91Ó°ÊÓ

The given data is listed below as follows,

• The limb of the tree is at a distance from the ground is,$L$
• Initially, the height of the center of mass above the ground is,$h$
• The distance of feet above the ground is,$d$
• Finally, the height of the center of mass above the ground is,$b$
• The mass of the body of an individual is,$M$.

The net internal energy of an object is described as the product of the force of that object and the distance moved by the object.

Moreover, internal energy is described as the difference between the heat transfer and the work done by the system.

The equation of the net internal energy is expressed as:

$∆E_{int}=F.\left(h-b\right)$ …(¾±)

Here, F is the force exerted, h is the height of the center of mass above the ground initially and b the height of the center of mass above the ground finally.

The equation of the force is expressed as:

$F=M.g$

Here,$M$ is the mass of the body and g is the acceleration due to gravity.

Substitute the above value in equation (i).

$∆E_{int}=M.g.\left(h-b\right)$

Thus, the net internal change in energy is as$Mg\left(h-b\right)$.

According to the law of energy conservation, the final and the initial energy are the same.

The equation of the initial and the final energy is expressed as:

$Mgh=Mg\left(h-d\right)+\frac{1}{2}M{v}^2$

Here, M is the mass of the body,g is the acceleration due to gravity,h is the height of the center of mass above the ground initially,d is the distance of the feet above the ground and v is the instant speed of the body.

The above equation can be reduced as follows:

$$\begin{gathered} gh=g\left(h-d\right)+\frac{1}{2}{v}^2 \\ {v}^2=2gh-2gh+2gd \\ {v}^2=2gd \\ v=\sqrt{2gd} \end{gathered}$$

Thus, the instant speed is when feet touch the ground is $\sqrt{2gd}$.

The equation of the approximate average force is expressed as:

$F=\frac{Mg\left(h-b\right)}{\left(h-d-b\right)}$

Here,$M$is the mass of the body,$g$is the acceleration due to gravity, $h$is the height of the center of mass above the ground initially,$d$ is the distance of the feet above the ground and the height of the center of mass above the ground finally.

Thus, the approximate average force is$\frac{Mg\left(h-b\right)}{\left(h-d-b\right)}$ .

The work done by the force$F$ is equal to 0 due to the fact that the earth moves very less distance that is negligible, and hence there cannot be any work done.

Thus, the work done by the force exerted by the ground is 0 .