91Ó°ÊÓ

The applied electric force is$F=1.6×{10}^{-13}\mathrm{N}$

The distance travelled by an electron is$d=2\mathrm{m}$

Generally, the travel speed of electron is $2200$kilometers per second. this speed is lower than the travel speed of light. But this speed of electron is fast enough to revolve around the earth in more than $18$seconds.

Here, the new speed of an electron is calculated by using mass-energy principle.

The principle of mass-energy,

$E=\mathrm{γ}m{c}^2...........\left(1\right)$

where,

mass of an electron $⇒9×{10}^{-31}\mathrm{kg}$

the speed of light in air $⇒3×{10}^8\mathrm{m}/\mathrm{s}$

$\mathrm{γ}=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}.......\left(a\right)$

$=\frac{1}{\sqrt{1-(0.95{)}^2}}$

Total Energy $E_{\text{total}}=E+W$........... (2) Where,

$E$= Energy

$W$= Work done by applied force

Using Equation (1), we can calculate Energy,

$$\begin{gathered} E=3.20×9×{10}^{-31}×{\left(3×{10}^8\right)}^2 \\ =2.59×{10}^{-13}J \end{gathered}$$

Work done is calculated by the following formula,

$W=F×d$

Where, $F=$Applied eletric force, role="math" localid="1657971421085" $d=$distance travelled by an electron

$$\begin{gathered} W=1.6×{10}^{-13}×2 \\ =3.2×{10}^{-13} \end{gathered}$$

From Equation (2),

$$\begin{gathered} E_{total}=2.59×{10}^{-13}+3.2×{10}^{-13} \\ =5.79×{10}^{-13J} \end{gathered}$$

From Equation (1),

$$\begin{gathered} \mathrm{γ}m{c}^2=5.79×{10}^{-13}J \\ \mathrm{γ}=\frac{5.79×{10}^{-13}}{9×{10}^{-31}×{\left(3×{10}^5\right)}^2} \\ =7.15 \end{gathered}$$

From Equation (a),

$\frac{1}{\sqrt{1-\frac{{\left(v^{\text{'}}\right)}^2}{c^2}}}=7.15$

where,$v^{\text{'}}=$ the new speed of an electron

$$\begin{gathered} \sqrt{1-\frac{(v{)}^2}{c^2}}=\frac{1}{7.15} \\ 1-\frac{(v{)}^2}{c^2}=0.020 \\ \frac{{\left(v^{\text{'}}\right)}^2}{c^2}=1-0.020 \\ \frac{{\left(v^{\text{'}}\right)}^2}{c^2}=0.98 \\ {\left(v^{\text{'}}\right)}^2=0.98{\mathrm{c}}^2 \\ {\mathrm{v}}^{\text{'}}=0.989\mathrm{c} \end{gathered}$$

Hence, the new speed of the electron is$0.989c$