91Ó°ÊÓ

The given data can be listed below as:

• The mass of the heavy load is$\mathrm{m}=1200 \mathrm{kg}$ .
• The angle of the load is$\mathrm{θ}={90}^{∘}$ .
• The time taken for the blast is $\mathrm{t}=1.0 \mathrm{s}$.
• The force exerted on the blast is $F=20 N$.
• The initial distance moved by the load is$h_1=3 m$ .
• The final distance moved by the load is $h_2=4 m$.
• The starting point of the blast is$s_1=⟨0,0,0âŸ\copyright  m$ .
• The middle point of the blast is $s_2=⟨0,3,0âŸ\copyright  m$.
• The ending point of the blast is $s_3=⟨4,3,0âŸ\copyright  m$.

The average velocity is described as the division of the change in the displacement with the change in the time. Moreover, the average velocity is the average speed that has a particular direction.

It has been identified that the blast first occurs in the - y direction, then in the +x direction and finally, in the -x direction.

The equation of the time for scheduling the blast initially is expressed as:

$\mathrm{m}\frac{{\mathrm{s}}_2-{\mathrm{s}}_1}{{\mathrm{t}}_1}={\mathrm{p}}_1+{\mathrm{Ft}}_1$

Here, m is the mass of the heavy load, $s_2$is the middle point of the blast,$s_1$is the starting point of the blast, $p_1$is the initial momentum, F is the force exerted on the blast and $t_1$is the time taken to schedule the blast initially.

As initially the spaceship was at rest, then the initial velocity of the spaceship is zero.

Substitute the values in the above equation.

As one second is needed to produce the required force, then the time needed to fire the blast is 12.42 s .

The equation of the time for scheduling the blast finally is expressed as:

$\mathrm{m}\frac{{\mathrm{s}}_3-{\mathrm{s}}_2}{{\mathrm{t}}_2}={\mathrm{p}}_1+{\mathrm{Ft}}_2$

Here, m is the mass of the heavy load,$s_3$ is the final point of the blast,$s_2$ is the middle point of the blast,$p_1$ is the initial momentum, F is the force exerted on the blast and $t_2$is the time taken to schedule the blast finally.

As initially the spaceship was at rest, then the initial velocity of the spaceship is zero

.Substitute the values in the above equation.

The equation of the total time is expressed as:

$t=t_1+t_2$

Here, t is the total time.

Substitute the values in the above equation.

$$\begin{gathered} t=13.42s+15.49s \\ =28.91s \end{gathered}$$

As one second is needed to produce the required force, then the time needed to fire the blast is 27.91 s.\

Thus, the blast should be fired at 12.42 s in the -y direction,13.42 s in the +x direction and 27.91 s in the -x direction.

The entire move will require $28.91\mathrm{s}$.