kinetic energy is the energy of motion, calculated using the formula:
  • Translational kinetic energy: \( \frac{1}{2}mv^2 \)
  • Rotational kinetic energy: \( \frac{1}{2}I\omega^2 \)
For the bicycles, both types of kinetic energies are significant. Since both have the same initial velocity, their translational kinetic energy is identical initially. However, the type of wheel greatly influences the rotational kinetic energy.
Child A rides a bicycle with ring-type wheels, which have a larger moment of inertia. In contrast, Child B’s bicycle has disc-type wheels, which come with a smaller moment of inertia. This means Child A's wheels need more energy to spin, while Child B's machine is more efficient in conversion of energy which will play a pivotal role as they climb.
Potential Energy
As the bicycles climb the bridge, their kinetic energy transforms into potential energy. Potential energy, often due to height, is calculated using the equation:
  • \( P.E. = mgh \)
Potential energy depends on the height \( h \) reached, the mass \( m \) of the object or system, and gravitational acceleration \( g \). When the bicycles roll up the bridge without pedaling, they eventually stop at a maximum height where their kinetic energy has been fully converted to potential energy. At this point, their potential energy is at its maximum.
Since the total mechanical energy at the start and end of the climb remains constant, the initial kinetic energy of each bicycle directly determines how high each will go. This lays the foundation for understanding how different moments of inertia will change which climbs higher.
Mechanical Energy Conservation
The principle of mechanical energy conservation states that if no external forces do work, the total mechanical energy of a system remains constant. This is expressed as:
  • Initial Kinetic Energy = Final Potential Energy
For both bicycles, this principle applies as they ascend the bridge. Despite initial differences in energy distribution due to their differing wheel types, the total mechanical energy is still conserved.
Because the bicycle with disc wheels (Child B) converts more of its kinetic energy into height, due to a lower moment of inertia, it achieves a greater height relative to the ring wheels bicycle (Child A). This is a fundamental concept in understanding why different types of wheels impact the final outcomes like height reached.
Pure Rolling
Pure rolling occurs when there is no slipping between the wheel and surface, meaning the point of contact with the bridge has zero relative velocity. This ensures efficient energy conversion between kinetic and potential energy.
  • No energy is lost to friction as slip is absent.
  • The condition \(v = r\omega\) holds firmly, connecting linear and angular motion.
In the given problem, pure rolling is critical. It assumes all the energy transformations concern only kinetic and potential energy, following the conservation principles succinctly. Child B's bicycle, being more efficient due to disc wheels, uses pure rolling to its advantage by converting energy effectively, leading to a higher ascent. Understanding this aids comprehension of how different wheel specifications and conservation laws interact in energetic scenarios.

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Most popular questions from this chapter

A disc of mass \(M\) and radius \(R\) rolls without slipping on a A horizontal surface. If the velocity of its centre is \(v_{0}\), then the | toral angular momentum of the disc about a fixed point \(P\) at a height \(3 / 2 R\) above the centre \(C\) (1) increases continuously as the disc moves away (2) decreases continuously as the disc moves away (3) is equal to \(2 M R v_{0}\) (4) is equal to \(M R v_{0}\)

A disc is given an initial angular velocity \(\omega_{0}\) and placed on a rough horizontal surface as shown in figure. The quantities which will not depend on the coefficient of friction is/are (1) the time until rolling begins (2) the displacement of the disc until rolling begins (3) the velocity when rolling begins (4) the work done by the force of friction

A homogenous rod of length \(l=\eta x\) and mass \(M\) is lying on a smooth horizontal floor. A bullet of mass \(m\) hits the rod at a distance \(x\) from the middle of the rod at a velocity \(v_{0}\) perpendicular to the rod and comes to rest after collision. If the velocity of the farther end of the rod just after the impact is in the opposite direction of \(v_{0}\), then (1) \(\eta>3\) (2) \(\eta<3\) (3) \(\eta>6\) (4) \(\eta<6\)

An impulse \(J\) is applied on a ring of mass \(m\) along a line passing through its centre \(O\). The ring is placed on a rough horizontal surface. The linear velocity of centre of ring once it starts rolling without slipping is (1) \(\mathrm{J} / \mathrm{m}\) (2) \(J / 2 m\) (3) \(J / 4 m\) (4) \(J / 3 m\)

A sphere \(A\) moving with speed \(u\) and rotating with an angular velocity \(\omega\) makes a head-on elastic collision with an identical stationary sphere \(B\). There is no friction between the surfaces of \(A\) and \(B\). Choose the correct alternative(s). Disregard gravity. (1) \(A\) will stop moving but continue to rotate with an angular velocity \(\omega\). (2) \(A\) will come to rest and stop rotating. (3) \(B\) will move with speed \(u\) without rotating. (4) \(B\) will move with speed \(u\) and rotate with an angular velocity \(\omega\).

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