91影视

The given data can be listed below as,

In this question, the kinetic energy of the charged particle (electron and proton) can be obtained with the help of the electric charge of the particle and potential difference. The relation between the respective kinetic energy and potential difference is direct linear.

The relation ofkinetic energy of electronis expressed as,

${\left(\mathrm{KE}\right)}_{\mathrm{e}}={\mathrm{q}}_{\mathrm{e}}\mathrm{V}$

Here, ${\left(\mathrm{KE}\right)}_{\mathrm{e}}$is the kinetic energy of the electron, ${\mathrm{q}}_{\mathrm{e}}$ represents the magnitude of the charge on an electron whose value is $1.6脳{10}^{鈭�19}\text{鈥塁}$.

Substitute all the known values in the above equation.

$\begin{array}{c}{\left(\mathrm{KE}\right)}_{\mathrm{e}}=(1.6脳{10}^{鈭�19}\text{鈥塁})\left(35\text{鈥塚}\right)\\ =(5.6脳{10}^{鈭�18}\text{鈥塁}鈰�\text{V})\left(\frac{1\text{鈥塭痴}}{1\text{鈥塁}鈰�\text{V}}\right)\\ =5.6脳{10}^{鈭�18}\text{鈥塭痴}\end{array}$

Thus, the kinetic energy of the electron is $5.6脳{10}^{鈭�18}\text{鈥塭痴}$.

The relation ofkinetic energy of protonis expressed as,

${\left(\mathrm{KE}\right)}_{\mathrm{p}}={\mathrm{q}}_{\mathrm{p}}\mathrm{V}$

Here,${\left(\mathrm{KE}\right)}_{\mathrm{p}}$ is the kinetic energy of the proton, ${\mathrm{q}}_{\mathrm{p}}$ represents the magnitude of the charge on a proton whose value is $1.6脳{10}^{鈭�19}\text{鈥塁}$.

Substitute all the known values in the above equation.

$\begin{array}{c}{\left(\mathrm{KE}\right)}_{\mathrm{p}}=(1.6脳{10}^{鈭�19}\text{鈥塁})\left(35\text{鈥塚}\right)\\ =(5.6脳{10}^{鈭�18}\text{鈥塁}鈰�\text{V})\left(\frac{1\text{鈥塭痴}}{1\text{鈥塁}鈰�\text{V}}\right)\\ =5.6脳{10}^{鈭�18}\text{鈥塭痴}\end{array}$

Thus, the kinetic energy of the proton is $5.6脳{10}^{鈭�18}\text{鈥塭痴}$.