/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 A disc is given an initial angul... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A disc is given an initial angular velocity \(\omega_{0}\) and placed on a rough horizontal surface as shown in figure. The quantities which will not depend on the coefficient of friction is/are (1) the time until rolling begins (2) the displacement of the disc until rolling begins (3) the velocity when rolling begins (4) the work done by the force of friction

Short Answer

Expert verified
The velocity when rolling begins may not depend on the coefficient of friction.

Step by step solution

01

Understanding the Problem

We need to determine which of the listed physical quantities are independent of the coefficient of friction. The disc is initially spinning and slides on a rough surface before it starts rolling without slipping.
02

Analyze Time Until Rolling Begins

Time until rolling begins can be influenced by the coefficient of friction because friction affects how quickly the disc slows down its spinning and sliding. Therefore, the time is typically dependent on the coefficient of friction.
03

Calculate Displacement Until Rolling Begins

Displacement refers to the distance the center of mass travels until rolling begins. Since friction affects the translational deceleration, the displacement will also typically depend on the coefficient of friction.
04

Evaluate Velocity When Rolling Begins

Velocity of the center of mass when rolling begins is related to the initial conditions and the need for the disc's angular velocity to satisfy the rolling condition \( v = r \omega \). Since rolling condition depends primarily on initial angular velocity and radius, it may be less affected by friction.
05

Assess Work Done by Friction

Work done by the force of friction depends directly on the displacement and friction force. Given friction is proportional to its coefficient and displacement is affected by it as well, friction affects the work done substantially.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Friction
The coefficient of friction is a key player when understanding how objects interact with surfaces. It's a measure of how much force of friction is present between a disc and a rough surface. In simple terms, it determines how slippery or sticky a surface feels.
  • A higher coefficient means more friction, causing objects to slow down faster.
  • A lower coefficient means less friction, allowing objects to move more easily.
Friction influences various aspects of a moving object, like how quickly it stops or how fast it rolls. In exercises involving motion, always check if you're asked to consider the role of friction. Calculations, such as the time and displacement until rolling begins, heavily depend on this friction coefficient. It is crucial because it modifies the forces that oppose the disc’s motion.
Rolling Motion
Rolling motion may sound complex, but it's quite straightforward. Imagine a disc or wheel that moves in a way that every point on its edge touches the ground only once during each full turn.Two main conditions are required to achieve rolling motion:
  • The velocity of the center, known as translational velocity, has to match the product of its radius and angular velocity: \(v = r \omega\).
  • Friction needs to be at a point where it just stops slipping without causing extra resistance.
When a disc transitions from sliding to rolling without slipping, it becomes very efficient in its movement. It is friction that initiates this change by equalizing the speeds of the center and edge, thereby inducing pure rolling. In practical tasks, note if the problem specifies rolling without slipping, as this influences the forces involved and simplifies calculations.
Kinetic Energy
Kinetic energy is a fascinating concept that involves both movement and speed. For a disc, it emerges in two forms: translational and rotational.
  • Translational kinetic energy is due to the movement of the disc’s center of mass. It's calculated by \(\frac{1}{2}mv^2\), where \(m\) is mass and \(v\) is velocity.
  • Rotational kinetic energy depends on how the disc spins around its center. It is determined by \(\frac{1}{2}I\omega^2\), with \(I\) being the moment of inertia and \(\omega\) being angular velocity.
Before rolling begins, both types of kinetic energy can change, primarily due to the frictional force. As sliding motion converts to rolling motion, some of the translational energy is converted into rotational energy. Understanding this exchange helps in deducing how and where energy is lost or transferred in physical systems.
Translational Motion
Translational motion is best visualized as a straight line path that the center of an object takes as it moves along a surface. In the context of the disc, before rolling begins, translational motion describes how the center of mass shifts forward. This type of motion is driven by forces like gravity and opposed by forces like friction. Translational motion is quantified by velocity and is influenced by factors such as mass and external forces placed upon the object. In exercises involving rolling, focus on how the translational speed of the disc changes over time. This is essential for solving for aspects like displacement and time before rolling starts. As the disc shifts from sliding to rolling, the friction helps match the speed of translation with the rotational speed, ensuring smooth rolling motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A particle falls freely near the surface of the earth. Consider a fixed point \(O\) (not vertically below the particle) on the ground. Then pick up the incorrect alternative. (1) Angular momentum of the particle about \(O\) is increasing. (2) The moment of inertia of the particle about \(O\) is decreasing. (3) The moment of inertia of the particle about \(O\) is increasing. (4) The angular velocity of the particle about \(O\) is increasing.

A solid iron sphere \(A\) rolls down an inclined plane, while an identical hollow sphere \(B\) of same mass slides down the plane in a frictionless manner. At the bottom of the inclined plane, the total kinetic energy of sphere \(A\) is (1) less than that of \(B\) (2) equal to that of \(B\) (3) more than that of \(B\) (4) sometimes more and sometimes less

A sphere is released on a smooth inclined plane from the top. When it moves down, its angular momentum is (1) conserved about every point (2) conserved about the point of contact only (3) conserved about the centre of the sphere only (4) conserved about any point on a line parallel to the inclined plane and passing through the centre of the ball

Two bodies with moments of inertia \(I_{1}\) and \(I_{2}\left(I_{1}>I_{2}\right)\) have equal angular momenta. If their kinetic energies of rotation \(\operatorname{are} E_{1}\) and \(E_{2}\), respectively, then (i) \(E_{1}=E_{2}\) (2) \(E_{1}E_{2}\) (4) \(E_{1} \geq E_{2}\)

A solid ball of mass \(m\) and radius \(r\) spinning with angular velocity \(\omega\) falls on a horizontal slab of mass \(M\) with rough upper surface (coefficient of friction \(\mu\) ) and smooth lower surface. Immediately after collision the normal component of velocity of the ball remains half of its value just before collision and it stops spinning. Find the velocity of the sphere in horizontal direction immediately after the impact \((\) given: \(R \omega=5\) ).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.