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A proton is located at <3×10-10,-3×10-10,8×10-10>m.

(a)What is r→, the vector from the origin to the location of the proton?

(b)What is |r→|?

(c)What is r^, the unit vector in the direction of r→?

Short Answer

Expert verified

(a) The vector from the origin to the location of the proton is r→=(3×10-10i^-3×10-10j^+8×10-10k^)m.

(b) The magnitude ofr→is|r→|=9.6×10-10m.

(c) The unit vector along r→is r^=0.33i^-0.33j^+0.883k^ .

Step by step solution

01

Given data

Location of the proton isr=<3×10-10,-3×10-10,8×10-10>m

02

Position vector, magnitude of a vector and unit vector

The position vector of a location x,y,zwith respect to origin 0,0,0is

r→=xi^+yj^+zk^......l

The magnitude of a vector r→=xi^+yj^+zk^ is

|r→|=x2+y2+z2.....ll

The unit vector along a vector r→ is

r^=r→|r→|......III

03

Determining the position vector of the proton

From equation (I), the position vector of the proton is

r→=(3×10-10i^-3×10-10j^+8×10-10k^)m

04

Determining the magnitude of the position vector of the proton

From equation (II), the magnitude of r→is

r→=3×10-102+-3×10-102+8×10-102m=32+32+82×10-10m=9.06×10-10m

Thus, the required magnitude is9.06×10-10m

05

Determining the unit vector along the position vector of the proton

From equation (III), the unit vector along r→ is

r→=(3×10-10i^-3×10-10j^+8×10-10k^)m9.06×10-10m=0.33i^-0.33j^+0.883k^

Thus, the required unit vector is0.33i^-0.33j^+0.883k^

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