91Ó°ÊÓ

The given data can be listed below as,

• The initial location of butterfly is, .
• Time at which the butterfly was at initial location is, 6 s.
• The final location of the butterfly is, .
• Time by which the butterfly reached to the final location is, 10 s.

This law states that a body will continue to proceed at a uniform velocity if no external force acts on that body.

The equation of the average velocity and the displacement gives the location of the butterfly.

The equation of the average velocity of the butterfly can be expressed as follows,

${\mathrm{v}}_{\mathrm{avg}}=\frac{{\mathrm{r}}_2-{\mathrm{r}}_1}{{\mathrm{t}}_2-{\mathrm{t}}_1}$

Here, v_avg is the average velocity, r₁ is the initial location of butterfly, r₂ is the final location of the butterfly, t₁ is the time taken by the butterfly to reach to the initial location and t₂ is the time taken by butterfly to reach at the final location.

For data-custom-editor="chemistry" , data-custom-editor="chemistry" , data-custom-editor="chemistry" ${\mathrm{t}}_1=6\mathrm{s}$and data-custom-editor="chemistry" ${\mathrm{t}}_2=10\mathrm{s}$.

data-custom-editor="chemistry"

The equation of displacement of the butterfly is expressed as follows,

$\mathrm{s}={\mathrm{s}}_0+{\mathrm{v}}_{\mathrm{avg}}\mathrm{t}$

Here, s is the displacement of the butterfly, s₀ is the initial displacement of the butterfly, v_avg is the average velocity of the butterfly, and t is the time taken by the butterfly to reach the final location.

For , and $\mathrm{t}=10\mathrm{s}-8.5\mathrm{s}=1.5\mathrm{s}$.

Thus, the location of the butterfly at a time 8.5 s is .

The assumption made in this question is that the average velocity is constant as the velocity may have changed with time. But here it is taken as constant.

Thus, the assumption made in this question is that the average velocity is constant.