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In a lab experiment you observe that a pendulum swings with a 鈥減eriod鈥 (time for one round trip) of 2s. In an iterative calculation of the motion, which of the following would NOT be a reasonable choice for t, for either hand or computer iterative calculations? a) 1sb) 0.1sc) 0.05sd) 0.01s.

Short Answer

Expert verified

d)0.01s is not a reasonable choice for t.

Step by step solution

01

Identification of the given data

The given data can be listed below as

  • A pendulum is referred to as a weight that is hung from a fixed end for swinging freely.

  • A constant force is applied to trigger the pendulum鈥檚 motion, which leads to imbalances in the equilibrium position of the pendulum.

  • The swing time of the pendulum is the time taken by the pendulum to reach its starting destination after a whole swing.

  • The pendulum swings at a period of 2s.

02

Determination of the unreasonable choice for the change in time

As the total period of the pendulum is 2s, the time0.01s will not be a reasonable choice for as this time is almost negligible for understanding the pendulum鈥檚 motion.

The other periods such as (a)1s, (b)0.01sand (c)0.05s can predict the time as the time is independent of the pendulum鈥檚 mass, plus these are not negligible. However, there are no devices that can predict the motion of a pendulum in this small amount of time, such as 0.01s.

Thus, d)0.01s is not a reasonable choice for t.

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