/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q27P A star is located at<6×1010,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A star is located at<6×1010,8×1010,6×1010>m. A planet is located at<-4×1010,-9×1010,6×1010>m. (a) What is the vector pointing from the star to the planet? (b) What is the vector pointing from the planet to the star?

Short Answer

Expert verified

(a) The vector pointing from star to the planet isr→Ps=-10×1010,-17×1010,0m.

(b) The vector pointing from planet to the star isr→Ps=-10×1010,17×1010,0m.

Step by step solution

01

Identification of given data

Star r→s=6×1010,8×1010,6×1010m

Planet r→P=-4×1010,-9×1010,6×1010m

02

Calculating vector pointing from star to planet

(a) Here the tail of the vector will be on the star, and the head of it is on the planet, and the position vector between these two points could be found by subtracting the position of the tail from the position of the head.

r→PS=-4×1010,-9×1010,6×1010-6×1010,8×1010,6×1010r→PS=-10×1010,-17×1010,0

Thus, the required vector is r→PS=-10×1010,-17×1010,0m.

03

Calculating vector pointing from planet to star

(b) The vector pointing from the planet (position of the tail) to the star (position of the head) is the result of subtracting the position of the planet from the position of the star (or simply it is the negative of the position vector from the star to the planet).

r→PS=6×1010,8×1010,6×1010--4×1010,-9×1010,6×1010r→PS=-10×1010,-17×1010,0m=-r→SP

Therefore, the required vector is r→PS=-10×1010,-17×1010,0mm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.