91Ó°ÊÓ

The speed of the baseball is$45m/s$

The energy is produced or destroyed as per the conservation of energy principle. The principle says that the experimental observations depend on the cogency of the energy conservation.

According to the principle of energy conservation,

Loss of potential energy = Gain in kinetic energy

To find the height goes by the baseball, we have to apply Principle of energy conservation,

$h=\frac{v^2}{2g}.........\left(1\right)$

Where,

$$\begin{gathered} h=heightgoesbybaseball \\ v=speedoftheball⇒45m/s \\ g=accelerationduetogravity⇒9.81m/s \end{gathered}$$

Substitute the values in Equation,

$$\begin{gathered} h=\frac{{45}^2}{2×9.81} \\ h=103.21m \end{gathered}$$

Hence, the baseball goes103.21 mheight.

• If we throw a baseballstraight up, it will experience deacceleration due to gravity.
• When a baseball reaches maximum height, the kinetic energy will be zero.
• The potential energy will become high.
• When the gravitational force starts accelerating, the kinetic energy will become high.