/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q27P A star is located at<6脳1010,... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q27P (page 40)

A star is located at<6脳1010,8脳1010,6脳1010>m. A planet is located at<-4脳1010,-9脳1010,6脳1010>m. (a) What is the vector pointing from the star to the planet? (b) What is the vector pointing from the planet to the star?

Short Answer

Expert verified

(a) The vector pointing from star to the planet isr鈫�Ps=-10脳1010,-17脳1010,0m.

(b) The vector pointing from planet to the star isr鈫�Ps=-10脳1010,17脳1010,0m.

Step by step solution

01

Identification of given data

Star r鈫�s=6脳1010,8脳1010,6脳1010m

Planet r鈫�P=-4脳1010,-9脳1010,6脳1010m

02

Calculating vector pointing from star to planet

(a) Here the tail of the vector will be on the star, and the head of it is on the planet, and the position vector between these two points could be found by subtracting the position of the tail from the position of the head.

r鈫�PS=-4脳1010,-9脳1010,6脳1010-6脳1010,8脳1010,6脳1010r鈫�PS=-10脳1010,-17脳1010,0

Thus, the required vector is r鈫�PS=-10脳1010,-17脳1010,0m.

03

Calculating vector pointing from planet to star

(b) The vector pointing from the planet (position of the tail) to the star (position of the head) is the result of subtracting the position of the planet from the position of the star (or simply it is the negative of the position vector from the star to the planet).

r鈫�PS=6脳1010,8脳1010,6脳1010--4脳1010,-9脳1010,6脳1010r鈫�PS=-10脳1010,-17脳1010,0m=-r鈫�SP

Therefore, the required vector is r鈫�PS=-10脳1010,-17脳1010,0mm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A proton is located at <3脳10-10,-3脳10-10,8脳10-10>m.

(a)What is r鈫�, the vector from the origin to the location of the proton?

(b)What is |r鈫�|?

(c)What is r^, the unit vector in the direction of r鈫�?

(a) Which of the following do you see moving with constant velocity? (1) A ship sailing northeast at a speed of 5 meters per second (2) The Moon orbiting the Earth (3) A tennis ball traveling across the court after having been hit by a tennis racket (4) A can of soda sitting on a table (5) A person riding on a Ferris wheel that is turning at a constant rate. (b) In which of the following situations is there observational evidence for significant interaction between two objects? How can you tell? (1) A ball bounces off a wall with no change in speed. (2) A baseball that was hit by a batter flies toward the outfield. (3) A communications satellite orbits the Earth. (4) A space probe travels at constant speed toward a distant star. (5) A charged particle leaves a curving track in a particle detector.

(a) Apply Newton's first law to each of the following situations. In which situations can you conclude that the object is undergoing a net interaction with one or more other objects? (1) A book slides across the table and comes to a stop. (2) A proton in a particle accelerator moves faster and faster. (3) A car travels at constant speed around a circular race track. (4) A spacecraft travels at a constant speed toward a distant star. (5) A hydrogen atom remains at rest in outer space. (b) A spaceship far from all other objects uses its rockets to attain a speed of. The crew then shuts off the power. According to Newton's first law, which of the following statements about the motion of the spaceship after the power is shut off are correct? (Choose all statements that are correct.) (1) The spaceship will move in a straight line. (2) The spaceship will travel on a curving path. (3) The spaceship will enter a circular orbit. (4) The speed of the spaceship will not change. (5) The spaceship will gradually slow down. (6) The spaceship will stop suddenly.

(a) Apply Newton's first law to each of the following situations. In which situations can you conclude that the object is undergoing a net interaction with one or more other objects? (1) A book slides across the table and comes to a stop. (2) A proton in a particle accelerator moves faster and faster. (3) A car travels at constant speed around a circular race track. (4) A spacecraft travels at a constant speed toward a distant star. (5) A hydrogen atom remains at rest in outer space. (b) A spaceship far from all other objects uses its rockets to attain a speed of . The crew then shuts off the power. According to Newton's first law, which of the following statements about the motion of the spaceship after the power is shut off are correct? (Choose all statements that are correct.) (1) The spaceship will move in a straight line. (2) The spaceship will travel on a curving path. (3) The spaceship will enter a circular orbit. (4) The speed of the spaceship will not change. (5) The spaceship will gradually slow down. (6) The spaceship will stop suddenly.

A planet is located at <-1脳1010,8脳1010,-3脳1010>. A star is located at <6脳1010,-5脳1010,1脳1010>.

(a)What is r鈫�, the vector from the star to the planet?

(b)What is the magnitude of r鈫�?

(c)What is r^, the unit vector (vector with magnitude 1) in the direction of r鈫�?
See all solutions

Recommended explanations on Physics Textbooks

Kinematics Physics

Read Explanation

Linear Momentum

Read Explanation

Famous Physicists

Read Explanation

Rotational Dynamics

Read Explanation

Space Physics

Read Explanation

Fluids

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.