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A proton is located at <310-10,-310-10,810-10>m.

(a)What is r, the vector from the origin to the location of the proton?

(b)What is |r|?

(c)What is r^, the unit vector in the direction of r?

Short Answer

Expert verified

(a) The vector from the origin to the location of the proton is r=(310-10i^-310-10j^+810-10k^)m.

(b) The magnitude ofris|r|=9.610-10m.

(c) The unit vector along ris r^=0.33i^-0.33j^+0.883k^ .

Step by step solution

01

Given data

Location of the proton isr=<310-10,-310-10,810-10>m

02

Position vector, magnitude of a vector and unit vector

The position vector of a location x,y,zwith respect to origin 0,0,0is

r=xi^+yj^+zk^......l

The magnitude of a vector r=xi^+yj^+zk^ is

|r|=x2+y2+z2.....ll

The unit vector along a vector r is

r^=r|r|......III

03

Determining the position vector of the proton

From equation (I), the position vector of the proton is

r=(310-10i^-310-10j^+810-10k^)m

04

Determining the magnitude of the position vector of the proton

From equation (II), the magnitude of ris

r=310-102+-310-102+810-102m=32+32+8210-10m=9.0610-10m

Thus, the required magnitude is9.0610-10m

05

Determining the unit vector along the position vector of the proton

From equation (III), the unit vector along r is

r=(310-10i^-310-10j^+810-10k^)m9.0610-10m=0.33i^-0.33j^+0.883k^

Thus, the required unit vector is0.33i^-0.33j^+0.883k^

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