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Chapter 21: Q4Q (page 897)
Based on its definition as electric flux per unit volume, what are the units of the divergence of electric field.
The unit of divergence of electric field is .
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The electric field has been measured to be vertically upward everywhere on the surface of a box 30 cm long, 4 cm high and 3 cm deep as shown in Figure 21.64. All over the bottom of the box , all over the sides and all over the top . What can you conclude about the contents of the box. Include a numerical result.
Figure 21.70 shows a close-up of the central region of a capacitor made of two large metal plates of area , very close together and charged equally and oppositely. There are +Q and -Q on the inner surfaces of the plates and small amounts of charge +q and -q on the outer surfaces.
(a). Knowing Q, determine E: Consider a Gaussian surface in the shape of a shoe box, with one end of area Abox in the interior of the left plate and the other end in the air gap (surface 1 in the diagram). Using only the fact that the electric field is expected to be horizontal everywhere in this region, use Gauss鈥檚 law to determine the magnitude of the field in the air gap. Check that your result agrees with our earlier calculations in the Chapter 15. (Be sure to consider the flux on all faces of your Gaussian box.)
Question: A negative point charge 鈥換 is at the center of a hollow insulting spherical shell, which has an inner radius R1 and an outer radius R2. There is a total charge of +3Q spread uniformly throughout volume of insulating shell, not just on its surface. Determine the electric field for (a) r<R1 (b) R1<r<R2 (c) R2<r.
Along the path shown in Figure 21.46 the magnetic field is measured and is found to be uniform in magnitude and always tangent to the circular path. If the radius of the path is and along the path is , what are magnitude and direction of the current enclosed by the path?
The electric field has been measured to be horizontal and to the right everywhere on the closed box as shown in Figure 21.66. All over the left side of box and all over the right (slanting) side of box .On the top the average field is , on the front and back the average field is and on the bottom the average field is .How much charge is inside the box? Explain briefly.
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