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Chapter 21: Q6P (page 897)

Figure 21.61 shows disk shaped region of radius of 2 cm on which there is a uniform electric field of magnitude 300 V/m at an angle of 300 to the plane of the disk. Assume that points upward in +y direction. Calculate the electric flux on the disk, and include the correct units.

Short Answer

Expert verified

The electric flux for plane is 0.33V.m.

Step by step solution

01

Identification of given data

The radius of disk shaped region isr=2cm

The magnitude of uniform electric field is E=300V/m.

The angle of electric field with plane of disk is胃=30掳 .

02

Conceptual Explanation

The electric flux is calculated by the product of magnitude of electric field with the horizontal component of the surface area of disk.

03

Determination of electric flux of the disk

The surface area of the disk is given as:

A=蟺r2

Substitute all the values in the above equation.

A=蟺2cm1m100cm2A=1.26脳10-3m2

The electric flux for plane is given as:

蠒=EAcos胃

Substitute all the values in the above equation.

蠒=300V/m1.26脳10-3m2cos30掳蠒=0.33V路m

Therefore, the electric flux for plane is 0.33V.m.

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Most popular questions from this chapter

Figure 21.62 shows a box on who surfaces the electric field is measured to be horizontal and to the right. On the left face (3 cm by 2 cm) the magnitude of electric field is 400 V/m and on the right face the magnitude of electric field is 1000 V/m. On the other faces only the direction is known (horizontal). Calculate the electric flux on every face of the box, the total flux and total amount of charge that is inside the box.

The electric field has been measured to be horizontal and to the right everywhere on the closed box as shown in Figure 21.66. All over the left side of box E1=100V/m and all over the right (slanting) side of box E2=300V/m.On the top the average field is E3=150V/m , on the front and back the average field is E4=175V/mand on the bottom the average field is E5=220V/m.How much charge is inside the box? Explain briefly.

The center of a thin paper cube in outer space is located at the origin. Each edge is 10 cm long. The only other objects in the neighborhood are some small charged particles whose charges and position at this instant are following: +9 nC at (4,2,-3) cm, -6 nC at (1,-3,2) cm, +7 nC at (15,0,4) cm, +4 nC at (-1,3,2) cm and -3 nC at (-2,12,-3) cm. The electric flux on the five of the six faces of the cube totals 564 V m. What is the flux on the other face?

Based on its definition as electric flux per unit volume, what are the units of the divergence of electric field.

The electric field is horizontal and has the values indicated on the surface of cylinder as shown in Figure 21.65. What can you deduce from this pattern of electric field? Include a numerical result.
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