/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A sphere \(A\) moving with speed... [FREE SOLUTION] | 91Ó°ÊÓ

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A sphere \(A\) moving with speed \(u\) and rotating with an angular velocity \(\omega\) makes a head-on elastic collision with an identical stationary sphere \(B\). There is no friction between the surfaces of \(A\) and \(B\). Choose the correct alternative(s). Disregard gravity. (1) \(A\) will stop moving but continue to rotate with an angular velocity \(\omega\). (2) \(A\) will come to rest and stop rotating. (3) \(B\) will move with speed \(u\) without rotating. (4) \(B\) will move with speed \(u\) and rotate with an angular velocity \(\omega\).

Short Answer

Expert verified
Correct alternatives are (1) and (3).

Step by step solution

01

Analyze the Type of Collision

The problem describes a head-on elastic collision with no friction, which implies conservation of both linear momentum and kinetic energy, while rotation is unaffected due to lack of friction.
02

Apply Conservation of Linear Momentum

For elastic collisions involving two identical spheres where one is stationary, the moving sphere stops and the stationary sphere takes the entire velocity of the moving sphere. Thus, after the collision, sphere \(A\) will stop, and sphere \(B\) will move with speed \(u\).
03

Consider Rotational Motion

Since there is no friction, the rotational motion of each sphere is unaffected by the collision. Sphere \(A\) will continue to rotate with angular velocity \(\omega\), and sphere \(B\) will not gain any rotation.
04

Evaluate Each Statement

(1) Sphere \(A\) will stop moving but continue rotating with angular velocity \(\omega\) aligns with our analysis. (2) Sphere \(A\) will not stop rotating; this is incorrect. (3) Sphere \(B\) will move with speed \(u\) without rotating, which is correct. (4) Sphere \(B\) will not rotate with angular velocity \(\omega\); this is incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Linear Momentum
In physics, the principle of conservation of linear momentum states that if no external forces act on a system, the total momentum of the system remains constant. This is particularly evident in elastic collisions, where none of the kinetic energy or momentum is dissipated. Linear momentum is given by the product of mass and velocity, so in any collision, the sum of the momentum of all objects before the collision must equal the sum of the momentum of all objects after the collision.

In the exercise involving spheres A and B, sphere A initially has momentum since it is moving. When it collides with stationary sphere B, because no external force acts on the system and due to the nature of elastic collisions, sphere B picks up the entire velocity that sphere A had before impact. Consequently, sphere A stops moving, and sphere B moves forward at the same speed that A initially had. This showcases the conservation of linear momentum very clearly.

Remember:
  • Momentum before collision = Momentum after collision
  • For collisions of identical spheres, the moving sphere stops and the stationary sphere takes on its speed
Kinetic Energy
Kinetic energy in the context of motion is the energy that an object possesses due to its motion, which is derived from its mass and velocity. In elastic collisions, the total kinetic energy of the system is conserved, meaning it remains the same before and after the collision.

Mathematically, kinetic energy (KE) is expressed as \[ KE = \frac{1}{2} mv^2 \] where \( m \) is the mass of an object and \( v \) is its velocity.

In our example with spheres A and B, all the kinetic energy of sphere A is transferred to sphere B during the collision. As a result, sphere B moves with the same velocity \( u \), and sphere A comes to a stop, thus conserving the total kinetic energy of the system before and after the impact. This illustrates perfectly how kinetic energy behaves during elastic collisions.

Key Points:
  • Total kinetic energy is conserved in elastic collisions
  • Spheres trade speeds to maintain constant kinetic energy in a frictionless system
Rotational Motion
Rotational motion refers to the motion of a body around an internal axis. Unlike linear motion, which is affected by velocities in a straight line, rotational motion involves angular velocity, represented by \( \omega \). When analyzing elastic collisions, particularly those without friction, the rotational motion can be completely independent of the linear motion.

In the problem of the colliding spheres, sphere A not only moves but also rotates. Because there is no friction between the surfaces of spheres A and B, the rotational motion of sphere A is unaffected by the linear collision. This means that even after sphere A comes to rest concerning its linear motion, it continues to rotate with its original angular velocity \( \omega \). Sphere B, meanwhile, only picks up linear speed because there is no mechanism to transfer rotational energy between the spheres in the absence of friction.

Where rotational motion is concerned:
  • Without friction, rotation is unaffected in collisions
  • Each sphere's rotation stays as it was before the impact

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