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Chapter 16: Q10Q (page 662)

Figure 16.59 shows several locations inside a capacitor. You need to calculate the potential differenceVD-VC

(a) What is the direction of the path (+x or 鈭抶)? (b)If the charge on the right plate is negative and the charge on the left plate is positive, what is the sign of VD-VC?

Short Answer

Expert verified

a)The direction of the path is +x-direction.

b) The sign of the potential difference is negative.

Step by step solution

01

Identification of given data

The given data can be listed below,

  • The charge on the right plate is, -q
  • The charge on the left plate is, -q
02

Concept/Significance of electric potential.

The potential at a position is the amount that, when multiplied by the charge of another particle, yields the potential energy of that particle at that location.

03

(a) Determination of the direction of the path

The potential differenceVD-VC is calculated by travelling from point C to D so the direction of path is from -x-direction to +x-direction.

Thus, the direction of the path is +x-direction.

04

(b) Determination of the sign of VD-VC.

The point C have more potential because of the positive charge on the left plate and the potential on the point D is less because of the negative charge carrying plate. So, the potential difference is negative which is given by,

鈭�V=VD-VC

Thus, the sign of the potential difference is negative

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Most popular questions from this chapter

The graph in Fig.16.56 shows the electric potential energy for a system of two interacting objects, as a function of the distance between the objects. What system might this graph represent?

(1) Two Protons, (2) Two sodium ions, (3) Two neutrons, (4) Two chloride ions, (5) Two electrons, (6) A Proton and an Electron, (7) A sodium ion and a chloride ion.

long thin metal wire with radius rand lengthLis surrounded by a concentric long narrow metal tube of radius R, whereR>>L, as shown in Figure 16.86. Insulating spokes hold the wire in the center of the tube and prevent electrical contact between the wire and the tube. A variable power supply is connected to the device as shown. There is a charge+Qon the inner wire and a charge鈭�Qon the outer tube. As we will see when we study Gauss鈥檚 law in a later chapter, the electric field inside the tube is contributed solely by the wire, and the field outside the wire is the same as though the wire were infinitely thin; the outer tube does not contribute as long as we are not near the ends of the tube. (a) In terms of the chargeQ, lengthL, inner radiusr, and outer radiusR , what is the potential differenceVtube鈭�Vwire between the inner wire and the outer tube? Explain, and include checks on your answer. (b) The power-supply voltage is slowly increased until you see a glow in the air very near the inner wire. Calculate this power-supply voltage (give a numerical value), and explain your calculation. The lengthL=80鈥塩尘 , the inner radiusr=0.7鈥尘尘, and the outer radiusR=3鈥塩尘. This device is called a 鈥淕eiger鈥揗眉ller tube鈥� and was one of the first electronic particle detectors. The voltage is set just below the threshold for making the air glow near the wire. A charged particle that passes near the center wire can trigger breakdown in the air, leading to a large current that can be easily measured.

A rod uniformly charged with charge \( - q\) is bent into a semicircular arc of radius\(b\), as shown in Figure 16.97. What is the potential relative to infinity at location\(A\), at the center of the arc?

You travel along a path from location A to location B, moving in a direction perpendicular to the direction of the net electric field in that region.

What is true of the potential difference VB-VA?

(1)VB-VA>0,(2)VB-VA<0(3)VB-VA=0

Suppose that the potential difference in going from location (2.00,3.50,4.00)m to locationrole="math" localid="1657094482453" (2.00,3.52,4.00)m is3V. What is the approximate value ofEyin this region? Include the appropriate sign.
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