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A runner starts from rest and in3 sreaches a speed of . Assume that her speed changed at a constant rate (constant net force).

(a) What was her average speed during this 3 s interval?

(b) How far did she go in this 3 s interval?

Short Answer

Expert verified
  1. Average speed for the 3 s, vavg=4 m/²õ
  2. Distance travels=12 m .

Step by step solution

01

Identification of given data

  • Initial velocity vi=0.
  • Final velocity vf=8″¾/s.
  • Time t=3 s.
02

Average speed

Average speed is the ratio of distance traveled per unit of time.

03

Calculation of the average speed

(a) The average speed of an object is calculated by

a=vf−vit

Here, a = Acceleration , and t = Total time

a=83a=2.66 m/s

s=ut+12at2s=0×3 s+12×2.66 m/s×3 s2s=12 m

role="math" localid="1657104664252" v=stv=12 m3 s=4 m/²õ

The average speed will be 4 m/²õ.

04

Calculation for the distance travel

(b) See part a

The distance is traveled s=12 m.

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